T Madas Two triangles are congruent if All

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© T Madas

© T Madas

Two triangles are congruent if… All 3 sides are equal SSS 2 sides and

Two triangles are congruent if… All 3 sides are equal SSS 2 sides and the contained angle are equal SAS 1 side and the 2 adjacent angles are equal ASA © T Madas

© T Madas

© T Madas

Prove that the any point that lies on the perpendicular bisector of a line

Prove that the any point that lies on the perpendicular bisector of a line segment is equidistant from the endpoints of the segment C Let AB be a line segment and M its midpoint Let C be a point on the perpendicular bisector Two right angled triangles are formed AM = MB A M B MC is common RAMC = RCMB = 90° The two triangles have two sides and the contained angle of those sides, correspondingly equal (SAS) Therefore the triangles are congruent AC = CB © T Madas

© T Madas

© T Madas

Given that a parallelogram has four equal sides, prove that its diagonals are perpendicular

Given that a parallelogram has four equal sides, prove that its diagonals are perpendicular to each other. A parallelogram with 4 equal sides is in general a rhombus C D A RBDC = RABD as alternate angles B © T Madas

Given that a parallelogram has four equal sides, prove that its diagonals are perpendicular

Given that a parallelogram has four equal sides, prove that its diagonals are perpendicular to each other. A parallelogram with 4 equal sides is in general a rhombus C D RBDC = RABD as alternate angles RDCA = RCAB as alternate angles A B © T Madas

Given that a parallelogram has four equal sides, prove that its diagonals are perpendicular

Given that a parallelogram has four equal sides, prove that its diagonals are perpendicular to each other. A parallelogram with 4 equal sides is in general a rhombus C D RBDC = RABD as alternate angles RDCA = RCAB as alternate angles 0 r. DCA = r. CAB A S A hence all their sides are equal A B but all four sides of a rhombus are equal thus all four triangles are congruent S So RAOD = RDOC = RCOB = RAOB Since all four add up to 360°, each must be 90° © T Madas

© T Madas

© T Madas

In the diagram below ABCD and DEFG are squares. Prove that the triangles ADE

In the diagram below ABCD and DEFG are squares. Prove that the triangles ADE and CDG are congruent. F E G A B D C © T Madas

In the diagram below ABCD and DEFG are squares. Prove that the triangles ADE

In the diagram below ABCD and DEFG are squares. Prove that the triangles ADE and CDG are congruent. F E G A D = B + C © T Madas

In the diagram below ABCD and DEFG are squares. Prove that the triangles ADE

In the diagram below ABCD and DEFG are squares. Prove that the triangles ADE and CDG are congruent. F E G A B D = + C © T Madas

In the diagram below ABCD and DEFG are squares. Prove that the triangles ADE

In the diagram below ABCD and DEFG are squares. Prove that the triangles ADE and CDG are congruent. F E SAS G A D ADE and CDG are congruent because 2 sides and the contained angle of ADE are equal to 2 sides and the contained angle of ADE. B C © T Madas

© T Madas

© T Madas

In a circle, centre O, two chords AB and CD are marked, so that

In a circle, centre O, two chords AB and CD are marked, so that AB = CD Prove that the chords are equidistant from the centre O B Need to prove OM = ON If we prove that AOB and COD are congruent then their corresponding heights OM and ON will be equal M O A C N D AB = CD (given) AO = CO (circle radii) BO = DO (circle radii) Triangle congruency SSS OM = ON © T Madas

© T Madas

© T Madas

In the diagram below ABD and BCE are equilateral triangles. Prove that the triangles

In the diagram below ABD and BCE are equilateral triangles. Prove that the triangles ABE and DBC are congruent. D A 60° θ B 60° AB = DB BC = BE RDBC = RABE [ABD is equilateral] [CBE is equilateral] [both angles are 60° + θ ] VABE and VDBC are congruent because 2 sides and the contained angle of VABE are equal to 2 sides and the contained angle of VDBC. SAS C E © T Madas

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© T Madas