Finding the Equation of the Tangent Line to

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Finding the Equation of the Tangent Line to a Curve Remember: Derivative=Slope of the

Finding the Equation of the Tangent Line to a Curve Remember: Derivative=Slope of the Tangent Line

What is the equation for the slope of the line tangent to the curve

What is the equation for the slope of the line tangent to the curve at point A using points A and B?

What is the equation for the slope of the line tangent to the curve

What is the equation for the slope of the line tangent to the curve f(x)=x 2+1 at point A using points A and B?

What is another way to find the slope of this line? The DERIVATIVE!!!!

What is another way to find the slope of this line? The DERIVATIVE!!!!

What is another way to find the slope of this line?

What is another way to find the slope of this line?

Both ways give you the slope of the tangent to the curve at point

Both ways give you the slope of the tangent to the curve at point A. set them equal to each other That means you can _______________.

That means you can set them equal to each other:

That means you can set them equal to each other:

That means you can set them equal to each other:

That means you can set them equal to each other:

Therefore, Is the slope of the tangent line for f(x)=x 2+1

Therefore, Is the slope of the tangent line for f(x)=x 2+1

Formula of the tangent line at a point A (a, f(a)) y-f(a)=f’(a)(x-a)

Formula of the tangent line at a point A (a, f(a)) y-f(a)=f’(a)(x-a)

Step 1: Find the point of contact by plugging in the x-value in f(x).

Step 1: Find the point of contact by plugging in the x-value in f(x). This is f(a).

Step 2: Find f’(x). Plug in x-value for f’(a)

Step 2: Find f’(x). Plug in x-value for f’(a)

Step 3: Plug all known values into formula y-f(a)=f’(a)(x-a)

Step 3: Plug all known values into formula y-f(a)=f’(a)(x-a)

 Find the equation of the tangent to y=x 3+2 x at: l x=2

Find the equation of the tangent to y=x 3+2 x at: l x=2 l x=-1 l x=-2

Question: If the tangent line to a point of f(x) was horizontal, what would

Question: If the tangent line to a point of f(x) was horizontal, what would that tell us about f’(x)? f’(x)=0

Step 1: Find the derivative, f’(x)

Step 1: Find the derivative, f’(x)

Step 2: Set derivative equal to zero and solve, f’(x)=0

Step 2: Set derivative equal to zero and solve, f’(x)=0

Step 3: Plug solutions into original formula to find y-value, (solution, yvalue) is the

Step 3: Plug solutions into original formula to find y-value, (solution, yvalue) is the coordinates.

Note: If it asks for the equation then you will write y=y value found

Note: If it asks for the equation then you will write y=y value found when you plugged in the solutions for f’(x)=0

What do you notice about the labeled minimum and maximum? They are the coordinates

What do you notice about the labeled minimum and maximum? They are the coordinates where the tangent is horizontal Let’s look at the graph of the function f(x)=x 3+3 x 2 -9 x+5 (we have already found the coordinates where the tangent to this curve is horizontal).

Where is the graph increasing? {x| x<-3, x>1} What is the ‘sign’ of the

Where is the graph increasing? {x| x<-3, x>1} What is the ‘sign’ of the derivative for these intervals? + + -3 1 This is called a sign diagram

Where is the graph decreasing? {x| -3<x<1} What is the ‘sign’ of the derivative

Where is the graph decreasing? {x| -3<x<1} What is the ‘sign’ of the derivative for this interval? + + – -3 1 What can we hypothesize about how the sign of the derivative relates to the graph? f’(x)=+, then graph increases f’(x)= – , then graph decreases

We can see this: When the graph is increasing then the gradient of the

We can see this: When the graph is increasing then the gradient of the tangent line is positive (derivative is +) When the graph is decreasing then the gradient of the tangent line is negative (derivative is - )

So back to the question…Why does the fact that the relative max/min of a

So back to the question…Why does the fact that the relative max/min of a graph have horizontal tangents make sense? A relative max or min is where the graph goes from increasing to decreasing (max) or from decreasing to increasing (min). This means that your derivative needs to change signs.

Okay…So what? To go from being positive to negative, the derivative like any function

Okay…So what? To go from being positive to negative, the derivative like any function must go through zero. Where the derivative is zero is where the graph changes direction, aka the relative max/min

Take a look at f(x)=x 3. What is the coordinates of the point on

Take a look at f(x)=x 3. What is the coordinates of the point on the function where the derivative is equal to 0? Find the graph in your calculator, is this coordinate a relative maximum or a relative minimum? NO – the graph only flattened out then continued in the same direction This is called a HORIZONTAL INFLECTION

It is necessary to make a sign diagram to determine whether the coordinate where

It is necessary to make a sign diagram to determine whether the coordinate where f’(x)=0 is a relative maximum, minimum, or a horizontal inflection.

Anywhere that f’(x)=0 is called a stationary point; a stationary point could be a

Anywhere that f’(x)=0 is called a stationary point; a stationary point could be a relative minimum, a relative maximum, or a horizontal inflection

 What do you know about the graph of f(x) when f’(x) is a)

What do you know about the graph of f(x) when f’(x) is a) Positive b) Negative c) Zero What do you know about the slope of the tangent line at a relative extrema? Why is this so? Sketch a graph of f(x) when the sign diagram of f’(x) looks like – + -5 – 1 What are the types of stationary points? What do they all have in common? What do the sign ? diagrams for each type look like? ? Stationary Point