Homework 8 due Today Homework 9 posted and

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Homework 8: due Today Homework 9 posted and due Monday 4/2

Homework 8: due Today Homework 9 posted and due Monday 4/2

Cut and try approach example #3: mixed grams C 12 H 22 O 11

Cut and try approach example #3: mixed grams C 12 H 22 O 11 + 12 O 2 ---- 12 CO 2 MW 342 g/mol 32 g/mol 44 g/mol 1*1023 molecules 72. 73 g ? ? g + 11 H 2 O 18 g/mol How many grams of CO 2 will be produced if 1023 molecules of sucrose, C 12 H 22 O 11, are combined with 72. 73 grams of O 2 according to the balanced equation above? 88 g CO 2 (sucrose limits)

2 C 8 H 18 + 25 O 2 ---- 16 CO 2 +

2 C 8 H 18 + 25 O 2 ---- 16 CO 2 + 18 H 2 O MW 114 g/mol 32 g/mol 44 g/mol 18 g/mol 1. 7051022 molecules 1. 136 g ? ? g Given 1. 705*1022 molecules of C 8 H 18 and 1. 136 g O 2, how many grams of CO 2 form ? A. 10. 0 g B. 1. 0 g C. 0. 11 g D. 1. 56 g

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% Yield: a non-chemical analogy Billy comes home with his math test. He got

% Yield: a non-chemical analogy Billy comes home with his math test. He got 40 out of 75 questions right. Did he `pass’ the test ? Test Score = Test Yield = 100* 40 =53. 3% 75

Examples of chemical % yield 5 O 2 + C 3 H 8 Given

Examples of chemical % yield 5 O 2 + C 3 H 8 Given mol excess 3 CO 2 + 4 H 2 O 0. 25 Theory product mol 4 x 0. 25 =1 (theory=max) 1 0. 7 (obs) Exp. Product mol 0. 7 % yield =exp. mol x 100 = 0. 7 x 100 theory mol 1 = 70%

Examples of chemical % yield (continued) 5 O 2 + C 3 H 8

Examples of chemical % yield (continued) 5 O 2 + C 3 H 8 3 CO 2 + 4 H 2 O MW 32 44 44 18 Given excess 1. 1 g 0. 5 g Exp. Mol CO 2 Mol C 3 H 8 = 1. 1=0. 025 = 0. 01136 44 44 Product CO 2 = 3 x 0. 025 =0. 075 moles theory 1 % yield = 100 * Exp Mol =0. 01136 x 100% =15. 1% Theory Mol 0. 075

Examples of chemical % yield (continued) Bob reports making 4. 0 g H 2

Examples of chemical % yield (continued) Bob reports making 4. 0 g H 2 O from 2. 2 g C 3 H 8. Is Bob crazy or okay ? 5 O 2 + C 3 H 8 3 CO 2 + 4 H 2 O MW 32 44 Given excess 2. 2 g 44 18 Bob Reports 4. 0 g H 2 O Mol C 3 H 8 =2. 2 =0. 050 44 Product H 2 O = 4 x 0. 05 =0. 2 moles theory 1 Maximum g H 2 O=18 g/mol*0. 2 mol=3. 6 g Bob’s an idiot

MW 16 32 18 CH 4 + 2 O 2 CO 2 + 2

MW 16 32 18 CH 4 + 2 O 2 CO 2 + 2 H 2 O A 1 g sample of methane (CH 4) is burned in excess O 2 according to the equation above. You collect 1. 125 g of H 2 O. What is your % yield ? A. 50% B. 89 % C. 25 % D. 100% E. I have no idea

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Need more practice ? ?

Where we are on the mole road trip…. We is done with moles !!!

Where we are on the mole road trip…. We is done with moles !!!

And now, after many weeks of &^%!! Moles …. for something completely different…. CLASSICAL

And now, after many weeks of &^%!! Moles …. for something completely different…. CLASSICAL REACTIONs

Today’s Student Learning Objective (SLO): SLO #6 Students will be able to: write, balance,

Today’s Student Learning Objective (SLO): SLO #6 Students will be able to: write, balance, identify and predict common reaction classes (metatheses, acidbase, redox). Translation: What happens when I add this to that ?

CLASSICAL REACTIONs (continued) What to read… chapter 4 ( + a bit of Ch.

CLASSICAL REACTIONs (continued) What to read… chapter 4 ( + a bit of Ch. 14) üMetatheses 131 -140 üAcid-base 140 -147; 549 -552 üOxidation-reduction 147 -159

Classical Reactions 1) Metathesis (double replacement) Complete Molecular reaction Pb(NO 3)2 (aq) + 2

Classical Reactions 1) Metathesis (double replacement) Complete Molecular reaction Pb(NO 3)2 (aq) + 2 KI(aq) Pb. I 2(s) + 2 KNO 3(aq) Complete Ionic Reaction Pb 2+ +2 NO 3 - +2 K+ +2 I- Pb. I 2(s) + 2 K+ +2 NO 3 - Net Ionic Reaction Pb 2+ + 2 I- Pb. I 2(s) METATHESIS REACTIONS (Two labs ago)