Symmetry and Symmetry Violation in Particle Physics Lecture

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Symmetry and Symmetry Violation 对称 in Particle Physics 违反 Lecture 3 March 21, 2008

Symmetry and Symmetry Violation 对称 in Particle Physics 违反 Lecture 3 March 21, 2008

Summary Lecture 2 • Antimatter predicted by Dirac & discovered by Chao & Anderson

Summary Lecture 2 • Antimatter predicted by Dirac & discovered by Chao & Anderson – 1933 Nobel prize Dirac – 1936 Nobel prize Anderson (but not Chao) • Electron & positron have opposite parity • Charge “reversal” Charge “conjugation” – Particle Antiparticle (not just charge) • C=+1 even # of g’s; C=-1 odd # of g’s • p and K mesons = qq with L=0, S=0 & P=-1

Summary Lecture 2 (pg 2) • t+ = p+p+p- & q+ p+p 0 puzzle

Summary Lecture 2 (pg 2) • t+ = p+p+p- & q+ p+p 0 puzzle led Lee & Yang to question L-R symmetry of nature • C. S. Wu discovered P viol. in Co 60 Ni 60 e-n – 1957 Nobel Prize to Lee & Yang (but not Wu) • t+ and q+ are the same particle, the K+ meson • C & P violation differences seen in m-/m+ decay – But CP seems okay • Large matter vs antimatter asymmetry in the present-day Universe implies CP is violated. • K 0 transitions possible @ 2 nd-order W. I.

C, P Reminder & CP for p and K mesons Particle P C CP

C, P Reminder & CP for p and K mesons Particle P C CP |p+ |p 0 -1 -1 +|p- +|p 0 -|p- -|p 0 |p- -1 +|p+ -|p+ |K+ |K 0 -1 -1 -1 +|K- -|K 0 +|K+ -|K- +|K 0 |K- -1 +|K 0 -|K+

My tentative plan for this class is as follows: Lecture 1. Definition of symmetry,

My tentative plan for this class is as follows: Lecture 1. Definition of symmetry, why they are important in physics. Symmetries of the laws of nature. Relation of symmetry and conservation laws. Discrete symmetries C, P & T. Violation of parity (P) in beta-decay Lecture 2. Antimatter, and matter-antimatter symmetry. Quark content of hadrons & discrete symmetries of hadrons. Violation of parity (P) and charge conjugation (C ) symmetry in beta-decay Particleantiparticle mixing. Lecture 3. K 0 mixing. CP violation in K decay. Difficulties with incorporating CP violation into a physics theory. KM 6 -quark mo CP violation. Role of B mesons in theory Lecture 4. Studying CP violation in the B meson system. Experimental techniques and results. What is left for the future. Lecture 5. Exam

Discovery of CP violation in the neutral K meson system outline • Neutral K

Discovery of CP violation in the neutral K meson system outline • Neutral K meson decay mechanisms • K 0 – K 0 mixing KS and KL mesons • Discovery of KL p+p • CP violation in KL p+e-n/p-e+n decays • “Direct” CP violation in KL pp decays

K 0 p+p- decays via weak interaction - p d K 0 d s

K 0 p+p- decays via weak interaction - p d K 0 d s u DS=-1 W. I. W+ d u p+

K 0 also decays to p+p+ p d K 0 d S u DS=1

K 0 also decays to p+p+ p d K 0 d S u DS=1 W. I. W- u d p-

K 0 possible as a 2 nd order weak interaction process |DS|=2 K 0

K 0 possible as a 2 nd order weak interaction process |DS|=2 K 0 p+ d u d S W+ W. I. W- s u p- d d K 0 This is a so-called “long-range” process. It occurs on a size scale determined by the p mesons: ~ 10 -15 m 1 fermi

K 0 in short-range quark |DS|=2 W. I. S u c WK 0 d

K 0 in short-range quark |DS|=2 W. I. S u c WK 0 d t W. I. d W+ W. I. u c K 0 s t This is a so-called “short-range” process. It occurs on a size scale determined by the t-quark: ~ 10 -18 m 10 -3 fermi

What happens when two identical systems are coupled? Energy transfers back-and-forth between the two

What happens when two identical systems are coupled? Energy transfers back-and-forth between the two oscillators

Steady-state “normal modes”

Steady-state “normal modes”

. . Shrodinger Equation: H Y = EY H Y Y If CP symmetry

. . Shrodinger Equation: H Y = EY H Y Y If CP symmetry holds:

Eigenvalues and Eigenstates 特征值 Find the eigenvalues and eigenvectors for: Answer Homework: Please check

Eigenvalues and Eigenstates 特征值 Find the eigenvalues and eigenvectors for: Answer Homework: Please check that these answers are correct

In standard (textbook) notation

In standard (textbook) notation

If CP symmetry is good:

