Chem 412 Phys Chem I Sign Convention U
- Slides: 48
Chem. 412 – Phys. Chem. I
Sign Convention Ø ΔU = Internal Energy. Ø q = heat flow; transfer of energy between two objects. Ø w = work; product of force applied to an object over a distance. Surroundings System
Work – Basic Formulation Work Done = Force x (Distance Moved) Differentially => dw = F • d. S
Work – Gas Expansions and Compressions – I (F 14)
Work – Gas Expansions and Compressions – II (F 14)
Work – Gas Expansions and Compressions – III (F 14)
Work – Gas Expansions and Compressions – IV (F 14)
Work – Gas Expansions and Compressions – V (F 14)
Work – Gas Expansions and Compressions – I (F 13) ØWork is area under curve of P-V Diagram. Ø dw = F • d. S = - P • d. V
Work – Gas Expansions and Compressions – II (F 13) ØWork is area under curve of P-V Diagram. Ø dw = F • d. S = - P • d. V
Work – Gas Expansions and Compressions – III (F 13) ØWork is area under curve of P-V Diagram. ØReversible versus Irreversible Work
Work – Gas Expansions and Compressions – IV (F 13) ØWork is area under curve of P-V Diagram. ØReversible versus Irreversible Work
Work – Gas Expansions and Compressions – V (F 13) ØReversible versus Irreversible Work
Tutorial Problem on ‘Work’ Consider one mole of an ideal gas kept in a right-circular cylinder with a movable piston cap at constant temperature. The cap is attached to an external engine that is capable of moving the piston in either directions. (a) Initially, the cylinder has a volume of 1. 0 m 3 at a pressure of 10. Pa. The cap was moved to give a final pressure of 1. 0 Pa. In this case, the piston cap was moved at an infinitely slow rate to achieve this final pressure, thereby following the ideal gas law. Calculate the work involved in this process. This work is referred to as reversible work, wrev. [ 23 J ] (b) The initial and final volume/pressure was kept the same as in part (a) but the piston cap was suddenly released to get to the final pressure value. Calculate the work involved in this process. This work is referred to as irreversible work, wirrev. [ 9 J ] (c) Draw one P-V diagram for parts (a) and (b). (d) Repeat parts (a), (b), and (c) by reversing the initial and final volume/pressure conditions; that is, compression instead of expansion. [ 23 J, 90 J ] (e) Compare/Contrast/Discuss the above results.
First Law of Thermodynamics
First Law of Thermodynamics Ø U = Internal Energy = Heat Flow under Constant Volume Ø H = Enthalpy = Heat Flow under Constant Pressure Ø H = U + PV
Two Heat Capacities from q
Calorimetry Bomb Calorimetry (Constant Volume Calorimetry) • Reaction carried out under constant volume. • Use a bomb calorimeter. • Usually study combustion.
Calorimetry Constant Pressure (Solution) Calorimetry • Atmospheric pressure is constant!
Calorimetry Constant Pressure Calorimetry
Calorimetry Examples Cyber. Chem video 1. In an experiment similar to the procedure set out for Part (A) of the Calorimetry experiment, 1. 500 g of Mg(s) was combined with 125. 0 m. L of 1. 0 M HCl. The initial temperature was 25. 0 o. C and the final temperature was 72. 3 o. C. Calculate: (a) the heat involved in the reaction and (b) the enthalpy of reaction in terms of the number of moles of Mg(s) used. Ans: (a) – 25. 0 k. J (b) – 406 k. J/mol 2. 50. 0 m. L of 1. 0 M HCl at 25. 0 o. C were mixed with 50. 0 m. L of 1. 0 M Na. OH also at 25. 0 o. C in a styrofoam cup calorimeter. After the mixing process, thermometer reading was at 31. 9 o. C. Calculate the energy involved in the reaction and the enthalpy per moles of hydrogen ions used. Ans: -2. 9 k. J , -58 k. J/mol [heat of neutralization for strong acid/base reactions]
Calorimetry Examples: Hints 50. 0 m. L of 1. 0 M HCl at 25. 0 o. C were mixed with 50. 0 m. L of 1. 0 M Na. OH also at 25. 0 o. C in a styrofoam cup calorimeter. After the mixing process, thermometer reading was at 31. 9 o. C. Calculate the energy involved in the reaction and the enthalpy per moles of hydrogen ions used. Ans: -2. 9 k. J , -58 k. J/mol [heat of neutralization for strong acid/base reactions]
Comparison of Heat Capacities: CP vs. CV
Comparison of Heat Capacities: CP vs. CV
Comparison of Heat Capacities: CP vs. CV (F 08)
Example on State and Path Functions 20. 0 grams of Argon gas was heated from 20. 0 o. C to 80. 0 o. C. Considering Argon behaving as an ideal gas, calculate q, w, U, and H for the following processes: (a) under Constant Volume, and (b) under Constant Pressure.
