Homework 4 due today Homework 5 posted and

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Homework 4 due today Homework 5 posted and due this Friday It’s hump day

Homework 4 due today Homework 5 posted and due this Friday It’s hump day !!! Two days till the 3 rd week is over !!

Homework 4… • another look at prefix assignment • Boo boos in naming

Homework 4… • another look at prefix assignment • Boo boos in naming

metals Naming Inorganic compounds: in-class practicing Non-metals Transition metals Lanthanides Actinides

metals Naming Inorganic compounds: in-class practicing Non-metals Transition metals Lanthanides Actinides

ATOMIC BOOKKEEPING (cont. ) Brain toss variant…. Atomic # 10 7 26 17 mass#

ATOMIC BOOKKEEPING (cont. ) Brain toss variant…. Atomic # 10 7 26 17 mass# 20 14 56 35 symbol #p+ #no #e- atom charge 10 0 Ne 10 10 N 7 7 * 8 -1 26 30 26 0 17 18 19 Fe Cl Let’s go down a column left to right…. 1 mole buck/right answer with explanation -2

Chemist’s C Isotopic C (12 C)

Chemist’s C Isotopic C (12 C)

Why the Chemist’s C lists 12. 01 and not 12 Imagine `fishing’ out 100

Why the Chemist’s C lists 12. 01 and not 12 Imagine `fishing’ out 100 atoms of Carbon from a sample of graphite (pure carbon). What would you catch ?

The carbon atom `catch: ’ #p #n mass # caught out of 100 C

The carbon atom `catch: ’ #p #n mass # caught out of 100 C atoms 6 6 6 12 99 Both kinds isotopes of C 7 13 1 act exactly the same, chemically so chemists just average the masses Average mass of each C=99*12 + 1*13 = 12. 01 100

Averages Written As Sums Of Fractional Contributions 99*12 + 1*13 = 12. 01 100

Averages Written As Sums Of Fractional Contributions 99*12 + 1*13 = 12. 01 100 = 99 *12 + 1 * 13 100 Average mass = of each C fm = fraction of C atoms with mass M =f 12*12 + f 13*13

Averages written as sums of % contributions Average mass = 99 of each C

Averages written as sums of % contributions Average mass = 99 of each C *12 100 + 1 * 13 100 =(99 % *12 + 1% * 13) 100 Pm = % of C atoms with = (P *12 + P *13) 12 13 mass M 100

Take home lesson : Average mass is computable from fractional abundances fk and mk

Take home lesson : Average mass is computable from fractional abundances fk and mk so: AV. MASS =f 1*m 1+f 2*m 2 +…. . Or, from % abundances Pk and mk so: AV. MASS =P 1*m 1+P 2*m 2 +…. . 100

`U-Do-it’ Example: Boron Isotope 11 B 10 B P= % abundance 81% 19% Average

`U-Do-it’ Example: Boron Isotope 11 B 10 B P= % abundance 81% 19% Average B mass ? ? ? AV. MASS =P 1*m 1+P 2*m 2 +…. . 100 =81*11 + 19*10 100 =10. 81

estimate average atomic masses for elements below (Note that even isotope masses are not

estimate average atomic masses for elements below (Note that even isotope masses are not even. Neutron actually weighs a little more than proton…. reflects E=mc 2 !!) Isotope ~mass 1 H 1. 008 2 H 2. 014 28 Si 29 Si 30 Si 35 Cl 37 Cl 27. 98 28. 98 29. 97 34. 97 36. 97 % abundance ~ average mass 99. 985 1. 008 0. 015 92. 2 4. 8 3. 0 75. 8 24. 2 28. 081 35. 454

Need more, or are you exhausted ? ? ?

Need more, or are you exhausted ? ? ?

In- class example with mercury: Compute the average mass of Hg from abundance data

In- class example with mercury: Compute the average mass of Hg from abundance data #p #n 80 ~Isotope Pk mass, mk 118 198 9. 5 mk *Pk 80 119 199 15. 8 3144 80 120 200 28. 6 5720 80 121 201 12. 4 80 122 202 27. 5 2492 5555 80 124 204 6. 2 1246 1881 Sum= 20057

AV. MASS =P 1*m 1+P 2*m 2 +…. . 100 ÞAverage mass of Hg

AV. MASS =P 1*m 1+P 2*m 2 +…. . 100 ÞAverage mass of Hg =20057 =200. 57 100

Chapter 3: MOLES- Every science involves counting Astronomers count …… Animal biologists count …

Chapter 3: MOLES- Every science involves counting Astronomers count …… Animal biologists count … Bacteriologists count. . . Chemists count…….

