Electrostatic fields Sandra CruzPol Ph D INEL 4151
- Slides: 40
Electrostatic fields Sandra Cruz-Pol, Ph. D. INEL 4151 ECE UPRM Mayagüez, PR
Some applications n n n n Power transmission, X rays, lightning protection Solid-state Electronics: resistors, capacitors, FET Computer peripherals: touch pads, LCD, CRT Medicine: electrocardiograms, electroencephalograms, monitoring eye activity Agriculture: seed sorting, moisture content monitoring, spinning cotton, … Art: spray painting …
We will study Electric charges: n Coulomb's Law n Gauss’s Law
Coulomb’s Law (1785) n Force one charge exerts on another Point charges + where k= 9 x 109 or k = 1/4 peo R + *Superposition applies
Force with direction
Example: Point charges 5 n. C and -2 n. C are located at r 1=(2, 0, 4) and r 2=(-3, 0, 5), respectively. a) Find the force on a 1 n. C point charge, Qx, located at (1, -3, 7) b) Apply superposition:
Electric field intensity n Is the force per unit charge when placed in the E field Example: Point charges 5 n. C and 2 n. C are located at (2, 0, 4) and (3, 0, 5), respectively. b) Find the E field at rx=(1, -3, 7).
If we have many charges Line charge density, C/m r. L Surface charge density C/m 2 r. S Volume charge density rv C/m 3
The total E-field intensity is
Find E from LINE charge z (x, y, z) T a B R (0, 0, z’) n x dl Line charge w/uniform A charge density, r. L 0 d. E
LINE charge z (x, y, z) T a B R (0, 0, z’) n x dl Substituting in: A 0 d. E
More Charge distributions Point charge n Line charge n Surface charge n Volume charge n
Find E from Surface charge z y n Sheet of charge w/uniform density r. S
SURFACE charge Due to SYMMETRY the r component cancels out. n
More Charge distributions Point charge n Line charge n Surface charge n Volume charge n
Find E from Volume charge P(0, 0, z) d. E a (Eq. *) (r’, q’, f’ rv n x q’ f’ ) Differentiating (Eq. *) sphere of charge w/uniform density, rv
Find E from Volume charge P(0, 0, z) d. E (r’, q’, f’ rv q’ ) f’ x n Substituting… De donde salen los limites de R?
P. E. 4. 5 n A square plate at plane z=0 and carries a charge m. C/m 2. Find the total charge on the plate and the electric field intensity at (0, 0, 10).
z of Cont…sheet charge y=2 x=2 Due to symmetry only Ez survives:
Electric Flux Density D is independent of the medium in which the charge is placed.
Gauss’s Law
Gauss’s Law n The total electric flux Y, through any closed surface is equal to the total charge enclosed by that surface.
n Point Charge is at the origin. n Choose a spherical d. S Note where D is perpendicular to this surface. Some examples: Finding D at point P from the charges: D n P r charge
Some examples: Finding D at point P from the charges: Line charge D r P n Infinite Line Charge n Choose a cylindrical d. S Note that integral =0 at top and bottom surfaces of cylinder n
Some examples: Find D at point P from the charges: n Infinite Sheet of charge n Choose a cylindrical box cutting the sheet D sheet of charge Area A D Note that D is parallel to the sides of the box.
P. E. 4. 7 plane y=3 carries charge 10 n. C/m 2. Find D at (0, 4, 3)
P. E. 4. 8 If n C/m 2. Find : volume charge density at (-1, 0, 3) n Flux thru the cube defined by n Total charge enclosed by the cube
Review Point charge or volume Charge distribution Line charge distribution Sheet charge distribution
We will study Electric charges: n Coulomb's Law (general cases) n Gauss’s Law (symmetrical cases) n Electric Potential vectors) (uses scalar, not
Electric Potential, V n The work done to move a charge Q from A to B is n The (-) means the work is done by an external force. The total work= potential energy required in moving Q: n n The energy per unit charge= potential difference between the 2 points: V is independent of the path taken.
The Potential at any point is the potential difference between that point and a chosen reference point at which the potential is zero. (choosing infinity): For many Point charges at rk: (apply superposition) For Line Charges: For Surface charges: For Volume charges:
P. E. 4. 10 A point charge of -4 m. C is located at (2, -1, 3) A point charge of 5 m. C is located at (0, 4, -2) A point charge of 3 m. C is located at the origin Assume V(∞)=0 and Find the potential at (-1, 5, 2) =10. 23 k. V
A line charge of 5 n. C/m is located on line x=10, y=20 Example Assume V(0, 0, 0)=0 and Find the potential at A(3, 0, 5) VA=+4. 8 V r 0=|(0, 0, 0)-(10, 20, 0)|=22. 36 and r. A=|(3, 0, 5)-(10, 20, 0)|= 21. 2
A point charge of 5 n. C is located at the origin V(0, 6, -8)=2 V and Find the potential at A(-3, 2, 6) P. E. 4. 11 Find the potential at B(1, 5, 7), the potential difference VAB
Relation between E and V V is independent of the path taken. B Esto aplica sólo a campos estáticos. Significa que no hay trabajo NETO en mover una carga en un paso cerrado donde haya un campo estático E. A
Static E satisfies: B Condition for Conservative field = independent of path of integration A
x P. E. 4. 12 work done in moving a -2 m. C charge from (0, 5, 0) to (2, -1, 0) by taking the straight-line path. a) (0, 5, 0)→(2, 5, 0) →(2, -1, 0) b) y = 5 -3 x y
Given the potential Example Find D at In spherical coordinates: .
Electric Dipole n z Is formed when 2 point charges of equal but opposite sign are separated by a small distance. P Q+ d Q- r 1 r For far away observation points (r>>d): r 2 y
Energy Density in Electrostatic fields n It can be shown that the total electric work done is:
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