CCE 201 Solid State Electronic Devices EEC 223

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CCE 201: Solid State Electronic Devices EEC 223: Electronics (1) Lecture 04: Diodes Prepared

CCE 201: Solid State Electronic Devices EEC 223: Electronics (1) Lecture 04: Diodes Prepared By Dr. Eng. Sherif Hekal Assistant Professor, CCE department Lecture 01 11/30/2020 1

Report 01 – Sol. • Prove that the built-in potential across the PN junction

Report 01 – Sol. • Prove that the built-in potential across the PN junction is given by • Solution: when no voltage applied and at equilibrium, no current flows and we have Note: 11/30/2020 2

Introduction • In this Lecture we will learn • the characteristics of the ideal

Introduction • In this Lecture we will learn • the characteristics of the ideal diode and how to analyze and design circuits containing multiple ideal diodes together with resistors and dc sources • the i-v characteristic of the junction diode and how to use it to analyze diode circuits operating in the various bias regions: forward, reverse, and breakdown • a simple but effective model of the diode i-v characteristic in the forward direction: the constantvoltage-drop model 11/30/2020 3

Introduction • a powerful technique for the application and modeling of the diode (and

Introduction • a powerful technique for the application and modeling of the diode (and in later chapters, transistors): dc-biasing the diode and modeling its operation for small signals around the dc-operating point by means of the small-signal model • the use of a string of forward-biased diodes and of diodes operating in the breakdown region (zener diodes), to provide constant dc voltages (voltage regulators) • application of the diode in the design of rectifier circuits, which convert ac voltages to dc as needed for powering electronic equipment • a number of other practical and important 11/30/2020 4 applications

Introduction Semiconductor Diode Notation Various types of junction diodes 11/30/2020 5

Introduction Semiconductor Diode Notation Various types of junction diodes 11/30/2020 5

Diode Testing • Diode Checking Function • Ohmmeter Testing • Curve Tracer 6

Diode Testing • Diode Checking Function • Ohmmeter Testing • Curve Tracer 6

4. 1. 1. Current-Voltage Characteristic of the Ideal Diode • ideal diode – most

4. 1. 1. Current-Voltage Characteristic of the Ideal Diode • ideal diode – most fundament nonlinear circuit element • two terminal device • circuit symbol shown to right • operates in two modes • on and off Figure 4. 1: Diode characteristics 11/30/2020 7

4. 1. 1. Current-Voltage Characteristic • cathode – negative terminal, from which current flows

4. 1. 1. Current-Voltage Characteristic • cathode – negative terminal, from which current flows • anode – positive terminal of diode, into which current flows • voltage-current (VI) behavior is: • nonlinear curve consists of straight-line segments and it is called piecewise linear. 11/30/2020 8

4. 1. 1: Current-Voltage 4. 1. 1. Current-Voltage Characteristic of the Ideal Diode mode

4. 1. 1: Current-Voltage 4. 1. 1. Current-Voltage Characteristic of the Ideal Diode mode #2: mode #1: reverse bias = forward bias = open ckt. short ckt • ideal diode: is most fundament device symbol nonlinear circuit element with two nodes • two terminal device with circuit symbol to right • operates in two modes forward and reverse bias figure 4. 1. 11/30/2020 9

4. 1. 1. Current-Voltage Characteristic • External circuit should be designed to limit… •

4. 1. 1. Current-Voltage Characteristic • External circuit should be designed to limit… • current flow across conducting diode • voltage across blocking diode • Examples are shown to right… Figure 4. 2: The two modes of operation of ideal diodes and the use of an external circuit to limit (a) the forward current and (b) the reverse voltage. 11/30/2020 10

4. 1. 2: A Simple Application – The Rectifier • One fundamental application of

4. 1. 2: A Simple Application – The Rectifier • One fundamental application of this piecewise linear behavior is the rectifier. • Q: What is a rectifier? • A: Circuit which converts AC waves in to DC…ideally with no loss. Figure 4. 3(a): Rectifier Circuit 11/30/2020 11

4. 1. 2: A Simple Application – The Rectifier • This circuit is composed

4. 1. 2: A Simple Application – The Rectifier • This circuit is composed of diode and series resistor. • Q: How does this circuit operate? • A: The diode blocks reverse current flow, preventing negative voltage across R. Figure 4. 3(a): Rectifier Circuit 11/30/2020 12

