T Madas T Madas Calculate the missing angles
- Slides: 114
© T Madas
© T Madas
Calculate the missing angles in each triangle 70° 50° 65° 55° © T Madas
© T Madas
One of the angles of an isosceles triangle is 64°. What are the sizes of the other two angles? [You must show that there are 2 different possibilities] 1 st possibility 2 nd possibility 52° 64 + 64 128 64° 180 – 128 52 58° 180 – 64 116 58° 116 ÷ 2 = 58° © T Madas
© T Madas
Calculate the angle marked as x. 49° 41° 49° x © T Madas
© T Madas
Calculate the angle marked as x. 61° 21° 69° 29° 50° x © T Madas
© T Madas
Calculate the angle marked as x 50° 130° 20° 70° ° 0 x 3 © T Madas
© T Madas
Calculate three angles of the triangle 70 ° 140° 40 ° 70 ° Calculate the angle marked with x 55 ° 110° x 70 ° 55 ° © T Madas
© T Madas
Calculate the angle marked with x 292° x 68 ° 136° 44 ° 68 ° © T Madas
© T Madas
In the following diagram RBAC = 28° and AC = BD Calculate the angle marked as x x 84° B 56° 68° D 28° C 28° 124 ° 56° A © T Madas
© T Madas
One of the angles of a rhombus is 47°. Calculate the angle marked as x. 47 + 47 94 47° x 133° 360 – 94 266 ÷ 2 = 133° • Opposite angles in a parallelogram are equal • A rhombus is a special parallelogram • Angles in any quadrilateral add up to 360° © T Madas
© T Madas
In the following diagram Calculate: 1. REFD 2. RDCF 3. RBEF RBAC = 90°, RADF = 71° and RBFE = 36° B REFD = 144° RDCF =35° E 36 ° F 14 4° 71° A 36 ° 109° D 35° C © T Madas
In the following diagram Calculate: 1. REFD 2. RDCF 3. RBEF RBAC = 90°, RADF = 71° and RBFE = 36° B 19° REFD = 144° E RDCF =35° 36 RBEF = ° F 14 4° 71° A 36 ° 109° D 35° C © T Madas
In the following diagram Calculate: 1. REFD 2. RDCF 3. RBEF RBAC = 90°, RADF = 71° and RBFE = 36° B 19° REFD = 144° RDCF =35° 12 E 5° 36 RBEF = 125° ° F 14 4° 71° A 36 ° 109° D 35° C © T Madas
© T Madas
The following shape has rotational symmetry of order 8. One angle is marked on the diagram. 1. Calculate the size of angle x 2. Calculate the size of angle y 360° ÷ 8 = 45° 360° 45° x y 21° © T Madas
The following shape has rotational symmetry of order 8. One angle is marked on the diagram. 1. Calculate the size of angle x 2. Calculate the size of angle y 360° ÷ 8 = 45° 21° + 45° = 66° 45° 114° y ° 1 2 180° – 66° = 114° 21° © T Madas
© T Madas
A farm gate consists of three parallel planks of wood with a metal bar running diagonally for extra support, as shown in the diagram. Calculate the angles x, y and z. y x z x = 30° x and the 30° angle are ALTERNATE ANGLES © T Madas
A farm gate consists of three parallel planks of wood with a metal bar running diagonally for extra support, as shown in the diagram. Calculate the angles x, y and z. y x z x = 30° y and the 30° angle are CORRESPONDING ANGLES © T Madas
A farm gate consists of three parallel planks of wood with a metal bar running diagonally for extra support, as shown in the diagram. Calculate the angles x, y and z. ALTERNATE ANGLES 30° y x 30° z x = 30° y = 30° z = 150° © T Madas
© T Madas
ABCD is a trapezium RADB = 90° RDBE = 25° and RCEB = 55° 1. Calculate RABD 2. Calculate RDAB 3. Calculate RBDC D E C 55 ° 25 ° A B © T Madas
ABCD is a trapezium RADB = 90° RDBE = 25° and RCEB = 55° 1. Calculate RABD 30° 2. Calculate RDAB 60° 3. Calculate RBDC D E C 55 ° Alternate Angles 25 ° 60° 30° A B Angles of a triangle © T Madas
ABCD is a trapezium RADB = 90° RDBE = 25° and RCBE = 55° 1. Calculate RABD 30° 2. Calculate RDAB 60° 3. Calculate RBDC 30° E D 30° C 55 ° Alternate Angles 25 ° 60° A 30° B © T Madas
© T Madas
A parallelogram ABCD, its diagonals and some of its angles are shown in the diagram below. 1. Calculate the four angles of the parallelogram. 2. Using the properties of parallelograms (including special parallelograms), explain why this drawing is impossible. B 55° A 20° C ° 50 D RCAD = RBCA: alternating angles © T Madas
A parallelogram ABCD, its diagonals and some of its angles are shown in the diagram below. 1. Calculate the four angles of the parallelogram. 2. Using the properties of parallelograms (including special parallelograms), explain why this drawing is impossible. B 55° 50 A 20° ° 20° D C ° 50 we could use: opposite angles in any parallelogram are equal or RCAD = RBCA: alternating angles RACD = RBAC: alternating angles © T Madas
