KINETICS JEOPARDY KINETICS Rate Laws Reaction Mechanisms Activation

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KINETICS JEOPARDY

KINETICS JEOPARDY

KINETICS Rate Laws Reaction Mechanisms Activation Energy Integrated Rate Law Rate Constant Equilibrium 100

KINETICS Rate Laws Reaction Mechanisms Activation Energy Integrated Rate Law Rate Constant Equilibrium 100 100 100 200 200 200 300 300 300 400 400 400 500 500 500

Rate Law 100 A reaction has the rate law, Rate = k[A][B]2. What is

Rate Law 100 A reaction has the rate law, Rate = k[A][B]2. What is the overall order for the reaction? Third Order Overall Return

Rate Law -200 A reaction has the rate law, rate = k[A][B]2. If the

Rate Law -200 A reaction has the rate law, rate = k[A][B]2. If the concentration of both A and B are doubled, what happens to the rate? Increases by a factor of 8. Return

Rate law -300 The equation, 2 A + 2 B C + D, describes

Rate law -300 The equation, 2 A + 2 B C + D, describes an elementary reaction which takes place in a single step. What is the rate law? Rate = k[A]2[B]2 Return

Rate Law -400 Based on the following equation, which of the following compounds would

Rate Law -400 Based on the following equation, which of the following compounds would you expect to undergo the most change in concentration in a given amount of time? 2 NH 3 N 2 + 3 H 2 Return

Rate Law -500 For the reaction, 2 XO + O 2 2 XO 2,

Rate Law -500 For the reaction, 2 XO + O 2 2 XO 2, the following data was obtained. What is the rate law for the reaction? Trial [XO] [O 2] rate 1 0. 010 2. 5 2 0. 010 0. 020 5. 0 3 0. 030 0. 020 45. 0 Rate = k [XO]2[O 2] Return

Reaction Mechanism -100 The reaction: A + 3 B D + F was studied

Reaction Mechanism -100 The reaction: A + 3 B D + F was studied and the following mechanism was determined A+B ↔C (fast) C + B D + E (slow) E+B F (very fast) Which step is the rate determining step? The second step (slow step) Return

DAILY DOUBLE 200 * 2 Suppose the reaction: A+B D followed the mechanism A

DAILY DOUBLE 200 * 2 Suppose the reaction: A+B D followed the mechanism A + B ↔ C (fast) C D (slow) What is the rate law for the reaction? Rate = k[A][B] Return

Reaction Mechanism -300 The reaction A + 3 B D + F was followed

Reaction Mechanism -300 The reaction A + 3 B D + F was followed and the following mechanism was determined: A + B ↔ C (fast) C + B D + E (slow) E + B F (very fast) Identify the intermediates. C and E Return

DAILY DOUBLE -400 * 2 The reaction A +3 B D + F was

DAILY DOUBLE -400 * 2 The reaction A +3 B D + F was studied and the mechanism was determined to be: A + B ↔ C (fast) C + B D + E (slow) E + B F (very fast) What is the rate law? Rate = k[A][B]2 Return

Reaction Mechanism 500 The decomposition of H 2 O 2 is determined to occur

Reaction Mechanism 500 The decomposition of H 2 O 2 is determined to occur by the following mechanism: H 2 O 2 + I- H 2 O + IO- (slow) H 2 O 2 + IO- H 2 O + O 2 + I- (fast) What is the overall reaction? 2 H 2 O 2 H 2 O + O 2 Return

Activation Energy-100 How does a catalyst alter the rate of a chemical reaction? Lowers

Activation Energy-100 How does a catalyst alter the rate of a chemical reaction? Lowers the activation energy (provides an alternative pathway) Return

Activation Energy-200 For a one step reaction, the activation energy for the forward reaction

Activation Energy-200 For a one step reaction, the activation energy for the forward reaction is 40 k. J/mol and the enthalpy of reaction is -20 k. J/mole. Which reaction is slower; the forward or the reverse? The reverse reaction is slower Return