4. 1. 2: A Simple Application – The Rectifier (a) (b) (c) Input waveform

4. 1. 2: A Simple Application – The Rectifier (a) (b) (c) Input waveform Output waveform. (d) (e) 11/30/2020 13

EXERCISE 4. 1 For the circuit in Fig. 4. 3(a), sketch the transfer characteristic

EXERCISE 4. 1 For the circuit in Fig. 4. 3(a), sketch the transfer characteristic v. O versus v. I. 11/30/2020 14

Example 4. 1: Diode Rectifier • Consider the circuit of Figure 4. 4. A

Example 4. 1: Diode Rectifier • Consider the circuit of Figure 4. 4. A source (v. S) with peak amplitude of 24 V is employed to charge a 12 V dc-battery. • Q(a): Find the fraction of each cycle during which the diode conducts. • Q(b): Find peak value of diode current and maximum reverse-bias voltage that appears across the diode. Figure 4. 4: Circuit and Waveforms for Example 4. 1. 11/30/2020 15

Example 4. 1: Diode Rectifier 11/30/2020 16

Example 4. 1: Diode Rectifier 11/30/2020 16

4. 1. 3. Another Application, Diode Logic Gates • Q: How may diodes be

4. 1. 3. Another Application, Diode Logic Gates • Q: How may diodes be used to create logic gates? • A: Examples of AND / OR gates are shown right. • Refer to next Figure 4. 5: Diode logic gates: (a) OR gate; (b) AND gate (in a positive-logic system). slide. 11/30/2020 17

OR GATE AND GATE IF v. A = 5 V THEN diode. A will

OR GATE AND GATE IF v. A = 5 V THEN diode. A will conduct AND v. Y = v. A = 5 V IF v. A = 0 V THEN diode. A will conduct AND v. Y = v. A = 0 V IF all diodes block THEN v. Y = 5 V IF any diode conducts THEN v. Y = 5 V + 5 V- + 5 V - 11/30/2020 18

Example 4. 2: More Diodes To apply nodal / mesh techniques, one must have

Example 4. 2: More Diodes To apply nodal / mesh techniques, one must have knowledge of all component impedances. • Q: What difficulties are Figure 4. 4: Circuit and Waveforms for Example 4. 1. associated with multidiode circuits? • A: Circuit cannot be solved without knowledge of diodes’ statuses. Yet, statuses are Figure 4. 6: Circuits for Example 4. 2. dependent on the IF v. B < 0 THEN ZD 1 = 0 ohms solution. ELSE ZD 1 = open circuit 11/30/2020 19

Example 4. 2: More Diodes • Q: How does one solve these circuits? •

Example 4. 2: More Diodes • Q: How does one solve these circuits? • A: One must use the following steps… • 1) assume the status of all diodes • 2) solve via mesh / nodal analysis • 3) check for coherence 11/30/2020 20

Example 4. 2: More Diodes If answer to either of these is no, then

Example 4. 2: More Diodes If answer to either of these is no, then the solution is not physically realizable. • Q: How does one check for coherence? • A: One must ask the following questions… • 1) Are calculated voltages across all “assumed conducting” diodes forward-biased? • 2) Are the calculated currents through all “assumed blocking” diodes zero? • Q: What does one do, if the solution is not coherent? • A: One must change one or more of these assumptions and solve as well as check for coherence again. 11/30/2020 21

Example 4. 2 – Sol. For the circuit in Fig. 4. 6(a), we shall

Example 4. 2 – Sol. For the circuit in Fig. 4. 6(a), we shall assume that both diodes are conducting. It follows that VB = 0 and V = 0. The current through D 2 can now be determined from Writing a node equation at B, results in I = 1 m. A. Thus D 1 is conducting as originally assumed, and the final result is I = 1 m. A and V = 0 V. 11/30/2020 22

Example 4. 2 – Sol. For the circuit in Fig. 4. 6(b), if we

Example 4. 2 – Sol. For the circuit in Fig. 4. 6(b), if we assume that both diodes are conducting, then VB = 0 and V = 0. The current in D 2 is obtained from The node equation at B is which yields I = − 1 m. A. Since this is not possible, our original assumption is not correct. We start again, assuming that D 1 is off and D 2 is on. The current ID 2 is given by and the voltage at node B is Thus D 1 is reverse biased as assumed, and the final result is I = 0 and V = 3. 3 11/30/2020 V. 23

