Thermodynamics Intensive and extensive properties Intensive properties System

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Thermodynamics

Thermodynamics

Intensive and extensive properties • Intensive properties: – System properties whose magnitudes are independent

Intensive and extensive properties • Intensive properties: – System properties whose magnitudes are independent of the total amount, instead, they are dependent on the concentration of substances • Extensive properties – Properties whose value depends on the amount of substance present

State and Nonstate Functions • Euler’s Criterion • State functions – Pressure – Internal

State and Nonstate Functions • Euler’s Criterion • State functions – Pressure – Internal energy • Nonstate functions – Work – Heat

Energy • Capacity to do work • Internal energy is the sum of the

Energy • Capacity to do work • Internal energy is the sum of the total various kinetic and potential energy distributions in a system.

Heat • The energy transferred between one object and another due to a difference

Heat • The energy transferred between one object and another due to a difference in temperature. • In a molecular viewpoint, heating is: – The transfer of energy that makes use of disorderly molecular motion • Thermal motion – The disorderly motion of molecules

Exothermic and endothermic • Exothermic process – A process that releases heat into its

Exothermic and endothermic • Exothermic process – A process that releases heat into its surroundings • Endothermic process – A process wherein energy is acquired from its surroundings as heat.

Work • Motion against an opposing force. • The product of an intensity factor

Work • Motion against an opposing force. • The product of an intensity factor (pressure, force, etc) and a capacity factor (distance, electrical charge, etc) • In a molecular viewpoint, work is: – The transfer of energy that makes use of organized motion

Free expansion ΔU Isothermal Isochoric 0 Isobaric q+w q wrev wirrev 0 0 -pextΔV

Free expansion ΔU Isothermal Isochoric 0 Isobaric q+w q wrev wirrev 0 0 -pextΔV Adiabatic

Adiabatic Changes • q=0! • Therefore ΔU = w • In adiabatic changes, we

Adiabatic Changes • q=0! • Therefore ΔU = w • In adiabatic changes, we can expect the temperature to change. • Adiabatic changes can be expressed in terms of two steps: the change in volume at constant temperature, followed by a change in temperature at constant volume.

Adiabatic changes • The overall change in internal energy of the gas only depends

Adiabatic changes • The overall change in internal energy of the gas only depends on the second step since internal energy is dependent on the temperature. • ΔUad = wad = n. CvΔT for irreversible conditions

Adiabatic changes • How to relate P, V, and T? during adiabatic changes? Use

Adiabatic changes • How to relate P, V, and T? during adiabatic changes? Use the following equations! • Vi. Tic = Vf. Tfc – Where c = Cv/R • Pi. Viγ = Pf. Vfγ – Where γ = Cp/Cv

Adiabatic changes •

Adiabatic changes •

Free Isothermal expansion ΔU 0 q wrev 0 wirrev 0 Isochoric Isobaric Adiabatic n.

Free Isothermal expansion ΔU 0 q wrev 0 wirrev 0 Isochoric Isobaric Adiabatic n. CvΔT q+w w n. CvΔT n. CpΔT or – wirrev 0 -pextΔV =-n. CvΔT =-pextΔV 0

1. 2. Exercise 10 g of N 2 is obtained at 17°C under 2

1. 2. Exercise 10 g of N 2 is obtained at 17°C under 2 atm. Calculate ΔU, q, and w for the following processes of this gas, assuming it behaves ideally: (5 pts each) a) Reversible expansion to 10 L under 2 atm b) Adiabatic free expansion c) Isothermal, reversible, compression to 2 L d) Isobaric, isothermal, irreversible expansion to 0. 015 m 3 under 2 atm e) Isothermal free expansion (Homework) 2 moles of a certain ideal gas is allowed to expand adiabatically and reversibly to 5 atm pressure from an initial state of 20°C and 15 atm. What will be the final temperature and volume of the gas? What is the change in internal energy during this process? Assume a Cp of 8. 58 cal/mole K (10 pts) 1 cal = 4. 184 J

Enthalpy • As can be seen in the previous derivation, at constant pressure: •

Enthalpy • As can be seen in the previous derivation, at constant pressure: • ΔH = n. CpΔT

Relating ΔH and ΔU in a reaction that produces or consumes gas • ΔH

Relating ΔH and ΔU in a reaction that produces or consumes gas • ΔH = ΔU + pΔV, • When a reaction produces or consumes gas, the change in volume is essentially the volume of gas produced or consumed. • pΔV = Δng. RT, assuming constant temperature during the reaction • Therefore: › ΔH = ΔU + Δng. RT

Dependence of Enthalpy on Temperature • The variation of the enthalpy of a substance

Dependence of Enthalpy on Temperature • The variation of the enthalpy of a substance with temperature can sometimes be ignored under certain conditions or assumptions, such as when the temperature difference is small. • However, most substances in real life have enthalpies that change with the temperature. • When it is necessary to account for this variation, an approximate empirical expression can be utilized