Activation Energy-300 According to the collision theory, what two conditions must be met in

Activation Energy-300 According to the collision theory, what two conditions must be met in order for a reaction to occur? Reactants must possess a minimum amount of energy and the collisions must occur with the correct orientation Return

Activation Energy -400 How can the slope of a plot of ln(k) vs 1/T

Activation Energy -400 How can the slope of a plot of ln(k) vs 1/T for a reaction be used to determine the activation energy? By multiplying by –R (-8. 314) Return

Activation Energy -500 For a one step reaction the activation energy is 40 k.

Activation Energy -500 For a one step reaction the activation energy is 40 k. J/mol and the enthalpy of reaction is 20 k. J/mol. What is the activation energy of the reverse reaction? 20 k. J/mol Return

Integrated Rate Law-100 The following reaction was studied: A B + C. The graph

Integrated Rate Law-100 The following reaction was studied: A B + C. The graph of 1/[A] vs time gave a straight line. What is the order of the reaction with respect to A? 2 nd order Return

Integrated Rate Law -200 Given a reaction, 2 A + B P, for which

Integrated Rate Law -200 Given a reaction, 2 A + B P, for which the observed rate law is rate = k [A], what is the integrated rate law? ln[A] = -kt + ln[A]o Return

Integrated Rate Law -300 In a first order reaction, what fraction of the material

Integrated Rate Law -300 In a first order reaction, what fraction of the material will remain after 4 half lives? 1/16 Return

Integrated Rate Law -400 A first order reaction has a rate constant of 0.

Integrated Rate Law -400 A first order reaction has a rate constant of 0. 00318 min-1. What is the half life of the reaction? 21. 8 minutes Return

Integrated Rate Law -500 A graph of [A] vs time gave a straight line.

Integrated Rate Law -500 A graph of [A] vs time gave a straight line. How does doubling the concentration of A affect the rate of the reaction? It has no affect Return

Rate Constant-100 How does changing the concentration affect the rate constant? It has no

Rate Constant-100 How does changing the concentration affect the rate constant? It has no affect Return

Rate Constant -200 How does increasing the temperature affect the rate and the rate

Rate Constant -200 How does increasing the temperature affect the rate and the rate constant? It increases both the rate constant and the rate Return

Rate Constant - 300 What is the unit for the rate constant in a

Rate Constant - 300 What is the unit for the rate constant in a reaction that is 2 nd order overall? L/mol s Return

Rate Constant -400 In a zero order rate law, what units must the rate

Rate Constant -400 In a zero order rate law, what units must the rate concept possess? Mol/L time Return

Rate Constant - 500 A rate constant has the units s-1. Doubling the concentration

Rate Constant - 500 A rate constant has the units s-1. Doubling the concentration would have what affect on the overall rate of reaction? It would double the rate Return

Equilibrium -100 What factors affect the value of Keq? Temperature and nature of reactants

Equilibrium -100 What factors affect the value of Keq? Temperature and nature of reactants Return

Equilibrium -200 How does a catalyst affect the value of Keq? It has no

Equilibrium -200 How does a catalyst affect the value of Keq? It has no effect Return

Equilibrium -300 If K>1, what does that indicate about the equilibrium position? The concentration

Equilibrium -300 If K>1, what does that indicate about the equilibrium position? The concentration of products is greater than the concentration of reactants at equilibrium Return

Equilibrium-500 Increasing the temperature increases the value of Keq. Is the reaction endothermic or

Equilibrium-500 Increasing the temperature increases the value of Keq. Is the reaction endothermic or endothermic? endothermic Return

Equilibrium-400 According to the equation: 3 H 2(g) + N 2(g) 2 NH 3(g),

Equilibrium-400 According to the equation: 3 H 2(g) + N 2(g) 2 NH 3(g), if the volume of the reaction chamber increases, will the forward or reverse reaction be favored? Reverse reaction Return