Lecture 18 Power in AC Circuits Hungyi Lee
- Slides: 27
Lecture 18 Power in AC Circuits Hung-yi Lee
Outline • Textbook: Chapter 7. 1 • Computing Average Power • Maximum Power Transfer for AC circuits • Maximum Power Transfer for DC circuits has been discussed in Chapter 3. 1
Average Power for AC Circuits
Review: Power for DC Circuits • Consumed Power for DC Circuits Resistor with resistance R A + - B reference current should flow from “+” to “-” Negative Communed Power = Supplied Power
Power for AC Circuits • Consumed Instantaneous Power A + • If p(t) is periodic with period T • Average Power - B
Average Power for AC Circuits Network Z
Average Power for AC Circuits Absorb power Supply power
Average Power for AC Circuits Network Z
Average Power for AC Circuits Network Z
Summary
Revisit Maximum Power Transfer
Review: Maximum Power Transfer for DC Circuits power Device (Load) Power consumed by Rs Real source Power consumed by RL Rs is fixed, increase RL
Maximum Power Transfer for AC Circuits Real source Device (Load) Real source Source Impedance: Find ZL such that the device can obtain maximum power Device (Load)
Maximum Power Transfer for AC Circuits Voltage Source: Real source Device (Load)
Maximum Power Transfer for AC Circuits Find ZL that maximize P Find XL and RL that maximize P XL = -Xs RL = Rs
Maximum Power Transfer for AC Circuits Only |ZL| can be tuned θ is fixed (R/X is fixed) PL is maximized when Special case: If
Maximum Power Transfer for AC Circuits – Example 1 • Determine ZL that maximize the power drawn from the circuit. What is the maximum power?
Maximum Power Transfer for AC Circuits – Example 1 • Network Find ZT
Maximum Power Transfer for AC Circuits – Example 1 • Network
Maximum Power Transfer for AC Circuits – Example 2 • Find RL that can absorb maximum power
Maximum Power Transfer for AC Circuits Power Transfer Efficiency: Real source Device (Load)
Example 7. 4 Real source Device (Load) Find Power Transfer Efficiency Real source Device (Load)
Example 7. 4 Real source Device (Load)
Homework • 7. 4, 7. 14, 7. 20
Thank you!
Answer • 7. 4: Irms = 5. 65 m. A, 160 m. W • 7. 14: R=141Ω, C=0. 707μF • 7. 20: (a) (12 -5 j)k Ω, 120 μW, 50%; (b) (10. 4 -7. 8 j)k Ω, 90 μW, 46%; (c) 13 k Ω, 115 μW, 52%
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