A parallelogram ABCD, its diagonals and some of its angles are shown in the diagram below. 1. Calculate the four angles of the parallelogram. 2. Using the properties of parallelograms (including special parallelograms), explain why this drawing is impossible. B 20° 55° 50 A ° 110° 20° 70 + 70 140 D 360 – 140 220 C ° 50 we could use: opposite angles in any parallelogram are equal or 220 ÷ 2 = 110° © T Madas
A parallelogram ABCD, its diagonals and some of its angles are shown in the diagram below. 1. Calculate the four angles of the parallelogram. 2. Using the properties of parallelograms (including special parallelograms), explain why this drawing is impossible. B 55° 50 A 55° ° 20° 110° D C ° 50 there is no parallelogram with only one diagonal bisecting its angles In any parallelogram both diagonals bisect their angles: rhombus, square both diagonals do not bisect their angles: rectangle , ordinary parallelogram only one diagonal bisect its angles: NONE Can you think of a quadrilateral where only one diagonal bisect its angles? © T Madas
© T Madas
Work the missing angle if and is a rectangle is equilateral E A x 50° D 40° 20° G F 120° 60° B C © T Madas
© T Madas
If is equilateral, is a rectangle and F, A and C lie on a straight line show that is isosceles F A E 30° 60° D 30° 120° 60° B C © T Madas
© T Madas
Find the value of the angle marked in purple 55° 75° 125° 75° 105° 50° © T Madas
© T Madas
Find the value of x and hence calculate these two angles 2 x 3 x 3 x + 2 x = 90° 5 x = 90° c c 2 x x = 18° © T Madas
Find the value of x and hence calculate these two angles 36° 3 x + 2 x = 90° 5 x = 90° c c 54° x = 18° © T Madas
© T Madas
Find the value of angle x ONLY 2 a b b x 90° 2 a + 2 b = 180° a + c a a b = 90° © T Madas
© T Madas
Find the value of the angle marked in purple 52° 100° 48° © T Madas
© T Madas
Find the value of the angle marked in purple 27° 275° 58° © T Madas
© T Madas
Find the value of x and hence calculate these two angles 3 x 108° 2 x 72° Alternate Angles Straight Line 3 x + 2 x = 180° 5 x = 180° c c 2 x x = 36° © T Madas
© T Madas
Two equilateral triangles overlap each other, forming angles of 50° and 80° with the straight line AB as shown in the diagram. What is the angle marked as x ? solution x 50° 60° 70° A 80° 70° 60° 50° 40° 70° B © T Madas
© T Madas
Four lines cross each other as shown in the diagram below. Four triangles are created by connecting the endpoints of these lines. What is the sum of the 8 angles shown in yellow? … the angles in a triangle add up to 180° … solution … the 12 angles of the 4 triangles must add up to … … 4 x 180° = 720° … … the green angles are vertically opposite to the 4 red angles of the quadrilateral … … the angles of a quadrilateral add up to 360° … … the yellow angles add up to… … 720° – 360° = … 360° © T Madas
© T Madas
The figure below shows a pentagon ABCDE. REAB = RABC = 105° and RBCD = RDEA = 100°. Calculate the angle REDC. D x E … split the pentagon into 3 triangles … C 100° … the angles of a triangle add up to 180°… … the angles of the pentagon must add up to… 105° A … 180° x 3 = 540°… 105° B … the four given angles add up to 410°… … REDC = 130° © T Madas
© T Madas
A regular heptagon (7 sided polygon) ABCDEFG is drawn below. Calculate the size of RAOC, giving your answer to 3 significant figures. A 360° ÷ 7 ≈ 51. 4286° B G 51. 4286° x 2 ≈ 103° [3 s. f. ] O F C E D © T Madas
© T Madas
A regular hexagon is shown below. Calculate the angles marked as x, y and z. 360° ÷ 6 = 60° 12 0° 30 z° 60° y 120° x 60° © T Madas
© T Madas
Three regular pentagons are placed in the way shown below so that they all share one vertex. Calculate the angle marked as x 54 ° 72 ° 54108° ° 108° x 36° © T Madas
© T Madas
A regular polygon has exterior angle of 40°. How many sides does it have? exterior angle = 360° n This is an easy problem… … but you are under exam pressure and you forgot this formula…. … in fact good mathematicians do not memorise this formula… … go back to basics © T Madas
A regular polygon has exterior angle of 40°. How many sides does it have? 40° 70° 360 ÷ 40 = 9 sides 40° © T Madas
© T Madas
Part of a regular polygon is shown below. Its exterior angle is 20° How many sides does it have? Calculate the angle marked as y. The exterior angle of an n-sided regular polygon is given by: 360° 20 ° n 20 ° 360 ÷ 20 = 18 sides y ° 20 20° The exterior angle of an n-sided regular polygon is equal to its central angle. y = 80° © T Madas