4. 2. Terminal Characteristics of Junction Diodes • 11/30/2020 24

4. 2. Terminal Characteristics of Junction Diodes • 11/30/2020 24

4. 2. 1. The Forward-Bias Region • The forward-bias region of operation is entered

4. 2. 1. The Forward-Bias Region • The forward-bias region of operation is entered when v > 0. • I-V relationship is closely approximated by equations to right. (4. 3) is a simplification suitable for large v 25

4. 2. 1. The Forward-Bias Region • Equation (4. 3) may be reversed to

4. 2. 1. The Forward-Bias Region • Equation (4. 3) may be reversed to yield (4. 4). • This relationship applies over as many as seven decades of current. 26

4. 2. 1. The Forward. Bias Region • Q: What is the relative effect

4. 2. 1. The Forward. Bias Region • Q: What is the relative effect of current flow (i) on forward biasing voltage (v)? • A: Very small. • 10 x change in i, effects 60 m. V change in v. 27

4. 2. 1: The Forward-Bias Region • cut-in voltage – is voltage, below which,

4. 2. 1: The Forward-Bias Region • cut-in voltage – is voltage, below which, minimal current flows • approximately 0. 5 V • fully conducting region – is region in which Rdiode is approximately equal 0 • between 0. 6 and 0. 8 V fully conducting region 11/30/2020 28

Temperature dependence of the diode forward characteristic the voltage drop across the diode decreases

Temperature dependence of the diode forward characteristic the voltage drop across the diode decreases by approximately 2 m. V for every 1°C increase in temperature. So diodes could be used in the design of electronic thermometers 11/30/2020 29

4. 2. 2. The Reverse-Bias Region • The reverse-bias region of operation is entered

4. 2. 2. The Reverse-Bias Region • The reverse-bias region of operation is entered when v < 0. • I-V relationship, for negative voltages with |v| > VT (25 m. V), is closely approximated by equations to right. 30

4. 2. 2. The Reverse-Bias Region • A “real” diode exhibits reverse-bias current, although

4. 2. 2. The Reverse-Bias Region • A “real” diode exhibits reverse-bias current, although small, much larger than IS. • 10 -9 vs. 10 -14 Amps • A large part of this reverse current is attributed to leakage effects. • whereas IS doubles for every 5°C rise in temperature, • the corresponding rule of thumb for the temperature dependence of the reverse current is that it doubles for every 10°C rise in temperature. 11/30/2020 31

4. 2. 2. The Reverse-Bias Region 11/30/2020 32

4. 2. 2. The Reverse-Bias Region 11/30/2020 32

4. 2. 3. The Breakdown Region • The breakdown region of operation is entered

4. 2. 3. The Breakdown Region • The breakdown region of operation is entered when v < VZK. • Zener-Knee Voltage (VZK) • This is normally nondestructive. breakdown region 11/30/2020 33

4. 3. Modeling the Diode Forward Characteristic • We are now ready to consider

4. 3. Modeling the Diode Forward Characteristic • We are now ready to consider the analysis of circuits employing forward-conducting diodes. • Upcoming slides, we will discuss simplified diode models better suited for use in circuit analyses: • • exponential model constant voltage-drop model ideal diode model small-signal (linearization) model 11/30/2020 34

4. 3. 1. The Exponential Model • exponential diode model • most accurate •

4. 3. 1. The Exponential Model • exponential diode model • most accurate • most difficult to employ in circuit analysis • due to nonlinear nature 11/30/2020 35

4. 3. 1. The Exponential Model • Q: How does one solve for ID

4. 3. 1. The Exponential Model • Q: How does one solve for ID in circuit to right? • VDD = 5 V • R = 1 k. Ohm • ID = 1 m. A @ 0. 7 V • A: Two methods exist… • graphical method • iterative method Figure 4. 10: A simple circuit used to illustrate the analysis of circuits in which the diode is forward conducting. 36

4. 3. 2. Graphical Analysis Using Exponential Model • step #1: Plot the relationships