If CP symmetry is good:

CP of K 1 and K 2 Recall: 1 + = P C CP

CP of K 1 and K 2 Recall: 1 + = P C CP = -1

K 1 decays CP= +1 K 1 + p p ? OK CP= (-1)x(-1)

K 1 decays CP= +1 K 1 + p p ? OK CP= (-1)x(-1) = +1 CP +1 K 1 p + p - p 0? CP = (-1)x(-1) = -1 NG

K 2 decays CP= -1 K 2 + p p ? NG CP= (-1)x(-1)

K 2 decays CP= -1 K 2 + p p ? NG CP= (-1)x(-1) = +1 CP -1 K 2 p + p - p 0? CP = (-1)x(-1) = -1 OK

K 1 & K 2 lifetimes K 2 + p 相空� 0 p p

K 1 & K 2 lifetimes K 2 + p 相空� 0 p p has little phase space QK 2 = MK – 3 Mp 80 Me. V K 1 p + p - has more phase space QK 1 = MK – 2 Mp 215 Me. V Easier for K 1 to decay t. K 1<<t. K 2

1956: Search for long-lived K 0 Brookhaven-Columbia Expt

1956: Search for long-lived K 0 Brookhaven-Columbia Expt

Can you see it?

Can you see it?

KS & KL mesons Two neutral K mesons were discovered: K S p +p

KS & KL mesons Two neutral K mesons were discovered: K S p +p - t. KS 0. 1 nanosecs ( 10 -10 s) 500 x bigger K L p +p -p 0 t. KS 50 nanosecs ( 5 x 10 -8 s) (Are they the CP eigenstates K 1 and K 2? )

KL & KS mesons in e+e- annihilation p. S = 110 Me. V <l>

KL & KS mesons in e+e- annihilation p. S = 110 Me. V <l> = 6 mm e+ p+ 510 Me. V p. L = 110 Me. V <l> = 3. 4 m p 0 p- KL = K-long KS = K-short p+ p- f 510 Me. V e- f = ss M(f) = 1020 Me. V

KLOE Experiment in Italy KL 2 m KS In this event the KL only

KLOE Experiment in Italy KL 2 m KS In this event the KL only travels ~1 m before it decays

Usually, the KL traverses to entire 2 m radius of the drift chamber “crash”

Usually, the KL traverses to entire 2 m radius of the drift chamber “crash” KKL L“crash” b= 0. 22 (TOF) 2 m K S p -e +n KS

Neutral K mesons “Basis” sets These have a well defined quark structure K 1

Neutral K mesons “Basis” sets These have a well defined quark structure K 1 -K 2 K 0 -K 0 Flavor States CP eigenstates These are the Particles that exist in Nature KS-KL Mass eigenstsate are these the same?

Does KS=K 1 & KL=K 2? (i. e. is CP conserved? ) These are

Does KS=K 1 & KL=K 2? (i. e. is CP conserved? ) These are the particles that are observed in nature express them in terms of K 1 and K 2:

inv er t

inv er t

e If CV is conserved: e=0, KS=K 1 & KL=K 2

e If CV is conserved: e=0, KS=K 1 & KL=K 2

Does KL + p p ? Remember, p+p- has CP=+1 Forbidden(? ) |e|2 =0

Does KL + p p ? Remember, p+p- has CP=+1 Forbidden(? ) |e|2 =0 if CP is conserved

Christenson-Cronin-Fitch-Turlay Experiment (1964) p+ KL p-

Christenson-Cronin-Fitch-Turlay Experiment (1964) p+ KL p-

p+p- “invariant mass” M(p+p-)<M(KL) M(p+p-)=M(KL) KL p+ |e|2 = 4 x 10 -6 small,

p+p- “invariant mass” M(p+p-)<M(KL) M(p+p-)=M(KL) KL p+ |e|2 = 4 x 10 -6 small, but not 0 q p- p+ M(p+p-)>M(KL) cosq

CP is violated!! James Cronin Val Fitch 1980 Nobel Prize for Physics No prizes

CP is violated!! James Cronin Val Fitch 1980 Nobel Prize for Physics No prizes for Christenson or Turlay

特定 Flavor-non specific K 0 (K 0) decays Decays that are equally likely for

特定 Flavor-non specific K 0 (K 0) decays Decays that are equally likely for K 0 and K 0 0 K + p p K 0 p + p 0 K + p 0 pp K 0 p + p - p 0 çIf you see p+p-, you don’t know if it was from a K 0 or a K 0 çSame for p+p-p 0, (& p 0 p 0 p 0)

