Section 3 Mixing and CP violation in mostly

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Section 3: : Mixing and CP violation in (mostly) neutral mesons

Section 3: : Mixing and CP violation in (mostly) neutral mesons

State evolution in neutral mesons • Neutral meson states Po, Po – Could be

State evolution in neutral mesons • Neutral meson states Po, Po – Could be Ko, Do, Bo • With internal quantum number F – Such that F=0 emag/strong, F 0 for Hweak • Obeys time dependent Schrödinger eqn M, Hermitian 2 x 2 matrices, mass matrix and decay matrix, H 11=H 22 from CPT (mass/decay particle = antiparticle)

 • Solve Schrödinger for Eigenstates of Hw Complex coeff. p, q obey |q|2+|p|2=1

• Solve Schrödinger for Eigenstates of Hw Complex coeff. p, q obey |q|2+|p|2=1 • From characteristic equation • If E 1=M 1 -i 1/2, E 2= M 2 -i 2/2 and M=M 2 -M 1, = 2 - 1

 • Eigenvector Eqn • Eigenstates have time evolution: • then with

• Eigenvector Eqn • Eigenstates have time evolution: • then with

Finally probabilities… • With Interference term Where = ( 1+ 2)/2 • The oscillations

Finally probabilities… • With Interference term Where = ( 1+ 2)/2 • The oscillations depend upon the parameter x the speed of oscillations c. f. lifetime

Mixing probabilities Probability of finding Po from initial pure Po beam x in Bs

Mixing probabilities Probability of finding Po from initial pure Po beam x in Bs not yet measured >19

Types of CP violation • CP in decay P P f f • CP

Types of CP violation • CP in decay P P f f • CP in mixing P P f • CP in interference between mixing and decay P P P + P f f P + f P f

1) CP Violation in mixing Indirect CP Violation • Mass eigenstates being different from

1) CP Violation in mixing Indirect CP Violation • Mass eigenstates being different from CP eigenstates • Mixing rate Po Po is different to Po Po • If conserved with • If violated CP|P 1> = +1 |P 1> CP|P 2> = -1 |P 2> Such asymmetries usually small Need to calculate M, , involve hadronic uncertainties Hence, tricky to relate to CKM parameters

2) CP Violation in decay direct CP Violation f is final state common to

2) CP Violation in decay direct CP Violation f is final state common to both decays • Two types of phase – Weak phase: due to weak interactions (complex CKM elements) – Strong phase: contribution from intermediate states, CP conserving (same sign in both) occurs for both charged and neutral states P

3)CP violation in the interference of mixing and decay • Choose state* f, Po

3)CP violation in the interference of mixing and decay • Choose state* f, Po f • Two possible decay chains, with or w/o mixing • Interference term depends on Can put and get but • CP can be conserved in mixing and in decay and still be violated ! *Not necessary to be CP eigenstate

Section 4: : Neutral Kaon system

Section 4: : Neutral Kaon system

o K system • Kaon mesons in two isospin doublets Part of pseudo-scalar JP=0

o K system • Kaon mesons in two isospin doublets Part of pseudo-scalar JP=0 - meson octet with , K+ = us I 3=+1/2 K- = us Ko = ds I 3=-1/2 Ko = ds S=+1 S=-1 • Kaon production Ko : - + p o + Ko S 0 0 -1 +1 But from baryon number conservation: Ko : + + p K+ + Ko + p S 0 0 Or +1 -1 0 Ko : - + p o + Ko + n +n S 0 0 +1 -1 0 0 Requires higher energy Much higher

Kaon oscillations d K 0 _ s d _ s s - W W+

Kaon oscillations d K 0 _ s d _ s s - W W+ u, c, t W - u, c, t _ __ u, c, t • So say at t=0, pure Ko, – later a superposition of states u, c, t _ d W+ s_ d 0 K

o K Assume CP Decay show CP=+1 CP=-1 mass eigenstates KS KL • In

o K Assume CP Decay show CP=+1 CP=-1 mass eigenstates KS KL • In that case KS branching fractions: + - 69%, 0 0 31% KL branching fractions: 0 0 0 21%, + - 0 13%, n 66% Ks o o Ks + KL + - o KL o o o CP=+1 CP=-1

Time dependent probabilities for the neutral kaon case. t (1/ +)

Time dependent probabilities for the neutral kaon case. t (1/ +)

o K Regeneration • Start with Pure Ko beam – After time all Ks

o K Regeneration • Start with Pure Ko beam – After time all Ks component decayed • Introduce slab of material in beam – reactions 1) Elastic scatttering 2) Charge exchange 3) Hyperon production • Hence Ko absorbed more strongly i. e. Ks regenerated

Discovery of CP Violation K 1 o o K 1 + - CP=+1 K

Discovery of CP Violation K 1 o o K 1 + - CP=+1 K 2 + - o CP=-1 So if KL =K 1 CP eigenstate, Observe no two pion component K 2 o o o But if broken get: Where quantifies degree of CP violation BUT Can one find KL decaying into + -?

