Chapter 17 THERMODYNAMICS What is Thermodynamics Thermodynamics is

  • Slides: 28
Download presentation
Chapter 17 THERMODYNAMICS

Chapter 17 THERMODYNAMICS

What is Thermodynamics? Thermodynamics is the study of energy changes that accompany physical and

What is Thermodynamics? Thermodynamics is the study of energy changes that accompany physical and chemical processes. Word origin: “Thermo”, from temperature, meaning heat “Dynamics”, which means motion (under the action of forces) Chemical thermodynamics answers the questions: v How much heat is evolved during a chemical reaction ("thermochemistry")? v What determines the direction of spontaneous chemical reactions?

Spontaneous Processes A spontaneous process occurs by itself without any ongoing outside intervention Examples:

Spontaneous Processes A spontaneous process occurs by itself without any ongoing outside intervention Examples: A cube of ice melting in water; a steel pipe rusting; Spontaneous chemical reactions behave the same way Ø Reaction continues until equilibrium is reached Ø If a reaction is spontaneous in one direction, it is not spontaneous in the other Ø Spontaneity has nothing to do with rate/speed of reaction

Spontaneity versus Speed/Rate Spontaneous; 1 atm, 25 0 C C Diamond C Graphite Nonspontaneous;

Spontaneity versus Speed/Rate Spontaneous; 1 atm, 25 0 C C Diamond C Graphite Nonspontaneous; 1 atm, 25 0 C Spontaneous = Thermodynamically favorable; Large Keq) BUT… Extremely slow = Kinetically unfavorable; Small rate) Spontaneous ≠ Instantaneous (Fast)

Spontaneous Processes If a reaction is spontaneous in one direction, it is not spontaneous

Spontaneous Processes If a reaction is spontaneous in one direction, it is not spontaneous in the other Ø Diamond to graphite: Spontaneous (but extremely slow) at room T Ø Graphite to diamond: Nonspontaneous at room T (otherwise we’ll all be rich!) Ø Melting of ice cube at room T is spontaneous, but freezing of water at room T is not spontaneous. In the examples above energy is conserved (1 st law). Yet one process occurs while the other does not.

Spontaneous Processes (Cont. ) Spontaneous processes may need a little “push” to get started

Spontaneous Processes (Cont. ) Spontaneous processes may need a little “push” to get started Example: Hydrogen and oxygen gases burn spontaneously only after being ignited by a spark 2 H 2 (g) + O 2 (g) 2 H 2 O(l) Ø The reverse reaction is nonspontaneous (i. e. Water does not simply decompose into H 2 and O 2 gases)

Nonspontaneous reactions Can we make nonspontaneous reactions happen? v Yes. It happens everyday. HOW?

Nonspontaneous reactions Can we make nonspontaneous reactions happen? v Yes. It happens everyday. HOW? Ø By supplying energy Examples: Photosynthesis (CO 2 (g) + H 2 O (l) = Carbohydrates) takes place upon absorption of solar energy The nonspontaneous reaction 2 H 2 O(l) 2 H 2 (g) + O 2 (g) happens if we pass electricity through water (electrolysis)

Factors Affecting Spontaneity 1. Changes in enthalpy (ΔH) a) Exothermic reactions ( - ΔH)

Factors Affecting Spontaneity 1. Changes in enthalpy (ΔH) a) Exothermic reactions ( - ΔH) → tend to be thermodynamically favorable [ large Keq] b) Endothermic reactions ( + ΔH) → tend to be unfavorable Example: All combustion reactions (such as the combustion of natural gas or methane) are spontaneous and exothermic. CH 4 (g) + 2 O 2 (g) CO 2 (g) + 2 H 2 O (g) ΔHrxn 0 = - 802 k. J Methane Ø Spontaneous and Ø Exothermic (- ΔH)

Factors Affecting Spontaneity – Cont. NOTE: Not all exothermic reactions are spontaneous Examples of

Factors Affecting Spontaneity – Cont. NOTE: Not all exothermic reactions are spontaneous Examples of endothermic reactions that are spontaneous Ø Vaporization of water (+ΔH) at ordinary T and P Ø Dissolving of Na. Cl in water (+ΔH) Thus, the sign of ΔH does not always predict spontaneous change Q. What other factor affects direction of spontaneous reactions?