特定 Flavor specific 0 K 0 (K ) decays Decays that can only come

特定 Flavor specific 0 K 0 (K ) decays Decays that can only come from a K 0 or K 0, but not both d + d p p u d K 0 W. I. s W+ DS=-1 DQ=-1 0 K p + e n If you see p-e+n, you know it must be from a K 0, not K 0 n K 0 s W. I. W- e+ Rule: only DS=DQ DS=+1 DQ=+1 n e- K 0 p + e - n If you see p+e-n, you know it must be from a K 0, not K 0

K 0 & K 0 in terms of KS & KL inv er t

K 0 & K 0 in terms of KS & KL inv er t

Start with a K 0 at t=0 KS & KL have different t-dependence using

Start with a K 0 at t=0 KS & KL have different t-dependence using and

Similarly:

Similarly:

0 0 K K Expt NA 48 (CERN) Oscillations GS>>GL (GS 500 x. GL)

0 0 K K Expt NA 48 (CERN) Oscillations GS>>GL (GS 500 x. GL) K 0 CP is violated in KL p+e-n/p-e+n decays t=t/g (“proper time”)

Search for direct CPV in KL pp In 2002, after 20 yr searches, NA

Search for direct CPV in KL pp In 2002, after 20 yr searches, NA 48 (CERN) & KTe. V (Fermilab) found direct |DS|=1 CPV in K 2 pp Is this true? Can there be a “direct” CP violation in |DS|=1 K 2 pp? Forbidden(? ) CP violation from |DS|=2 transition Mass Matrix = e’ 1. 6 x 10 -3 Small, but establishes existence of “direct” |DS|=1 CP violation. x e

CPV in neutral K meson system summary • Neutral K mesons mix: K 0

CPV in neutral K meson system summary • Neutral K mesons mix: K 0 • CP is violated in the K 0 -K 0 mass-mixing matrix – scale e 2 x 10 -3 • CPV is seen in flavor non-specific & flavor specific modes – KL pp (CPV e 2 4 x 10 -6) – K L p + e -n / p-e+n (CPV e = 2 x 10 -3) • Direct CP is seen in KL pp decays – scale = e’ = 1. 6 x 10 -3 e

CP is violated in the Weak Interactions Observation of both Mass-Matrix CPV (|DS|=2) &

CP is violated in the Weak Interactions Observation of both Mass-Matrix CPV (|DS|=2) & direct CPV (|DS|=1) rule out theories where CPV comes from a previously unknown “fifth” force characterized by |DS|=2

C P and the forces of Nature Slide from last weak Force Gravity Electro-magnetic

C P and the forces of Nature Slide from last weak Force Gravity Electro-magnetic Strong-nuclear Weak-Interaction C P CP √ √ √ ╳ √ √ √ OK? ╳

Next: • How are CP-violating asymmetries generated in QM? • How does CP violation

Next: • How are CP-violating asymmetries generated in QM? • How does CP violation fit into the Standard Model for particle physics? – Brief review of flavor mixing/GIM-mechanism – Kobayashi 6 -quark model

Generating CPV asymmetries in QM

Generating CPV asymmetries in QM

CP: matter antimatter “charge” CP operator: CP( q g q W )= some basic

CP: matter antimatter “charge” CP operator: CP( q g q W )= some basic process q’ g* q W† mirror For CPV: g g* (charge has to be complex)

QM: processes go as |A|2 • Phases tend to cancel out in rate calculations

QM: processes go as |A|2 • Phases tend to cancel out in rate calculations g*g gg* 2 2 q’ g* = q q J J† mirror even for g* = g (i. e with CPV) matter- antimatter symmetry is ~“automatic”

Phase measurements in QM: need interference 干� • need a process with 2 competing

Phase measurements in QM: need interference 干� • need a process with 2 competing mechanisms: e s a e h p gl an A & Beif: |A+B|2=|A|2+|B|2+2|A|B|cosf • Amplitudes should have similar magnitudes: 2|A|B|cosf |A|2+|B|2 Relative size of the interference effect if |A|>>|B| 2|B| |A| cosf Small number

Even this doesn’t work for CPV!! A+B f B A A+B A |A+B| =

Even this doesn’t work for CPV!! A+B f B A A+B A |A+B| = f B |A+B| l! l i t s matter antimatter symmetric

need a “common phase” d between A & B 合用 same sign eg A=real:

need a “common phase” d between A & B 合用 same sign eg A=real: B = |B|eid+if A+B B A & B = |B|eid-if f A+B d f d A |A+B| = |A+B| matter antimatter difference B

CP violating asymmetries in QM • Even if CP is violated, generating matter-antimatter differences

CP violating asymmetries in QM • Even if CP is violated, generating matter-antimatter differences is hard – need a CP-violating phase (f) – need 2 (or more) interfering amplitudes – + a non-zero “common” phase (d) (often called a “strong” phase)

Common and weak phases “Common” (strong) phase (d): same sign for matter & antimatter

