Thermodynamics Energy is neither created or destroyed during

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Thermodynamics

Thermodynamics

Energy is neither created or destroyed during chemical or physical changes, but it is

Energy is neither created or destroyed during chemical or physical changes, but it is transformed from one form to another. Euniverse = 0

TYPES of ENERGY Kinetic Mechanical Thermal Electrical Radiant Energy Conversion Examples: 1. dropping a

TYPES of ENERGY Kinetic Mechanical Thermal Electrical Radiant Energy Conversion Examples: 1. dropping a rock 2. using a flashlight 3. driving a car Potential Gravitational Electrostatic Chemical

SYSTEMS and SURROUNDINGS System: The thing under study Surroundings: Everything else in the universe

SYSTEMS and SURROUNDINGS System: The thing under study Surroundings: Everything else in the universe Energy transfer between system and surroundings: Endo: heat added to system Exo: heat released by system

HEAT: What happens to thermal (heat) energy? Three possibilities: • Warms another object •

HEAT: What happens to thermal (heat) energy? Three possibilities: • Warms another object • Causes a change of state • Is used in an endothermic reaction

Temperature Changes from Heat Exchange Example 1: 5 g wood at 0 o. C

Temperature Changes from Heat Exchange Example 1: 5 g wood at 0 o. C Example 2: 10 g wood at 0 o. C Example 3: 5 g copper at 0 o. C Example 4: 5 g wood at 0 o. C Choices: 1: 0 o. C 2: 33 o. C 3: 50 o. C + + 5 g wood at 100 o. C 5 g copper at 100 o. C 4. 67 o. C 5: 100 o. C 6: other

What happens to thermal (heat) energy? When objects of different temperature meet: • Warmer

What happens to thermal (heat) energy? When objects of different temperature meet: • Warmer object cools • Cooler object warms • Thermal energy is transferred • qwarmer = -qcooler

Quantitative: Calculating Heat Exchange: Specific Heat Capacity

Quantitative: Calculating Heat Exchange: Specific Heat Capacity

Specific Heat Capacity The energy required to heat one gram of a substance by

Specific Heat Capacity The energy required to heat one gram of a substance by 1 o. C. Usefulness: #J transferred = S. H. x #g x T How much energy is used to heat 250 g water from 17 o. C to 100 o. C?

What happens to thermal (heat) energy? When objects of different temperature meet: • Warmer

What happens to thermal (heat) energy? When objects of different temperature meet: • Warmer object cools • Cooler object warms • Thermal energy is transferred • qwarmer = -qcooler specific heat x mass x T = specific heat x mass x T warmer object cooler object

Heat transfer between substances: Specific heats: Cu = 0. 385 J/g o. C Wood

Heat transfer between substances: Specific heats: Cu = 0. 385 J/g o. C Wood = 1. 8 J/g o. C

Conceptually Easy Example with Annoying Algebra: If we mix 250 g H 2 O

Conceptually Easy Example with Annoying Algebra: If we mix 250 g H 2 O at 95 o. C with 50 g H 2 O at 5 o. C, what will the final temperature be?

Thermal Energy and Phase Changes First: What happens?

Thermal Energy and Phase Changes First: What happens?

Thermal Energy and Phase Changes First: What happens?

Thermal Energy and Phase Changes First: What happens?

Thermal Energy and Phase Changes First: What happens?

Thermal Energy and Phase Changes First: What happens?

But what’s really happening? Warming: • Molecules move more rapidly • Kinetic Energy increases

But what’s really happening? Warming: • Molecules move more rapidly • Kinetic Energy increases • Temperature increases Melting/Boiling: • Molecules do NOT move more rapidly • Temperature remains constant • Intermolecular bonds are broken • Chemical potential energy (enthalpy) increases

Energy and Phase Changes: Quantitative Treatment Melting: Heat of Fusion (DHfus) for Water: 333

Energy and Phase Changes: Quantitative Treatment Melting: Heat of Fusion (DHfus) for Water: 333 J/g Boiling: Heat of Vaporization (DHvap) for Water: 2256 J/g

Total Quantitative Analysis Convert 40. 0 g of ice at – 30 o. C

Total Quantitative Analysis Convert 40. 0 g of ice at – 30 o. C to steam at 125 o. C Warm ice: (Specific heat = 2. 06 J/g-o. C) Melt ice: Warm water (s. h. = 4. 18 J/g-o. C)

Total Quantitative Analysis Convert 40. 0 g of ice at – 30 o. C

Total Quantitative Analysis Convert 40. 0 g of ice at – 30 o. C to steam at 125 o. C Boil water: Warm steam (s. h. = 1. 92 J/g-o. C)

Energy and Chemical Reactions Lots of different types of energy. We use Enthalpy: Heat

Energy and Chemical Reactions Lots of different types of energy. We use Enthalpy: Heat exchanged under constant pressure.

Energy/Enthalpy Diagrams

Energy/Enthalpy Diagrams

Some Examples of Enthalpy Change 2 C(s) + 2 H 2(g) C 2 H

Some Examples of Enthalpy Change 2 C(s) + 2 H 2(g) C 2 H 4(g) H = +52 k. J

Enthalpy Change and Chemical Reactions H is usually more complicated, due to solvent and

Enthalpy Change and Chemical Reactions H is usually more complicated, due to solvent and solid interactions. So, we measure H experimentally. Calorimetry Run reaction in a way that the heat exchanged can be measured. Use a “calorimeter. ”

Bomb Calorimetry Experiment N 2 H 4 + 3 O 2 2 NO 2

Bomb Calorimetry Experiment N 2 H 4 + 3 O 2 2 NO 2 + 2 H 2 O Energy released = E absorbed by water + E absorbed by calorimeter Ewater = Ecalorimeter = Total E = H = energy/moles = 0. 500 g N 2 H 4 600 g water 420 J/o. C

Enthalpy Change and Bond Energies H = energy needed to break bonds – energy

Enthalpy Change and Bond Energies H = energy needed to break bonds – energy released forming bonds Example: formation of water: H = [498 + (2 x 436)] – [4 x 436] k. J = -482 k. J

General Rule:

General Rule:

SO 2 + ½ O 2 SO 3 d. H = -98. 9 k.

SO 2 + ½ O 2 SO 3 d. H = -98. 9 k. J 2 SO 3 2 SO 2 + O 2 d. H = ?

Hess’s Law Enthalpy is a State Function.

Hess’s Law Enthalpy is a State Function.

Thermochemistry Lab Calculations Goal: What is H for the formation of Mg. O from

Thermochemistry Lab Calculations Goal: What is H for the formation of Mg. O from Mg(s) and O 2(g)? Mg(s) + ½ O 2(g) Mg. O(s) Data: From lab measurements: H = ? k. J/mol Mg(s) + 2 H+(aq) Mg 2+(aq) + H 2(g) H 1 = ______ k. J/mol Mg. O(s) + 2 H+(aq) Mg 2+(aq) + H 2 O(l) H 2 = ______ k. J/mol From a table: H 2(g) + ½ O 2(g) H 2 O(l) H 3 = -285. 8 k. J/mol Task: Find a way to add these three reactions to get the desired reaction. Manipulate the H values as needed, and add them.

Calculating Heat Production

Calculating Heat Production

Heat of Formation

Heat of Formation

Heat of Formation: The general idea

Heat of Formation: The general idea

Find the enthalpy change for burning ethyl alcohol

Find the enthalpy change for burning ethyl alcohol