Momentum Dr Walker Momentum Momentum is the reaction

  • Slides: 38
Download presentation
Momentum Dr. Walker

Momentum Dr. Walker

Momentum • Momentum is the reaction of an object to a force exerted upon

Momentum • Momentum is the reaction of an object to a force exerted upon it – Refers to inertia in motion – Inertia is the tendency of an Object to Resist a Change in Movement • Mass is a Measurement of Inertia • It is harder to stop a large truck than a smaller vehicle • In football, a 220 lb running back that is moving forward can run through a stationary (or moving) 190 lb defensive back

Momentum • Momentum = mass x velocity • Momentum is a vector quantity similar

Momentum • Momentum = mass x velocity • Momentum is a vector quantity similar to force

Momentum • Different objects can have the same momentum – The 220 lb (100

Momentum • Different objects can have the same momentum – The 220 lb (100 kg) running back with a velocity of 8. 5 m/s has the same momentum as a 198 lb (90 kg) defensive back with a velocity of 9. 44 m/s. – Running back momentum = 100 kg x 8. 5 m/s = 850 kg. m/s – Defensive back momentum = 90 kg x 9. 4 4 m/s = 850 kg. m/s

Changes In Momentum • If the mass (unlikely) or velocity (more likely) of an

Changes In Momentum • If the mass (unlikely) or velocity (more likely) of an object changes, the momentum (p) changes • If a force acts on a moving object – The object will accelerate (F = ma) – The velocity changes (v = at) – The momentum will change (p = mv) • p is the symbol for momentum

Changing Momentum • If the change in momentum occurs over a long time, the

Changing Momentum • If the change in momentum occurs over a long time, the force of impact is small.

Changing Momentum • If the change in momentum occurs over a short time, the

Changing Momentum • If the change in momentum occurs over a short time, the force of impact is large.

Impulse • Impulse is a change in momentum • Impulse = FDt – When

Impulse • Impulse is a change in momentum • Impulse = FDt – When you work out the units for impulse, you have kg. m/s 2 x s, which equals kg. m/s – This is the same unit as momentum, which is mass x velocity – The relationship between force, acceleration, velocity, and time can be rearranged in a number of different ways

Changes In Momentum The impulse provided by a boxer’s jaw counteracts the momentum of

Changes In Momentum The impulse provided by a boxer’s jaw counteracts the momentum of the punch. a. The boxer moves away from the punch. b. The boxer moves toward the punch. Ouch!

Impulse and Momentum Impulse – Momentum Theorem The Impulse Produced by a Net Force

Impulse and Momentum Impulse – Momentum Theorem The Impulse Produced by a Net Force is Equal to the Change in the Object’s Momentum

Example 1 • Give the momentum of a 1000 kg truck driving at a

Example 1 • Give the momentum of a 1000 kg truck driving at a velocity of 30 m/s. • p = mv • p = (1000 kg)(30 m/s) = 30000 kg m/s

Example 1 • Give the momentum of a 1000 kg truck driving at a

Example 1 • Give the momentum of a 1000 kg truck driving at a velocity of 30 m/s.

Example 2 • Hilary strikes a 0. 058 kg golf ball with a force

Example 2 • Hilary strikes a 0. 058 kg golf ball with a force of 272 N and gives it a velocity of 62. 0 m/s. How long was Hilary’s club in contact with the ball?

Example 2 • Hilary strikes a 0. 058 kg golf ball with a force

Example 2 • Hilary strikes a 0. 058 kg golf ball with a force of 272 N and gives it a velocity of 62. 0 m/s. How long was Hilary’s club in contact with the ball? • (272 N)(Dt) = (0. 058 kg)(62. 0 m/s) – (0. 058 kg)(0 m/s) • Dt = 0. 013 s

Example 3 • A 6. 0 g bullet is fired at a velocity of

Example 3 • A 6. 0 g bullet is fired at a velocity of 350 m/s into a container of ballistic gelatin that stops the bullet in 1. 8 ms. What is the average force that stops the bullet?