© T Madas
A tessellation of squares and regular octagons is shown opposite. Calculate the angle marked as x. x x angles around a point add up to … … 360° subtracting the right angle gives … … 270° dividing by 2 gives … 135° x = 135° © T Madas
© T Madas
Regular dodecagons tessellate with equilateral triangles as shown opposite. Use this fact to calculate the interior angle of a regular dodecagon. angles around a point add up to … … 360° subtracting the 60° angle gives … … 300° 60° x x dividing by 2 gives … 150° The interior angle of a regular dodecagon is 150° © T Madas
© T Madas
A regular enneagon, (9 -sided polygon), is drawn below. Calculate the angles marked as x and y. 360° ÷ 9 = 40° x 70° 40° 70° y 180° – 40° = 140° ÷ 2 = 70° x = 140° y = 40° © T Madas
© T Madas
Calculate the exterior angle of a regular pentagon 360° ÷ 5 = 72° 180° – 72° = 108° ÷ 2 = 54° 72° 54° 54° 72° © T Madas
© T Madas
The diagram below shows part of a tessellation consisting of a regular octagon and a square. Show by a calculation that a regular hexagon cannot be used to fit the space between the square and the octagon. What regular polygon can fit instead? 360° ÷ 8 = 45° 180° – 45° = 135° 5° 13 135° ÷ 2 = 67. 5° 45° 5°. 7 6 © T Madas
The diagram below shows part of a tessellation consisting of a regular octagon and a square. Show by a calculation that a regular hexagon cannot be used to fit the space between the square and the octagon. What regular polygon can fit instead? 360° ÷ 6 = 60° 180° – 60° = 120° 5° 13 135° 120° ÷ 2 = 60° 120° 60° 135° + 90° = 225° 360° – 225° = 135° 45° 5°. 7 6 The angle between the square and the octagon is 135° while the interior angle of a regular hexagon is 120°. Therefore a regular hexagon will not fit. © T Madas
The diagram below shows part of a tessellation consisting of a regular octagon and a square. Show by a calculation that a regular hexagon cannot be used to fit the space between the square and the octagon. What regular polygon can fit instead? 360° ÷ 6 = 60° 180° – 60° = 120° ÷ 2 = 60° 120° 5° 13 60° 135° + 90° = 225° 360° – 225° = 135° 45° 5°. 7 6 The angle between the square and the octagon is 135° while the interior angle of a regular hexagon is 120°. Therefore a regular hexagon will not fit. © T Madas
The diagram below shows part of a tessellation consisting of a regular octagon and a square. Show by a calculation that a regular hexagon cannot be used to fit the space between the square and the octagon. What regular polygon can fit instead? 360° ÷ 6 = 60° 180° – 60° = 120° ÷ 2 = 60° 120° 5° 13 60 ° 135° + 90° = 225° 360° – 225° = 135° 45° 5°. 7 6 The angle between the square and the octagon is 135° while the interior angle of a regular hexagon is 120°. Therefore a regular hexagon will not fit. © T Madas
5° 13 135° The diagram below shows part of a tessellation consisting of a regular octagon and a square. Show by a calculation that a regular hexagon cannot be used to fit the space between the square and the octagon. What regular polygon can fit instead? 45° 5°. 7 6 © T Madas
5° 13 135° The diagram below shows part of a tessellation consisting of a regular octagon and a square. Show by a calculation that a regular hexagon cannot be used to fit the space between the square and the octagon. What regular polygon can fit instead? 45° 5°. 7 6 Another a regular octagon can fit. © T Madas
© T Madas
The sides of a regular pentagon are extended until they form the star shape shown below. Calculate the size of the angles marked as α and β. φ φ c c c α The central angle of a regular pentagon is given by: θ β 360° ÷ 5 = 72° θ = 72° φ = 54° β = 108° © T Madas
The sides of a regular pentagon are extended until they form the star shape shown below. Calculate the size of the angles marked as α and β. θ φ φ β θ c c α The central angle of a regular pentagon is given by: 360° ÷ 5 = 72° θ = 72° φ = 54° β = 108° α = 36° © T Madas
© T Madas
The shape below has rotational symmetry of order 5 and each of the five quadrilateral “arrowheads” consists of two congruent isosceles triangles. Calculate the angles marked as x and y. … rotational symmetry of order 5 … 22 x ° 72° … each “arrowhead has been rotated about the centre of the shape though an angle of … y … 360° ÷ 5 = 72° … © T Madas