Constant Volume Constant Pressure q 374 J 623 J q w 0 -249 J w U 374 J U H 623 J H CVm 12. 5 J mol-1 K-1 20. 8 J mol-1 K-1 CPm
Enthalpy of Phase Transitions Constant P: s g
Enthalpy of Phase Transitions
Relating Urxn and Hrxn
Hess’s Law • Hess’s law: if a reaction is carried out in a number of steps, H for the overall reaction is the sum of H for each individual step. • For example: CH 4(g) + 2 O 2(g) CO 2(g) + 2 H 2 O(g) H = -802 k. J 2 H 2 O(g) 2 H 2 O(l) H = -88 k. J CH 4(g) + 2 O 2(g) CO 2(g) + 2 H 2 O(l) H = -890 k. J
Hess’s Law Given: (i) (ii) Fe 2 O 3(s) + 3 CO(g) 2 Fe(s) + 3 CO 2(g) CO(g) + ½O 2(g) CO 2(g) Calculate the heat of reaction for: ∆H = -26. 7 k. J/mol ∆H = -283. 0 k. J/mol 2 Fe(s) + 3/2 O 2(g) Fe 2 O 3(s) Ans: -822. 3 k. J/mol
Enthalpies of Formation If 1 mol of compound is formed from its constituent elements (standard state), then the enthalpy change for the reaction is called the enthalpy of formation, Hof. • Standard conditions (standard state): Most stable form of the substance at 1 atm and 25. 00 o. C (298. 15 K). • Standard enthalpy, Ho, is the enthalpy measured when everything is in its standard state. • Standard enthalpy of formation: 1 mol of compound is formed from substances in their standard states. • Standard enthalpy of formation of the most stable form of an element is zero.
Enthalpies of Formation: Example: Write the balanced reaction equation for the standard enthalpy of formation of solid ammonium carbonate.
Enthalpies of Formation Substance Hof (k. J/mol) C(s, graphite) 0 O(g) 247. 5 O 2(g) 0 N 2(g) 0
Bucky Ball drawn by Hyper. Chem
Enthalpies of Formation Using Enthalpies of Formation to Calculate Enthalpies of Reaction • For a reaction • Calculate/Compare heat of reactions for the combustion of methanol gas and ethanol gas giving carbon dioxide and water.
Temperature Dependence of CP and Hrxn
Temperature Dependence of CP and Hrxn Example: Find the heat of reaction for the following reaction at 1000. K ( Horxn, 1000 K ? ) Na. Cl(s) Na(g) + ½ Cl 2(g) [ Given: Horxn, 298 K = 519. 23 k. J ] Species CP / J K-1 mol-1 Na(g) 20. 80 Na. Cl(s) 49. 70 Cl 2(g) 31. 70 + 10. 14 x 10 -3 T – 2. 72 x 10 -7 T 2
- All the signs for driving
- Max shearing stress formula
- Torsional shear stress formula
- Lens sign convention
- Sfd bmd examples
- Concave mirror sign convention
- Sign convention for vectors
- Sign convention for lens
- Passive sign convention definition
- Passive sign convention examples
- Chegg
- Sign convention for lenses in tabular form
- Sign convention table for mirrors and lenses
- Passive sign convention
- Loop law sign convention
- The new cartesian sign convention for spherical mirrors
- First law of thermodynamics sign convention
- Reflection of light by spherical mirror
- Sfd bmd
- Sign convention of ampere's circuital law
- Sign convention for lenses in tabular form
- Shoreline school district 412
- Easy 412-ac-rc
- Resolucion 412 de 2000
- Friday 412
- Cse 412
- Ertugrul 412
- Factors of 412
- Phonak supero 412
- Kj 412
- Ekyros.com
- Complex data types in data mining
- Ertugrul 412
- The preterite of hacer and dar (p. 412)
- Cs 412
- P-fet short 412
- Cmsc412
- 5 cfr 412
- Cmput 412
- Problem
- Tum-412
- Ertugrul 412
- Mykrispykreme.com
- Chvostek sign
- When the signs are the same,
- Chvostek sign trousseau sign
- Asystomatic
- Kernig's sign
- Hydr root words