J. H. Christenson et al. , PRL 13, 138 (1964) Discovery of CP violation

J. H. Christenson et al. , PRL 13, 138 (1964) Discovery of CP violation • Mass and angular KL + -+X + -) < m m ( K spectrum p+- = p + + p q = angle between p. KL and p+If X = 0, p+- = p. KL : cos q = 1 If X 0, p+- p. KL : cos q 1 q KL KL m ( + -) = m. K m ( + -) > m. K cos q

So CP symmetry is violated in the neutral kaon system. Mass eigenstates (KS and

So CP symmetry is violated in the neutral kaon system. Mass eigenstates (KS and KL) CP eigenstates Both KS and KL could decay into +- -. • Experimentally well known: The majority of KS decays into +- - and KL into +- -- 0. In KL Small but with profound implications

CPLEAR revisited Initial state at t = 0 S=0 Decay final state at time

CPLEAR revisited Initial state at t = 0 S=0 Decay final state at time t +- - Spin( ) = 0 L - = 0 S=0 CP( +- -) = +1 i. e. CP eigenstate • Tag Ko/Ko from charged pion/kaon K 0 at t = 0 decays into + vs K 0 at t = 0 decays into + - any difference = CP violation

CPLEAR R+-(t) and _ R+-(t) CP violation K 0 _ K 0

CPLEAR R+-(t) and _ R+-(t) CP violation K 0 _ K 0

CPLEAR CP asymmetry _ R+-(t) - R+-(t) A+-(t) = _ R+-(t) + R+-(t) large

CPLEAR CP asymmetry _ R+-(t) - R+-(t) A+-(t) = _ R+-(t) + R+-(t) large difference! • CP violation in mixing • The two mass eigenstates are not CP eigenstates

Kaons: CP violation in Decay CP violation first through existence of certain decay modes

Kaons: CP violation in Decay CP violation first through existence of certain decay modes ~2. 3 x 10 -3 If CP violation is only in mixing, i. e. independent of decay So, put channel independent term and channel dependent ’ Hence, by measuring only rates: get

So, two expts in the 80’s did it: • NA 31 (CERN) • E

So, two expts in the 80’s did it: • NA 31 (CERN) • E 731 (Fermilab) • Ambiguous result! So, two expts did it again…….

NA 48

NA 48

KTe. V

KTe. V

Measure + - and 0 0 at the same time: Normalisation constants NA 31,

Measure + - and 0 0 at the same time: Normalisation constants NA 31, NA 48 KS is regenerated from KL: E 731, KTe. V No normalization is required, but efficiencies, acceptances etc. have to be corrected…

Effort over 30 years! Not easy to compare with SM theory 0. 0050 0.

Effort over 30 years! Not easy to compare with SM theory 0. 0050 0. 0005 0 |h+-| |h 00| e e Note; 3 Re e = |h+-/h 00 | - 1, i. e. Re e 0

CKM parameters with CP conserving parameters • |Vud| : nuclear Beta decay 0. 9734

CKM parameters with CP conserving parameters • |Vud| : nuclear Beta decay 0. 9734 0. 0008 • |Vus| : semileptonic Kaon and hyperon decay (CCFR) 0. 2196 0. 0026 • |Vcd| : Neutrino and anti-neutrino production of charm off valence d quarks 0. 224 0. 016 • |Vcs| : W decays (LEP/me!) 0. 996 0. 013 • |Vcb| : semileptonic inclusive and exclusive B decays (LEP/CLEO) 0. 0412 0. 0020 • |Vub| end point spectrum in semileptonic B decays(LEP/CLEO) 0. 0036 0. 0007 • Bo mixing xd, + lattice gauge inputs |Vtb*Vtd| 0. 0079 0. 0015 • Can use Unitarity constraints