4. 3. 2. Graphical Analysis Using Exponential Model • step #1: Plot the relationships of (4. 6) and (4. 7) on single graph • step #2: Find intersection of the two… • load line and diode Figure 4. 11: Graphical analysis of the circuit in Fig. 4. 10 using the exponential diode model. characteristic intersect at operating point 11/30/2020 37

4. 3. 2. Graphical Analysis Using Exponential Model • Pro’s • Intuitive • b/c

4. 3. 2. Graphical Analysis Using Exponential Model • Pro’s • Intuitive • b/c of visual nature • Con’s • Poor Precision • Not Practical for Complex Analyses • multiple lines Figure 4. 11: Graphical analysis of the circuit in Fig. 4. 10 using the exponential diode model. required 11/30/2020 38

4. 3. 3. Iterative Analysis Using Exponential Method • step #1: Start with initial

4. 3. 3. Iterative Analysis Using Exponential Method • step #1: Start with initial guess of VD. • VD(0) • step #2: Use nodal / mesh analysis to solve I D. • step #4: Repeat these steps until VD(k+1) = VD(k). • Upon convergence, the new and old values of VD will match. • step #3: Use exponential model to update VD. • VD(1) = f(VD(0)) 11/30/2020 39

4. 3. 3. Iterative Analysis Using Exponential Method • Pro’s • High Precision •

4. 3. 3. Iterative Analysis Using Exponential Method • Pro’s • High Precision • Con’s • Not Intuitive • Not Practical for Complex Analyses • 10+ iterations may be required 11/30/2020 40

EXAMPLE 4. 4 11/30/2020 41

EXAMPLE 4. 4 11/30/2020 41

EXAMPLE 4. 4 11/30/2020 42

EXAMPLE 4. 4 11/30/2020 42

4. 3. Modeling the Diode Forward Characteristic The Need for Rapid Analysis • Q:

4. 3. Modeling the Diode Forward Characteristic The Need for Rapid Analysis • Q: How can one analyze these diodebased circuits more efficiently? • A: Find a simpler model. • One example is assume that voltage drop across the diode is constant. 11/30/2020 43

4. 3. 5. The Constant Voltage-Drop Model • The constant voltage-drop diode model assumes

4. 3. 5. The Constant Voltage-Drop Model • The constant voltage-drop diode model assumes that the slope of ID vs. VD is vertical @ 0. 7 V • Q: How does example 4. 4 solution change if CVDM is used? • A: 4. 262 m. A to 4. 3 m. A Figure 4. 12: Development of the diode constant-voltagedrop model: (a) the exponential characteristic; (b) approximating the exponential characteristic by a constant voltage, usually about 0. 7 V; (c) the resulting model of the forward–conducting diodes. 11/30/2020 44

4. 3. 6. Ideal Diode Model • The ideal diode model assumes that the

4. 3. 6. Ideal Diode Model • The ideal diode model assumes that the slope of ID vs. VD is vertical @ 0 V • Q: How does example 4. 4 solution change if ideal model is used? • A: 4. 262 m. A to 5 m. A 11/30/2020 45

EXERCISE 4. 11 Design the circuit in Fig. E 4. 11 to provide an

EXERCISE 4. 11 Design the circuit in Fig. E 4. 11 to provide an output voltage of 2. 4 V. Assume that the diodes available have 0. 7 -V drop at 1 m. A. 11/30/2020 46

When to use these models? • exponential model • low voltages • less complex

When to use these models? • exponential model • low voltages • less complex circuits • emphasis on accuracy over practicality • constant voltage- drop mode: • medium voltages = 0. 7 V • more complex circuits • emphasis on practicality over accuracy • ideal diode model • high voltages >> 0. 7 V • very complex circuits • cases where a difference in voltage by 0. 7 V is negligible • small-signal model • this is next… 11/30/2020 47

4. 3. 7. Small-Signal Model • small-signal diode model • Diode is modeled as

4. 3. 7. Small-Signal Model • small-signal diode model • Diode is modeled as variable resistor. • Whose value is defined via linearization of exponential model. • Around bias point defined by constant voltage drop model. • VD(0) = 0. 7 V 11/30/2020 48

4. 3. 7. Small-Signal Model 11/30/2020 49

4. 3. 7. Small-Signal Model 11/30/2020 49

4. 3. 7. Small-Signal Model • Q: How is the small-signal diode model defined?