Astronomers can see…. Animal biologists can see … Bacteriologists can see… Chemists can’t see….

Astronomers can see…. Animal biologists can see … Bacteriologists can see… Chemists can’t see…. molecules

Even worse news…even if we could see molecules…guess long would it take to count

Even worse news…even if we could see molecules…guess long would it take to count the number of water molecules in a tea cup ? ?

Let’s use the Chinese Tihane-2 computer (world’s current fastest computer) to count all the

Let’s use the Chinese Tihane-2 computer (world’s current fastest computer) to count all the molecules of water in a teacup assuming it counted at its maximum processor rate = 34, 000, 000 molecules/second (=3400 THz=3. 4*106 GHz 1 ) ? How long would it take to count them all ? Answer: ~ 3. 2 years 1 ~ 1 million times faster than a typical laptop (It houses 3 million processors in parallel)

From your lecture syllabus…. Student Learning Outcome 5 Students should be able to perform

From your lecture syllabus…. Student Learning Outcome 5 Students should be able to perform basic chemical calculations connected to: • • • mole-weight-count conversions reaction stoichiometry limiting yields. Translation: How do chemists count atoms and molecules without actually having to count them ? ? ?

Chemists count atoms and molecules using… Moles

Chemists count atoms and molecules using… Moles

A trip to Mole land Moles connect the atomic world to human world ~

A trip to Mole land Moles connect the atomic world to human world ~ 1027 molecules in the shape of a couch potato ~0. 00000002 m ~30 CO 2 ~2 m ØMoles allow us to molecules conveniently connect between arranged in shape of muffin these worlds using a scale. man (IBM)

The mole: starting definitions What is a chemical mole ? The classic textbook rant…….

The mole: starting definitions What is a chemical mole ? The classic textbook rant……. (but not your text’s rant, fortunately) • # • atoms in 12. 000 g of 12 C 6. 0221335 *1023 atoms (Avogadro’s Number) …Not that helpful when first starting out…

A better beginning: the mole concept is really … the same idea as a

A better beginning: the mole concept is really … the same idea as a `dozen. ’

IN-CLASS EGG CALCULATIONS

IN-CLASS EGG CALCULATIONS

EGG WORLD CHEMISTRY WORLD Smallest unit 1 egg Practical Dozen Counting unit 1 molecule

EGG WORLD CHEMISTRY WORLD Smallest unit 1 egg Practical Dozen Counting unit 1 molecule Mole (The chemist’s dozen)

Eggs vs. chemistry world (continued) EGG WORLD CHEMISTRY WORLD # units in practical 1

Eggs vs. chemistry world (continued) EGG WORLD CHEMISTRY WORLD # units in practical 1 dozen=12 counting unit 1 mole 6. 022 *1023 Practical grams/dozen mass unit (WEIGH) grams/mole =gram molecular weight = MW (molecular weight) (ADD) (Avogadro’s #)

THE ONE PLACE EGG WORLD AND CHEMISTRY WORLD DEVIATE A TEENY BIT: Egg world

THE ONE PLACE EGG WORLD AND CHEMISTRY WORLD DEVIATE A TEENY BIT: Egg world Mass dozen Must weigh box of eggs Chemistry world Mass = molecular weight mol (MW) Just add up atomic masses using Periodic Table in grams

Mass (grams) = MW=Molecular mol Weight = sum of masses in grams of component

Mass (grams) = MW=Molecular mol Weight = sum of masses in grams of component elements in a compound. (element masses are average masses taken from Periodic Table)

Example of MW Calculation: What is the MW of methane =CH 4 ? ?