Example 3 • A 6. 0 g bullet is fired at a velocity of

Example 3 • A 6. 0 g bullet is fired at a velocity of 350 m/s into a container of ballistic gelatin that stops the bullet in 1. 8 ms. What is the average force that stops the bullet? • F (0. 0018 s) = (0. 006 kg)(0 m/s - 350 m/s) • F = -1. 2 x 103 N • Notice the force is negative because it is acting in the opposite direction that the bullet was initially moving • Vector quantities!!

Example 4 • A hockey puck has a mass of 0. 115 kg and

Example 4 • A hockey puck has a mass of 0. 115 kg and is at rest. A hockey player makes a shot, exerting a constant force of 30. 0 N on the puck for 0. 16 s. With what speed does it head toward the goal?

Example 4 • A hockey puck has a mass of 0. 115 kg and

Example 4 • A hockey puck has a mass of 0. 115 kg and is at rest. A hockey player makes a shot, exerting a constant force of 30. 0 N on the puck for 0. 16 s. With what speed does it head toward the goal? • (30. 0 N)(0. 16 s) = (0. 115 kg)(vf) – (0. 115 kg)(0 m/s) • v = 42 m/s

Conservation of Momentum • In a given system, the momentum can not change unless

Conservation of Momentum • In a given system, the momentum can not change unless it is acted on by an external force – We talked about this previously • In science, when a quantity doesn’t change, it is conserved – In chemistry, we talked about the Law of Conservation of Mass

Conservation of Momentum • The momentum before firing is zero. After firing, the net

Conservation of Momentum • The momentum before firing is zero. After firing, the net momentum is still zero because the momentum of the cannon is equal and opposite to the momentum of the cannonball. Cannon has no momentum Before firing Cannonball has forward Momentum. The cannon Has rearward momentum Net momentum = 0

Conservation of Momentum • Note that no outside force acted on the system. The

Conservation of Momentum • Note that no outside force acted on the system. The ignition of the gunpowder provided energy to send the cannonball forward. To conserve momentum, the cannon reacted in the opposite direction. Cannon has no momentum Before firing Cannonball has forward Momentum. The cannon Has rearward momentum Net momentum = 0

Collisions • An example of a collision with conserved momentum • https: //youtu. be/zaxq.

Collisions • An example of a collision with conserved momentum • https: //youtu. be/zaxq. BAj 0 k. KY

Collision Examples http: //www. physicsclassroom. com/class/momentum/Lesson-2/Momentum-Conservation-Principle

Collision Examples http: //www. physicsclassroom. com/class/momentum/Lesson-2/Momentum-Conservation-Principle

Conservation Of Momentum If a system undergoes changes wherein all forces are internal, the

Conservation Of Momentum If a system undergoes changes wherein all forces are internal, the net momentum of the system before and after the event is the same. Examples are: • Atomic nuclei undergoing radioactive decay • Cars colliding • Stars exploding

Conservation of Momentum • In mathematics terms… – pa = - p b m

Conservation of Momentum • In mathematics terms… – pa = - p b m av a = - m b v b

Example • Consider a 6 -kg fish that swims toward and swallows a 2

Example • Consider a 6 -kg fish that swims toward and swallows a 2 -kg fish that is at rest. If the larger fish swims at 1 m/s, what is its velocity immediately after lunch?

Example • Consider a 6 -kg fish that swims toward and swallows a 2

Example • Consider a 6 -kg fish that swims toward and swallows a 2 -kg fish that is at rest. If the larger fish swims at 1 m/s, what is its velocity immediately after lunch? • pbefore lunch = pafter lunch • pbig fish + plittle fish = pbig fish (after)

Example • Consider a 6 -kg fish that swims toward and swallows a 2

Example • Consider a 6 -kg fish that swims toward and swallows a 2 -kg fish that is at rest. If the larger fish swims at 1 m/s, what is its velocity immediately after lunch? • • pbefore lunch = pafter lunch pbig fish + plittle fish = pbig fish (after) (6 kg)(1 m/s) + (2 kg)(0 m/s) = (8 kg)(vafter) Vafter = 0. 75 m/s

Example 2 • Consider a 6 -kg fish that swims at 1. 0 m/s

Example 2 • Consider a 6 -kg fish that swims at 1. 0 m/s toward and swallows a 2 -kg fish that is swimming 2. 0 m/s in the opposite direction. What is the velocity of the larger fish after his meal?