4. 3. 7. Small-Signal Model • Q: How is the small-signal diode model defined? • A: The total instantaneous circuit is divided into steady-state and time varying components, which may be analyzed separately and solved via algebra. • In steady-state, diode represented as CVDM. • In time-varying, diode represented as resistor. 11/30/2020 50

CVDM DC Total Instantaneous AC (v. D. ) Solution = DC Steady-State Solution (VD.

CVDM DC Total Instantaneous AC (v. D. ) Solution = DC Steady-State Solution (VD. ) + Time-Varying AC Solution (vd. ) Figure 4. 14: (a) Circuit for Example 4. 5. (b) Circuit for calculating the dc operating point. (c) Small-signal equivalent circuit. 11/30/2020 51

4. 3. 7. Small-Signal Model • Q: How is the small-signal diode model defined?

4. 3. 7. Small-Signal Model • Q: How is the small-signal diode model defined? • step #1: Consider the conceptual circuit of Figure 4. 13(a). • DC voltage (VD) is applied to diode • Upon VD, arbitrary time- varying signal vd is superimposed 11/30/2020 52

4. 3. 7. Small-Signal Model • DC only – upper-case w/ upper-case subscript •

4. 3. 7. Small-Signal Model • DC only – upper-case w/ upper-case subscript • time-varying only – lower-case w/ lower-case subscript • total instantaneous – lower-case w/ upper-case subscript • DC + time-varying 11/30/2020 53

4. 3. 7. Small-Signal Model • step #2: Define DC current as in (4.

4. 3. 7. Small-Signal Model • step #2: Define DC current as in (4. 8). • step #3: Define total instantaneous voltage (v. D) as composed of VD and vd. • step #4: Define total instantaneous current (i. D) as function of v. D. 54

4. 3. 7. Small-Signal Model • step #5: Redefine (4. 10) as function of

4. 3. 7. Small-Signal Model • step #5: Redefine (4. 10) as function of both VD and vd. • step #6: Split this exponential in two. • step #7: Redefine total instant current in terms of DC component (ID) and time-varying voltage (vd). 55

4. 3. 7. Small-Signal Model • step #8: Apply power series expansion to (4.

4. 3. 7. Small-Signal Model • step #8: Apply power series expansion to (4. 12). • step #9: Because vd/VT << 1, certain terms may be neglected. 56

4. 3. 7. Small-Signal Model • small signal approximation • Shown to right for

4. 3. 7. Small-Signal Model • small signal approximation • Shown to right for exponential diode model. • total instant current (i. D) • small-signal current (id. ) • small-signal resistance (rd. ) • Valid for vd < 5 m. V amplitude (not peak to peak). 57

4. 3. 7: Small-Signal Model • Q: How is small-signal resistance rd defined? •

4. 3. 7: Small-Signal Model • Q: How is small-signal resistance rd defined? • A: From steady-state current (ID) and thermal voltage (VT) as below. • Note this approximation is only valid for smallsignal voltages vd < 5 m. V. 11/30/2020 58

Example 4. 5: Small-Signal Model • Consider the circuit shown in Figure 4. 14(a)

Example 4. 5: Small-Signal Model • Consider the circuit shown in Figure 4. 14(a) for the case in which R = 10 k. Ohm. • The power supply V+ has a dc value of 10 V over which is super-imposed a 60 Hz sinusoid of 1 V peak amplitude (known as the supply ripple) • Q: Calculate both amplitude of the sine-wave signal observed across the diode. • A: vd. (peak) = 2. 68 m. V • Assume diode to have 0. 7 V drop at 1 m. A current. 11/30/2020 59

Figure 4. 14: (a) circuit for Example 4. 5. (b) circuit for calculating the

Figure 4. 14: (a) circuit for Example 4. 5. (b) circuit for calculating the dc operating point. (c) small-signal equivalent circuit. 11/30/2020 60

Example 4. 5: Small-Signal Model 11/30/2020 61

Example 4. 5: Small-Signal Model 11/30/2020 61

4. 3. 8. Use of Diode Forward Drop in Voltage Regulation • Q: What

4. 3. 8. Use of Diode Forward Drop in Voltage Regulation • Q: What is a voltage • Q: What regulator? • A: Circuit whose voltage output remains stable in spite of changes in supply and load. characteristic of the diode facilitates voltage regulation? • A: The approximately constant voltage drop across it (0. 7 V). 11/30/2020 62

Example 4. 6: Diode-Based Voltage Regulator • Consider circuit shown in Figure 4. 15.