Factors Affecting Spontaneity – Cont. 2. Changes in entropy (ΔS) or degree of “disorder”

Factors Affecting Spontaneity – Cont. 2. Changes in entropy (ΔS) or degree of “disorder” Recall: Entropy (S) is a measure of the dispersal of energy as a function of temperature Ø Closely associated with randomness or disorder a) Increase in entropy ( + ΔS) or disorder → tend to be favorable [ large Keq] b) Decrease in entropy ( - ΔS) or more order → tend to be unfavorable

The “Randomness” Factor In general, nature tends to move spontaneously from a more ordered

The “Randomness” Factor In general, nature tends to move spontaneously from a more ordered state to more random (less ordered) state. Ø Randomness also predicts spontaneous processes An example of a + ΔS What? Are you expecting your room to become more ordered in time? http: //www. lecb. ncifcrf. gov/~toms/ molecularmachines. html

Factors Affecting Spontaneity – Cont. Change to more disordered (more random) state = Increase

Factors Affecting Spontaneity – Cont. Change to more disordered (more random) state = Increase in entropy (+ ΔS) Q. Which of the two images below has a + ΔS? Is spontaneous above 0 0 C? Image source: http: //demo. physics. uiuc. edu/Lect Demo/scripts/demo_descript. idc? Demo. ID=1114 MELTING v More disorder = higher entropy (+ ΔS) v Spontaneous when T > 0 0 C

Entropy (S) is a State Function Recall that entropy is a state function: Ø

Entropy (S) is a State Function Recall that entropy is a state function: Ø Depends only on the initial and final states of the system (Not on path taken from one state to another) ΔS = Sfinal - Sinitial For a chemical reaction, entropy change is expressed as: ΔSrxn = ∑ n x ΔSproducts - ∑ n x ΔSreactants In general: ΔS gas > ΔS liquid > ΔS solid Most disordered Most ordered (Least disorder)

Entropy (S) and Phase Changes Exercise: Predict the sign of ΔS in each of

Entropy (S) and Phase Changes Exercise: Predict the sign of ΔS in each of the following processes. Freezing - ΔS Vaporization + ΔS (becomes more disordered) Condensation - ΔS Reactions that produce gas (+ ΔS) tend to be favorable

Entropy and the 2 nd Law of Thermo. Second law of thermodynamics: In a

Entropy and the 2 nd Law of Thermo. Second law of thermodynamics: In a spontaneous process there is a net increase in the entropy of the universe* Layman’s term: All real processes occur spontaneously in the direction that increases disorder. * Universe = System + Surrounding Thus, ΔSuniverse = ΔSsystem + ΔSsurrounding v A process (or reaction) is spontaneous if ∆Suniverse is (+)

Entropy and the 2 nd Law of Thermo. – Cont. ΔSuniverse = ΔSsystem +

Entropy and the 2 nd Law of Thermo. – Cont. ΔSuniverse = ΔSsystem + ΔSsurrounding Q. When is ∆Suniverse positive? v (+) ∆Suniverse when: ΔSsystem + ΔSsurrounding > 0 If this decreases, ∆Ssurr. must increase even more to offset the system’s decrease in entropy Example: During growth of a child, food molecules (carbs, proteins, etc) are broken down into CO 2, water and energy v Increases ∆Ssurrounding Exothermic ( -∆H) But formation of body mass decreases ∆Ssystem Thus, ↓ ∆Ssystem is offset by ↑ ∆Ssurrounding = Still obeys 2 nd law

Entropy and the 3 rd Law of Thermo. Q. What happens to a system

Entropy and the 3 rd Law of Thermo. Q. What happens to a system if we decrease the temperature continuously? v Entropy will decrease (more order) v Recall: ∆S (g) > ∆S (l) > ∆S (s) Third law of thermodynamics: The entropy of a pure crystalline substance at 0 K is zero. = System All motion/vibration at absolute zero has stopped v Particles in highest order v Ssystem = 0 at T = 0 K

Entropy and 3 rd Law - Cont. It follows that as the temperature of

Entropy and 3 rd Law - Cont. It follows that as the temperature of a system increases, its entropy also increases. v Thus, T (related to ∆H) and entropy (∆S) both influence spontaneous reactions v ∆H can be measured using a calorimeter v How is ∆S measured?