Dependence of Enthalpy on Temperature • Where the empirical parameters a, b, and c

Dependence of Enthalpy on Temperature • Where the empirical parameters a, b, and c are independent of temperature and are specific for each substance • Integrate resulting equation for Cp appropriately in order to get ΔH

Free expansion ΔU Isothermal Isochoric Isobaric Adiabatic 0 n. CvΔT q+w w n. CvΔT

Free expansion ΔU Isothermal Isochoric Isobaric Adiabatic 0 n. CvΔT q+w w n. CvΔT n. CpΔT or – wirrev 0 q wrev 0 wirrev 0 ΔH 0 -pextΔV =-n. CvΔT =-pextΔV 0 (for ideal gas) ΔU =ΔU + pΔV =n. CpΔT Adiabatic

Problem • Calculate the change in molar enthalpy of N 2 when it is

Problem • Calculate the change in molar enthalpy of N 2 when it is heated from 25°C to 100°C. N 2(g) Cp, m (J/mol K) a =28. 58; b = 3. 77 x 10 -3 K; c = -0. 50 x 105 K 2

Problem • Water is heated to boiling under a pressure of 1. 0 atm.

Problem • Water is heated to boiling under a pressure of 1. 0 atm. When an electric current of 0. 50 A from a 12 V supply is passed for 300 s through a resistance in thermal contact with it, it is found that 0. 798 g of water is vaporized. Calculate the molar internal energy and enthalpy changes at the boiling point. * 1 A V s = 1 J

Thermochemistry • The study of energy transfer as heat during chemical reactions. • This

Thermochemistry • The study of energy transfer as heat during chemical reactions. • This is where endothermic and exothermic reactions come in. • Standard enthalpy changes of various kinds of reactions have already been determined and tabulated.

Standard Enthalpy Changes • ΔHƟ • Defined as the change in enthalpy for a

Standard Enthalpy Changes • ΔHƟ • Defined as the change in enthalpy for a process wherein the initial and final substances are in their standard states – The standard state of a substance at a specified temperature is its pure form at 1 bar • Standard enthalpy changes are taken to be isothermal changes, except in some cases to be discussed later.

Enthalpies of Physical Change • The standard enthalpy change that accompanies a change of

Enthalpies of Physical Change • The standard enthalpy change that accompanies a change of physical state is called the standard enthalpy of transition • Examples: standard enthalpy of vaporization (Δvap. HƟ) and the standard enthalpy of fusion (Δfus. HƟ)

Enthalpies of chemical change • These are enthalpy changes that accompany chemical reactions. •

Enthalpies of chemical change • These are enthalpy changes that accompany chemical reactions. • We utilize a thermochemical equation for such enthalpies, a combination of a chemical equation and the corresponding change in standard enthalpy. • Where ΔHƟ is the change in enthalpy when the reactants in their standard states change to the products in their standard states.

Hess’s Law • Standard enthalpies of individual reactions can be combined to acquire the

Hess’s Law • Standard enthalpies of individual reactions can be combined to acquire the enthalpy of another reaction. This is an application of the First Law named the Hess’s Law • “The standard enthalpy of an overall reaction is the sum of the standard enthalpies of the individual reactions into which a reaction may be divided. ”

Hess’s Law: Example

Hess’s Law: Example

Standard Enthalpies of Formation • The standard enthalpy of formation, denoted as Δf. HƟ,

Standard Enthalpies of Formation • The standard enthalpy of formation, denoted as Δf. HƟ, is the standard reaction enthalpy for the formation of 1 mole of the compound from its elements in their reference states. • The reference state of an element is its most stable state at the specified temperature and 1 bar. • Example: Benzene formation 6 C (s, graphite) + 3 H 2(g) C 6 H 6 (l) Δf. HƟ = 49 k. J/mol

The temperature dependence of reaction enthalpies • d. H = Cpd. T • From

The temperature dependence of reaction enthalpies • d. H = Cpd. T • From this equation, when a substance is heated from T 1 to T 2, its enthalpy changes from the enthalpy at T 1 to the enthalpy at T 2.

Kirchhoff’s Law • It is normally a good approximation to assume that Δr. CpƟ

Kirchhoff’s Law • It is normally a good approximation to assume that Δr. CpƟ is independent of temperature over a limited temperature range, but when the temperature dependence of heat capacities must be taken into account, we can utilize another equation

Dependence of Enthalpy on Temperature • Where the empirical parameters a, b, and c

Dependence of Enthalpy on Temperature • Where the empirical parameters a, b, and c are independent of temperature and are specific for each substance • Integrate resulting equation for Cp appropriately in order to get ΔH

Kirchhoff’s Law: Example

Kirchhoff’s Law: Example

Exercise

Exercise