Example 4. 6: Diode-Based Voltage Regulator • Consider circuit shown in Figure 4. 15. A string of three diodes is used to provide a constant voltage of 2. 1 V. • Q: What is the change in this regulated voltage caused by (a) a +/- 10% change in supply voltage and (b) connection of 1 k. Ohm load resistor. Figure 4. 15: Circuit for Example 4. 6. 11/30/2020 63

Example 4. 6: Diode-Based Voltage Regulator Thus, This resistance, along with the resistance R,

Example 4. 6: Diode-Based Voltage Regulator Thus, This resistance, along with the resistance R, forms a voltage divider whose ratio can be used to calculate the change in output voltage due to a ± 10% (i. e. ± 1 V) change in supply voltage. Thus the peak-to-peak change in output voltage will be That is, corresponding to the ± 1 -V (± 10%) change in supply voltage, the output voltage will change by ± 9. 5 m. V or ± 0. 5%. Since this implies a change of about ± 3. 2 m. V per diode, our use of the small signal model is justified. 11/30/2020 64

Example 4. 6: Diode-Based Voltage Regulator When a load resistance of 1 kΩ is

Example 4. 6: Diode-Based Voltage Regulator When a load resistance of 1 kΩ is connected across the diode string, it draws a current of approximately 2. 1 m. A. Thus the current in the diodes decreases by 2. 1 m. A, resulting in a decrease in voltage across the diode string given by 11/30/2020 65

EXERCISE 4. 14 Consider a diode biased at 1 m. A. Find the change

EXERCISE 4. 14 Consider a diode biased at 1 m. A. Find the change in current as a result of changing the voltage by (a) − 10 m. V, (b) − 5 m. V, (c) +5 m. V, and (d) +10 m. V. In each case, do the calculations (i) using the small-signal model and (ii) using the exponential model. 11/30/2020 66

EXERCISE 4. 14 11/30/2020 67

EXERCISE 4. 14 11/30/2020 67

Summary (1) • In the forward direction, the ideal diode conducts any current forced

Summary (1) • In the forward direction, the ideal diode conducts any current forced by the external circuit while displaying a zero-voltage drop. The ideal diode does not conduct in reverse direction; any applied voltage appears as reverse bias across the diode. • The unidirectional current flow property makes the diode useful in the design of rectifier circuits. • The forward conduction of practical silicon-junction diodes is accurately characterized by the relationship i = ISe. V/VT. 11/30/2020 71

Summary (2) • A silicon diode conducts a negligible current until the forward voltage

Summary (2) • A silicon diode conducts a negligible current until the forward voltage is at least 0. 5 V. Then, the current increases rapidly with the voltage drop increasing by 60 m. V for every decade of current change. • In the reverse direction, a silicon diode conducts a current on the order of 10 -9 A. This current is much greater than IS and increases with the magnitude of reverse voltage. 11/30/2020 72

Summary (3) • Beyond a certain value of reverse voltage (that depends on the

Summary (3) • Beyond a certain value of reverse voltage (that depends on the diode itself), breakdown occurs and current increases rapidly with a small corresponding increase in voltage. • Diodes designed to operate in the breakdown region are called zener diodes. They are employed in the design of voltage regulators whose function is to provide a constant dc voltage that varies little with variations in power supply voltage and / or load current. 11/30/2020 73

Summary (4) • In many applications, a conducting diode is modeled as having a

Summary (4) • In many applications, a conducting diode is modeled as having a constant voltage drop – usually with value of approximately 0. 7 V. • A diode biased to operate at a dc current ID has small signal resistance rd = VT/ID. • Rectifiers covert ac voltage into unipolar voltages. Half-wave rectifiers do this by passing the voltage in half of each cycle and blocking the oppositepolarity voltage in the other half of the cycle. 11/30/2020 74