Chemical Kinetics Reaction Rates Reaction Rate How fast

  • Slides: 26
Download presentation
Chemical Kinetics/ Reaction Rates

Chemical Kinetics/ Reaction Rates

Reaction Rate • How fast reactants become products in a chemical reaction • [

Reaction Rate • How fast reactants become products in a chemical reaction • [ ]/s = M/s

Kinetic Theory 1. 2. 3. All matter is made up of tiny particles are

Kinetic Theory 1. 2. 3. All matter is made up of tiny particles are in constant motion All collisions are elastic (no energy change) *In order for particles to react, they must collide! How fast they collide determines reaction rate.

Rate Expressions • Reactions do not necessarily occur in one step Ex: 2 NO

Rate Expressions • Reactions do not necessarily occur in one step Ex: 2 NO 2(g)→ 2 NO(g)+O 2(g) Actually occurs in TWO steps: 2 NO 2→NO 3+NO (fast) NO 3→NO+O 2 (Slow) *The SLOW step is the rate determining step*

Writing Rate Expressions for Rate Determining Step If “aq” Aqueous: a. A(aq) + b.

Writing Rate Expressions for Rate Determining Step If “aq” Aqueous: a. A(aq) + b. B(aq) P Rate = k[A]a[B]b • [A] = molarity of A • Coefficients exponents • k=rate constant

If “g” gas: a. A(g) + b. B(g) Product a b • Exp: Rate

If “g” gas: a. A(g) + b. B(g) Product a b • Exp: Rate = k. PA PB • PA = Pressure of A • PB = Pressure of B

If it’s a combination of (g) and (aq), just pick 1 1 Cl 2(g)

If it’s a combination of (g) and (aq), just pick 1 1 Cl 2(g) + 1 HOOH (aq) 2 HOCl(aq) Rate = k(PCl 2) OR Rate = k[HOOH] Solids don’t contribute! (concentration =1) 2 A(aq)+ B(aq)+ 3 C(s) P Rate = k[A]2[B]

Reaction Order • Reaction Order = total exponents in rate expression (don’t forget 1!)

Reaction Order • Reaction Order = total exponents in rate expression (don’t forget 1!) Ex. Rate = k[A][B]2 Reaction Order = 3

Rate Determining Step: 2 A(aq)+ B(aq)+ 3 C(s) P Write the rate law expression,

Rate Determining Step: 2 A(aq)+ B(aq)+ 3 C(s) P Write the rate law expression, calculate the rate and determine the order. [A] = 0. 40 M [B] = 0. 20 M k = 2. 0 x 102 M-2 s-1

Think about it. . Rate = [A][B]2 If the initial concentration of B is

Think about it. . Rate = [A][B]2 If the initial concentration of B is increased from 0. 1 M to 0. 3 M, by what factor will the rate increase?

Determining Rate Law from Experimental Results Rate 2 Rate 1 = a b k[A

Determining Rate Law from Experimental Results Rate 2 Rate 1 = a b k[A 2] [B 2] a b k[A 1] [B 1] Solve for a & b

How do you solve for x if Ax=B?

How do you solve for x if Ax=B?

x A =B x Log A = log B x = Log B Log

x A =B x Log A = log B x = Log B Log A

Once you have determined rate law, you can use one of the trials to

Once you have determined rate law, you can use one of the trials to solve for k!

Experiment [Br. O 3 -] (M) [Br-] (M) [H+] (M) Initial Rate (M/s) 1

Experiment [Br. O 3 -] (M) [Br-] (M) [H+] (M) Initial Rate (M/s) 1 0. 10 8. 0 x 10 -4 2 3 4 0. 20 0. 10 0. 20 1. 6 x 10 -3 3. 2 x 10 -3

VIDEO • https: //www. youtube. com/watch? v=Ott. RV 5 yk. P 7 A

VIDEO • https: //www. youtube. com/watch? v=Ott. RV 5 yk. P 7 A

The Collision Model Molecules must collide to react!

The Collision Model Molecules must collide to react!

Factors That Affect Reaction Rates • Concentration of Reactants – As the concentration of

Factors That Affect Reaction Rates • Concentration of Reactants – As the concentration of reactants increases, so does the likelihood that reactant molecules will collide (more particles in a smaller space to run into each other). • Temperature – At higher temperatures, reactants have more KE, move faster, and collide more often. • Catalysts – Speeds up rxn by lowering activation energy. • Surface Area – The larger the surface area, more particles available to collide, the faster the reaction

Activation Energy (Ea) • a minimum amount of energy required for reaction to take

Activation Energy (Ea) • a minimum amount of energy required for reaction to take place *picture ball rolling up a hill

Transition State

Transition State

With a Catalyst

With a Catalyst

Rate Constants • Rate constants (k) are DIFFERENT at DIFFERENT TEMPERATURES • Can use

Rate Constants • Rate constants (k) are DIFFERENT at DIFFERENT TEMPERATURES • Can use the different rate constants to determine activation energy

Clausius-Claperon Eq For: Activation Energy (T 2)(T 1) k 2 Ea= R (T –

Clausius-Claperon Eq For: Activation Energy (T 2)(T 1) k 2 Ea= R (T – T ) ln k 2 1 1 R= 8. 314 J/mol K Temperatures MUST be in K

Calculate the activation energy of a reaction whose rate constant is 2. 0 x

Calculate the activation energy of a reaction whose rate constant is 2. 0 x 103 M-2 S-1 at 27 o. C and is 2. 0 x 106 M-2 S-1 at 77 o. C:

Examples

Examples