The shape below has rotational symmetry of order 5 and each of the five quadrilateral “arrowheads” consists of two congruent isosceles triangles. Calculate the angles marked as x and y. … rotational symmetry of order 5 … ° 22 25° x x 72° … each “arrowhead has been rotated about the centre of the shape though an angle of … y … 360° ÷ 5 = 72° … … 72° – 22 ° = 50° … … 50° ÷ 2 = 25° … … x = 25° … © T Madas
The shape below has rotational symmetry of order 5 and each of the five quadrilateral “arrowheads” consists of two congruent isosceles triangles. Calculate the angles marked as x and y. … 130° x 2 = 260° … ° 22 0° 3 1 25° 13 0° ° 25 y =100° … 360° – 260° = 100° … … y = 100° … © T Madas
The shape below has rotational symmetry of order 5 and each of the five quadrilateral “arrowheads” consists of two congruent isosceles triangles. Calculate the angles marked as x and y. … or we could use a circle theorem… ° 22 25° y =100° © T Madas
© T Madas
Calculate the area of a regular hexagon of side 8 cm, giving your answer to 3 significant figures. E D 4 30° h O F A 8 cm h h tan 30° = 4 4 h= tan 30° C 30° 4 cm 6. 928 60° = tan 30° h ≈ 6. 928 cm B © T Madas
Calculate the area of a regular hexagon of side 8 cm, giving your answer to 3 significant figures. E D O F C 6. 928 30° A 8 cm B © T Madas
There is a better method for this problem © T Madas
Calculate the area of a regular hexagon of side 8 cm, giving your answer to 3 significant figures. E F 8 60° C cm A 60° 8 cm 60° AT = 32 sin 60° AH = 192 sin 60° AH = 166 cm 2 [ 3 s. f. ] x 8 x sin 60° c = c O AT c D B © T Madas
© T Madas
A regular enneagon (9 -sided polygon) ABCDEFGHI is shown below. Calculate RICE. I A ● for the circle circumscribing H ● ● ● B G O C ● the enneagon: RIOE is a central angle RICE is an inscribed angle both angles correspond to the same arc. hence RICE is half of RIOE ● The central angle of a regular F D E enneagon is given by: 360° ÷ 9 = 40° ● RIOE = 160° ● hence RICE = 80° © T Madas
© T Madas
18 identical slabs in the shape of isosceles trapeziums fit tightly around a small fish pond as shown below. What is the smallest and what is the largest angle of these trapezoidal slabs? 360° ÷ 18 = 20° © T Madas
18 identical slabs in the shape of isosceles trapeziums fit tightly around a small fish pond as shown below. What is the smallest and what is the largest angle of these trapezoidal slabs? 360° ÷ 18 = 20° © T Madas
18 identical slabs in the shape of isosceles trapeziums fit tightly around a small fish pond as shown below. What is the smallest and what is the largest angle of these trapezoidal slabs? 360° ÷ 18 = 20° © T Madas
18 identical slabs in the shape of isosceles trapeziums fit tightly around a small fish pond as shown below. What is the smallest and what is the largest angle of these trapezoidal slabs? 80° 20° 80° 100° 80° 360° ÷ 18 = 20° © T Madas
© T Madas
A regular hexagon and a regular pentagon are made to overlap each other as shown in the diagram below. What is the size of the angle marked as x ? x © T Madas
A regular hexagon and a regular pentagon are made to overlap each other as shown in the diagram below. What is the size of the angle marked as x ? x How many degrees interior angle of a hexagon? is the regular … six equilateral triangles 120° 60° © T Madas
A regular hexagon and a regular pentagon are made to overlap each other as shown in the diagram below. What is the size of the angle marked as x ? © T Madas
A regular hexagon and a regular pentagon are made to overlap each other as shown in the diagram below. What is the size of the angle marked as x ? How many degrees interior angle of a pentagon? 72° 108° 54° is the regular … five isosceles triangles … 360° ÷ 5 = … … 72° … … 180° – 72° = … … 108° ÷ 2 = … … 54° … © T Madas
A regular hexagon and a regular pentagon are made to overlap each other as shown in the diagram below. What is the size of the angle marked as x ? x … split the overlapping pentagon into 3 triangles … … the angles of a triangle add up to 180°… 120° 108° … the angles of the pentagon must add up to… … 180° x 3 = 540°… … the four angles of the pentagon add up to 456°… … x = 84° © T Madas
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