STOICHIOMETRY What is stoichiometry l Stoichiometry is the

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STOICHIOMETRY

STOICHIOMETRY

What is stoichiometry? l. Stoichiometry is the quantitative study of reactants and products in

What is stoichiometry? l. Stoichiometry is the quantitative study of reactants and products in a chemical reaction.

What You Should Expect l l Given : Amount of reactants Question: how much

What You Should Expect l l Given : Amount of reactants Question: how much of products can be formed. l Example l l 2 A + 2 B 3 C Given 20. 0 grams of A and sufficient B, how many grams of C can be produced?

What do you need? i. iii. iv. You will need to use molar ratios,

What do you need? i. iii. iv. You will need to use molar ratios, molar masses, balancing and interpreting equations, and conversions between grams and moles. Note: This type of problem is often called "mass-mass. "

Steps Involved in Solving Mass-Mass Stoichiometry Problems l l Balance the chemical equation correctly

Steps Involved in Solving Mass-Mass Stoichiometry Problems l l Balance the chemical equation correctly Using the molar mass of the given substance, convert the mass given to moles. Construct a molar proportion (two molar ratios set equal to each other) Using the molar mass of the unknown substance, convert the moles just calculated to mass.

Mole Ratios A mole ratio converts moles of one compound in a balanced chemical

Mole Ratios A mole ratio converts moles of one compound in a balanced chemical equation into moles of another compound.

Example Reaction between magnesium and oxygen to form magnesium oxide. ( fireworks) 2 Mg(s)

Example Reaction between magnesium and oxygen to form magnesium oxide. ( fireworks) 2 Mg(s) + O 2(g) Mole Ratios: 2 : 1 2 Mg. O(s) : 2

Practice Problems 1) N 2 + 3 H 2 ---> 2 NH 3 Write

Practice Problems 1) N 2 + 3 H 2 ---> 2 NH 3 Write the mole ratios for N 2 to H 2 and NH 3 to H 2. 2) A can of butane lighter fluid contains 1. 20 moles of butane (C 4 H 10). Calculate the number of moles of carbon dioxide given off when this butane is burned.

Mole-Mole Problems Using the practice question 2) above: Equation of reaction 2 C 4

Mole-Mole Problems Using the practice question 2) above: Equation of reaction 2 C 4 H 10 + 13 O 2 8 CO 2 + 10 H 2 O Mole ratio C 4 H 10 CO 2 1 : 4 [ bases] 1. 2 : X [ problem] By cross-multiplication, X = 4. 8 mols of CO 2 given off

Mole-Mass Problems l Problem 1: 1. 50 mol of KCl. O 3 decomposes. How

Mole-Mass Problems l Problem 1: 1. 50 mol of KCl. O 3 decomposes. How many grams of O 2 will be produced? [k = 39, Cl = 35. 5, O = 16] 2 KCl. O 3 2 KCl + 3 O 2

Three steps…Get Your Correct Answer Use mole ratio l Get the answer in moles

Three steps…Get Your Correct Answer Use mole ratio l Get the answer in moles and then l Convert to Mass. [Simple Arithmetic] l Hello! If you are given a mass in the problem, you will need to convert this to moles first. Ok?

Let’s go! 2 KCl. O 3 2 : 1. 50 : X = 2.

Let’s go! 2 KCl. O 3 2 : 1. 50 : X = 2. 25 mol Convert to mass 2 KCl + 3 O 2 3 X 2. 25 mol x 32. 0 g/mol = 72. 0 grams Cool!

Try This: We want to produce 2. 75 mol of KCl. How many grams

Try This: We want to produce 2. 75 mol of KCl. How many grams of KCl. O 3 would be required? Soln l KCl. O 3 : KCl 2 : 2 X : 2. 75 X = 2. 75 mol In mass: 2. 75 mol X 122. 55 g/mol = 337 grams zooo zimple!

Mass-Mass Problems l l There are four steps involved in solving these problems: Make

Mass-Mass Problems l l There are four steps involved in solving these problems: Make sure you are working with a properly balanced equation. Convert grams of the substance given in the problem to moles. Construct two ratios - one from the problem and one from the equation and set them equal. Solve for "x, " which is usually found in the ratio from the problem. Convert moles of the substance just solved for into grams.

Mass-Volume Problems Just follow mass problem to the penultimate level

Mass-Volume Problems Just follow mass problem to the penultimate level

Like this: There are four steps involved in solving these problems: l Make sure

Like this: There are four steps involved in solving these problems: l Make sure you are working with a properly balanced equation. l Convert grams of the substance given in the problem to moles. l Construct two ratios - one from the problem and one from the equation and set them equal. Solve for "x, " which is usually found in the ratio from the problem. l Convert moles of the substance just solved for into Volume.

Conversion of mole to volume No of moles = Volume Molar volume Can you

Conversion of mole to volume No of moles = Volume Molar volume Can you remember a similar equation?

Molar volume The molar volume is the volume occupied by one mole of ideal

Molar volume The molar volume is the volume occupied by one mole of ideal gas at STP. Its value is: 22. 4 dm 3

Practice Problems Calculate the volume of carbon dioxide formed at STP in ‘dm 3'

Practice Problems Calculate the volume of carbon dioxide formed at STP in ‘dm 3' by the complete thermal decomposition of 3. 125 g of pure calcium carbonate (Relative atomic mass of Ca=40, C=12, O=16) Solution: Convert the mass to mole: Molar mass of Ca. CO 3 = 40 + 12 + (16 x 3) = 100 gmol-1 Mole = mass/molar mass 3. 125/100 = 0. 03125 mol

Practice Problems As per the equation, Mole ratio 1 : 1 problem 0. 03125

Practice Problems As per the equation, Mole ratio 1 : 1 problem 0. 03125 mol X X = 0. 03125 mol of CO 2 Convert mole to volume [slide 17] 3 x 22. 4)dm Volume = (0. 03125 = 0. 7 dm 3

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