Standard Molar Entropies, S 0 Standard Molar Entropy, S 0 Ø Entropy (S) at

Standard Molar Entropies, S 0 Standard Molar Entropy, S 0 Ø Entropy (S) at standard conditions of 1 atm pressure and 25 0 C temperature for one mole of a substance Ø Unit for S 0: J/mol • K Ø NOTE: Be able to calculate ΔS 0 rxn from given S 0 values ΔS 0 rxn = ∑ n x ΔS 0 products - ∑ n x ΔS 0 reactants Table 17. 1: Standard molar entropies of substances Ø Elements and compounds have (+) S 0 Ø Aqueous ions may have (+) or (-) S 0

Gibbs Free Energy, G Ø So far you’ve learned that both ∆H and ∆S

Gibbs Free Energy, G Ø So far you’ve learned that both ∆H and ∆S affect reaction spontaneity Ø Is there an equation that relates these two thermodynamic quantities? At a constant temperature, the free energy change, ΔG, of a system is given by the Gibbs-Helmholtz equation: ΔG = ΔH - TΔS Free energy change Enthalpy change Kelvin T * Entropy change

Standard Free Energy Change, ΔG 0 The standard free energy change, ΔG 0, applies

Standard Free Energy Change, ΔG 0 The standard free energy change, ΔG 0, applies to standards states as follows: (1) 1 atm pressure for pure liquids and solids (2) 1 atm partial pressure for gases (3) 1 M concentration for solutions Mathematically: ΔG 0 = ΔH 0 - TΔS 0 Importance of Free Energy Change: Ø The sign of ΔG 0 determines reaction spontaneity

Importance of ΔG 0 The sign of ΔG 0 determines reaction spontaneity (1) -

Importance of ΔG 0 The sign of ΔG 0 determines reaction spontaneity (1) - ΔG 0 = spontaneous reaction* (2) + ΔG 0 = nonspontaneous reaction (3) ΔG 0 = 0 for reactions at equilibrium (occurs in either direction) *At a constant T and P, reactions go in the direction that lowers the free energy of the system.

ΔG 0 and Spontaneous Reactions Q. Just when is a reaction spontaneous by looking

ΔG 0 and Spontaneous Reactions Q. Just when is a reaction spontaneous by looking at ΔG 0? ΔG 0 = ΔH 0 - TΔS 0 Source: Principles of General Chemistry by Silberberg, © 2007.

ΔG 0 versus ΔG ΔG 0 vs. ΔG 0 = free energy of the

ΔG 0 versus ΔG ΔG 0 vs. ΔG 0 = free energy of the system at standard conditions [Pgas = 1 atm; [ ] = 1 M for species in solution (aq)] v Fixed during a reaction under std. conditions ΔG = free energy of the system at any given condition [i. e. at any point in the reaction] v Changes during a reaction

Importance of ΔG 0 For a given chemical reaction a. A + b. B

Importance of ΔG 0 For a given chemical reaction a. A + b. B → c. C + d. D the free energy of the reaction is given by the equation ∆G = ∆G 0 + RT ln Q Reaction quotient Std. free energy Gas constant Kelvin temp. Q = [C]c [D]d [A]a [B]b

Importance of ΔG 0 – Cont. At equilibrium, reaction seem to have stopped (ratefwd

Importance of ΔG 0 – Cont. At equilibrium, reaction seem to have stopped (ratefwd = raterev. ) and: At equilibrium ∆G = 0 ; Q = Keq ∆G = ∆G 0 + RT ln Q = Keq =0 Thus, or 0 = ∆G 0 + RT ln Keq at equilibrium ∆G 0 = - RT ln Keq - (∆G 0/RT) or Keq = e Importance of this equation: v Allows us to calculate ∆G 0 given Keq or Keq given ∆G 0