Stoichiometric relationships Where am I at Stations activity

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Stoichiometric relationships Where am I at? Stations activity

Stoichiometric relationships Where am I at? Stations activity

How am I at each station? Station # 1. Kinetic theory - states of

How am I at each station? Station # 1. Kinetic theory - states of matters 2. Mole and molar mass 3. Empirical formula 4. Molecular formula 5. Reaction yield 6. Limiting reactant I do not understand after reading the answer After reading the answer I understand some parts After reading the answer I understand all parts I know the problem and I can do it by myself without looking at the answer

Station 1: Fill in the missing part of the diagram ? ? Dry ice

Station 1: Fill in the missing part of the diagram ? ? Dry ice turns into smoke is an example of what process?

Station 1: Fill in the missing part of the diagram Dry ice turns into

Station 1: Fill in the missing part of the diagram Dry ice turns into smoke is an example of what process? sublimation

Station 2: Measure exactly 0. 13 moles of Na. Cl on an electric balance

Station 2: Measure exactly 0. 13 moles of Na. Cl on an electric balance

Mr of Na. Cl = 22. 99 + 35. 45 = 58. 44 g

Mr of Na. Cl = 22. 99 + 35. 45 = 58. 44 g mol-1 mass of Na. Cl = 0. 13 mol x 58. 44 mass = 35. 06 g

Station 3:

Station 3:

Station 4: Calomel is a compound once used in the treatment of syphilis. It

Station 4: Calomel is a compound once used in the treatment of syphilis. It has the empirical formula Hg. Cl and a molar mass of 472. 08 g / mol. What is its molecular formula?

Station 5:

Station 5:

Station 6: � In the manufacture of phosphoric acid, molten elemental phosphorus is oxidized

Station 6: � In the manufacture of phosphoric acid, molten elemental phosphorus is oxidized and then hydrated according to the following equation: P 4 + 5 O 2 + 6 H 2 O → 4 H 3 PO 4 � If 24. 77 g of phosphorus reacts with 100. 0 g of oxygen and excess water, determine the a) limiting reagent b) the amount in mol of phosphoric acid produced (the theoretical yield)

Station 6 answer P 4 + 5 O 2 + 6 H 2 O

Station 6 answer P 4 + 5 O 2 + 6 H 2 O → � M 123. 8832 � m 24. 77 100. 0 � n 0. 200 3. 125 n (final) 0. 0 2. 125 �m=Mxn � m = 98 x 0. 800 = 78. 40 g 4 H 3 PO 4 0. 800