Example of MW Calculation: What is the MW of methane =CH 4 ? ? atomic mass (Table) # atoms/molecule C 12. 011~12 H 1. 00794~1 1 4 product ~12*1=12 ~1*4 = 4 Sum = MW = 12+4=16 g/mole

In – class exercise on Molecular Weight (MW) calculations Find the MW of… H

In – class exercise on Molecular Weight (MW) calculations Find the MW of… H 2 SO 4 2*1 + 1*32 + 4*16 = 98 g/mol

In – class exercise on Molecular Weight (MW) calculations (continued) Find the MW of…

In – class exercise on Molecular Weight (MW) calculations (continued) Find the MW of… Ca. Cl 2 1*40 + 2*35. 4 = 110. 4 g/mol

In – class exercise on Molecular Weight (MW) calculations (continued) Find the MW of…

In – class exercise on Molecular Weight (MW) calculations (continued) Find the MW of… Cu 3(PO 4)2 3*63. 5 + 2*(1*31 +4*16) = 380. 5 g/mol

In – class exercise on Molecular Weight (MW) calculations (continued) Find the MW of…

In – class exercise on Molecular Weight (MW) calculations (continued) Find the MW of… Ca. Cl 2*2 H 2 O 2 `waters of hydration’ per Ca. Cl 2 1*40 + 2*35. 4 + 2*(2*1 + 1*16) =146. 8 g/mol

IN-CLASS simple mole calculations (on board) the dozen method way

IN-CLASS simple mole calculations (on board) the dozen method way

The triangle `trick’ for those allergic to eggs Multiply Down Moles (n) MW ALL

The triangle `trick’ for those allergic to eggs Multiply Down Moles (n) MW ALL ROADS LEAD THROUGH MOLES Weight (w) 23 6. 0*10 molecule count (N) Divide up

the dozen concept is really the triangle trick Given 6000 g of eggs= ?

the dozen concept is really the triangle trick Given 6000 g of eggs= ? ? dozens 6 # of dozens 1000 g 1 dozen eggs 12 eggs in a dozen # of eggs (count) Weight of eggs 6000 grams DIVIDE UP: 6000/1000=6

the dozen concept is really the triangle trick Given 6000 g of eggs= ?

the dozen concept is really the triangle trick Given 6000 g of eggs= ? ? # eggs ? 6 Multiply down # of dozens 1000 g 1 dozen eggs Weight of eggs 6000 grams 6*12=72 12 eggs in a dozen # of eggs (count) 72 g

On the triangle…, . DIVIDE UP MULTIPLY DOWN

On the triangle…, . DIVIDE UP MULTIPLY DOWN

mole math the triangle way You always get MW and Avogadro’s # = 6.

mole math the triangle way You always get MW and Avogadro’s # = 6. 02*1023 w= n x MW Weight (w) Moles (n) N= n*6. 02*1023 If you have moles they multiply !! (because… moles breed whenever they can) Molecule count (N)

reverse mole math the triangle way n= w MW Weight (w) Moles (n) If

reverse mole math the triangle way n= w MW Weight (w) Moles (n) If you want moles n= N 6. 02*1023 Molecule count (N) …don’t let these horny critters multiply…divide them up!!!

Trips around the triangle: N w Given: 100 g/mol =MW w= n*MW = 20

Trips around the triangle: N w Given: 100 g/mol =MW w= n*MW = 20 * 100 6. 02*1023 Weight (w) ? w~3. 3*10 -21 g Given: chemist’s dozen =1 mol count=6. 02*1023 Moles (n) All roads lead through moles n= 20 6. 02*1023 Given molecule count N=20

Trips around the triangle: w N Given : chemist’s dozen =1 mol count=6. 02*1023

Trips around the triangle: w N Given : chemist’s dozen =1 mol count=6. 02*1023 Given: 100 g/mol =MW n= w = 200 MW 100 Moles (n) N=n x 6. 02*1023 =200 All roads lead through moles Given weight w=200 g x 6. 02*1023 100 Molecule count N ? N=1. 2*1024

IN-CLASS simple mole calculations (on board) the triangle trick way

IN-CLASS simple mole calculations (on board) the triangle trick way

AN ANECDOTE An `out-of-towner’ visiting NYC for the first time asks Joshua Bell (world’s

AN ANECDOTE An `out-of-towner’ visiting NYC for the first time asks Joshua Bell (world’s greatest violinist): “How do you get to the Lincoln Center for the Performing Arts ? ” Joshua’s answer (supposedly): “Practice, practice, practice…. ”