Example 2 • Consider a 6 -kg fish that swims at 1. 0 m/s

Example 2 • Consider a 6 -kg fish that swims at 1. 0 m/s toward and swallows a 2 -kg fish that is swimming 2. 0 m/s in the opposite direction. What is the velocity of the larger fish after his meal? • • Notice the velocity is negative because the little fish is swimming in the opposite direction!! pbefore lunch = pafter lunch pbig fish + plittle fish = pbig fish (after) (6 kg)(1. 0 m/s) + (2 kg)(- 2. 0 m/s) = (8 kg)(vafter) Vafter = 0. 25 m/s

Example 3 • Ben and Erika are at an ice skating rink they stand

Example 3 • Ben and Erika are at an ice skating rink they stand at rest and Ben pushes Erika. Ben is sent in one direction at a velocity of 0. 90 m/s while Erika is sent the other direction at 1. 2 m/s. If Ben’s mass is 96 kg, what is Erika’s mass?

Example 3 • Ben and Erika are at an ice skating rink they stand

Example 3 • Ben and Erika are at an ice skating rink they stand at rest and Ben pushes Erika. Ben is sent in one direction at a velocity of 0. 90 m/s while Erika is sent the other direction at 1. 2 m/s. If Ben’s mass is 96 kg, what is Erika’s mass? • p. Ben = p. Erika • (96 kg)(0. 90 m/s) = m. Erika(1. 2 m/s) • m. Erika = 72 kg

Example 4 • Erika (72 kg) is standing still on ice skates, when Ben

Example 4 • Erika (72 kg) is standing still on ice skates, when Ben (96 kg) is skating at 1. 5 m/s and grabs Erika. After grabbing Erika, what is the new velocity of the pair assuming momentum is conserved?

Example 4 • Erika (72 kg) is standing still on ice skates, when Ben

Example 4 • Erika (72 kg) is standing still on ice skates, when Ben (96 kg) is skating at 1. 5 m/s and grabs Erika. After grabbing Erika, what is the new velocity of the pair assuming momentum is conserved? • p. Ben + p. Erika = pboth • (96 kg)(1. 5 m/s) + (72 kg)(0 m/s) = (168 kg)(vboth) • vboth = 0. 86 m/s

Example 5 • A 2575 kg van runs into the back of an 825

Example 5 • A 2575 kg van runs into the back of an 825 kg compact car at rest. They move off together at 8. 5 m/s. Assuming that the friction with the road is negligible, calculate the initial speed of the van.

Example 5 • A 2575 kg van runs into the back of an 825

Example 5 • A 2575 kg van runs into the back of an 825 kg compact car at rest. They move off together at 8. 5 m/s. Assuming that the friction with the road is negligible, calculate the initial speed of the van. • Pvan + pcar = pcombined • (2575 kg)vvan + (825 kg)(0 m/s)= (2575 kg + 825 kg)(8. 5 m/s) • (2575 kg)vvan = 28900 kgm/s • Vvan = 11. 2 m/s

Momentum Vectors • Since momentum is a vector, is has a direction • Not

Momentum Vectors • Since momentum is a vector, is has a direction • Not all collisions are head on – If collisions occur at an angle, the combined momentum will have a resultant, just like any other 2 -dimensional process

Momentum Vectors • If an object breaks apart, the pieces will have the same

Momentum Vectors • If an object breaks apart, the pieces will have the same total momentum as the original • This is observed when firecrackers explode