Common and weak phases “Common” (strong) phase (d): same sign for matter & antimatter CP conserving Weak phase (f): opposite sign for matter & antimatter CP violating B = |B|eid-if |B|eid+if A+B B f d A+B A f d B

How does CPV fit into the Standard model? Clue: CPV is seen in strangeness-changing

How does CPV fit into the Standard model? Clue: CPV is seen in strangeness-changing weak decays. It must have something to do with flavor-changing Weak Interactions

Flavor mixing & CP Violation

Flavor mixing & CP Violation

Brief review of weak int’s in the 3 -quark era 1964 --1974 3 quarks:

Brief review of weak int’s in the 3 -quark era 1964 --1974 3 quarks: q=+2/3 |DS|=1 q=-1/3 s 4 leptons: Weak interactions

Problems Problem 1: Different weak interaction “charges” for leptons & hadrons: Fermi Constant d

Problems Problem 1: Different weak interaction “charges” for leptons & hadrons: Fermi Constant d u Gd 0. 98 GF d n m- Gd u GF Kp nm s s u Gs 0. 21 GF Gs u p 0

Cabibbo’s sol’n: flavor mixing Weak Int flavor state Flavor mass eigenstates d = a

Cabibbo’s sol’n: flavor mixing Weak Int flavor state Flavor mass eigenstates d = a d + b s GF d’ u = W- a=cosqc=0. 98 a. GF d b=sinqc=0. 21 u + W- b. GF s u W- Unitarity: |a|2 + |b|2 = 1 a=cos qc; b = sin qc qc=“Cabibbo angle”

Missing neutral currents Problem 2: no flavor-changing Discovered “neutral currents” seen. At CERN GN

Missing neutral currents Problem 2: no flavor-changing Discovered “neutral currents” seen. At CERN GN d, u s d, u K- flavor-preserving neutral currents (e. g. n. N n. X) are allowed d pflavor-changing neutral currents (e. g. K p l+l-) are strongly supressed

GIM sol’n: Introduce 4 th quark 2 quark doublets: charmed quark Weak eigenstates Mass

GIM sol’n: Introduce 4 th quark 2 quark doublets: charmed quark Weak eigenstates Mass eigenstates

d’ & s’ are mixed d & s 4 -quark flavor-mixing matrix Weak eigenstates

d’ & s’ are mixed d & s 4 -quark flavor-mixing matrix Weak eigenstates Mass eigenstates

Mixing matrix must be Unitary UU† = 1 |a|2 + |b|2 = 1 &

Mixing matrix must be Unitary UU† = 1 |a|2 + |b|2 = 1 & a*b - ab* =0

Charged currents (u-quark) |DS|=1 a. GF d(s) GF u(c) W- modified by b. GF

Charged currents (u-quark) |DS|=1 a. GF d(s) GF u(c) W- modified by b. GF s(d) a GF u(c) W- modified by b

Charged currents (c-quark) |DC|=1 |DS|=1 |DC|=1 |DS|=0 -b. GF d GF c W- modified

Charged currents (c-quark) |DC|=1 |DS|=1 |DC|=1 |DS|=0 -b. GF d GF c W- modified by s b a. GF GF c W- modified by a

Flavor preserving Neutral Current 1 = |a|2+|b| 2 G d, (s) =1 OK d,

Flavor preserving Neutral Current 1 = |a|2+|b| 2 G d, (s) =1 OK d, (S) N Z 0 =0 =0 =1 =1 From Unitarity

Flavor changing Neutral Current =0 G (a*b+ba*) N d(s) s(d) Z 0 =0 =1

Flavor changing Neutral Current =0 G (a*b+ba*) N d(s) s(d) Z 0 =0 =1 =0 From FCNC forbidden by Unitarity GIMMechanism

GIM Mechanism FCNC forbidden by Unitarity if quarks come in pairs of 2 GIM:

GIM Mechanism FCNC forbidden by Unitarity if quarks come in pairs of 2 GIM: Glashow Iliopoulis Maiani Glashow won 1979 Physics Nobel prize No prize for Iliopoulis & Maiani

Next Friday: Incorporating CPV into flavor mixing

Next Friday: Incorporating CPV into flavor mixing

Summary Lecture 3 • CP is violated Weak-Interactions – Mass-matrix induced; scale e 2

Summary Lecture 3 • CP is violated Weak-Interactions – Mass-matrix induced; scale e 2 x 10 -3 – Direct CPV; scale = e’ = 1. 6 x 10 -3 e • Observing CPV requires: – Two interfering amplitudes – One with a CP-violating weak phase – Another “common” or “strong” phase • In the W. I. , the d and s quark mix d’ & s’ – d’ =cosqcd +sinq s; s’ =-sinqcd +cosqcs – qc 120 is the “Cabibbo angle • If all quarks are in pairs, FCNC = 0 by Unitarity – (GIM Mechanism)