DATA STORAGE Danang Wahyu Utomo danang wudsn dinus

DATA STORAGE Danang Wahyu Utomo danang. wu@dsn. dinus. ac. id +6285 725 158 327 Danang Wahyu Utomo

RENCANA KEGIATAN PERKULIAHAN SEMESTER W Pokok Bahasan W 1 Pengenalan Teknologi Informasi 9 2 10 Pokok Bahasan Komputasi Pemrograman 3 Konsep Sistem Komputer & Pengenalan Perangkat Keras 4 Data Storage 12 Komunikasi data & Jaringan 13 Komputer Perangkat Lunak 14 Etika dan dampak teknologi informasi 7 Data dan Informasi 8 Ujian Tengah Semester 15 Teknologi Terkini / Advance Topik 5 6 11 Rekayasa Perangkat Lunak sosial 16 Ujian Akhir Semester Danang Wahyu Utomo

Reference � William Stallings – Computer Organization and Architecture : Designing for Performance 8 th Edition (2010) � J. Glenn Brookshear – Computer Science : An Overview 11 th Edition (2011) Danang Wahyu Utomo

Review Last Week �Three Key Concept of Computer System �Component of Hardware �Component of CPU �System Software �Application Software Danang Wahyu Utomo

Outline Sistem Bilangan Representasi informasi dalam bit Main Memory Mass Storage Danang Wahyu Utomo

Sistem Bilangan Decimal Binary Hexadecimal Octal Converting Binary, Hexadecimal, Octal and Decimal Danang Wahyu Utomo

Decimal �Have a base, or radix of 10 �Each digit in the number is multiplied by 10 raised to a power corresponding to the digit’s position �Ex : - 83 - 4728 - 10009 Danang Wahyu Utomo

Decimal � 83 = (8 x 101) + (3 x 100) � 4728 = (4 x 103) + (7 x 102) + (2 x 101) + (8 x 100) � 10009 = (1 x 104) + (0 x 103) + (0 x 102) + = (0 x 101) + (9 x 100) Danang Wahyu Utomo

Binary �Only 2 digits, 1 and 0 �Numbers in the binary system are represented to the base 2 �Ex : � 0(2) � 1(2) � 0101(2) � 1010(2) Danang Wahyu Utomo

Decimal to Binary � 3(10) = …(2) 128 27 64 26 32 25 16 24 8 23 4 22 2 21 1 20 Danang Wahyu Utomo

Decimal to Binary � 3(10) = …(2) 128 27 0 64 26 0 32 25 0 16 24 0 8 23 0 4 22 0 2 21 1 1 20 1 3(10) = 11(2) Danang Wahyu Utomo

Decimal to Binary � 24(10) 128 27 0 = …(2) 64 26 0 32 25 0 16 24 1 8 23 1 4 22 0 2 21 0 1 20 0 24(10) = 11000(2) Danang Wahyu Utomo

Decimal to Binary � 255(10) 128 27 1 = …(2) 64 26 1 32 25 1 16 24 1 8 23 1 4 22 1 2 21 1 1 20 1 255(10) = 1111(2) Danang Wahyu Utomo

Binary to Decimal � 101(2) = ………. . (10) � 1001(2) = ………. . (10) � 1111(2) = ………. . (10) Danang Wahyu Utomo

Binary to Decimal � 101(2) = …(10) 1 0 1 Danang Wahyu Utomo

Binary to Decimal � 101(2) = …(10) 1 22 0 21 1 20 Danang Wahyu Utomo

Binary to Decimal � 101(2) = …(10) 1 22 4 0 21 0 1 20 1 101(2) = (1 x 22) + (0 x 21) + (1 x 20) = 4 + 0 + 1 = 5(10) Danang Wahyu Utomo

Hexadecimal �Binary digits are grouped into sets of four �Base 16 Ex : - 2 C(16) - DE 2(16) - AA(16) - 69 F(16) Danang Wahyu Utomo

Hexadecimal to Decimal 2 C(16) = …(10) 2 C(16) = (2 x 161) + (12 x 160) = 32 + 12 = 44(10) Danang Wahyu Utomo

Decimal to Hexadecimal 44(10) = …(16) 12 = C 44(10) = 2 C(16) Danang Wahyu Utomo

Hexadecimal to Binary 2 C(16) = …(2) 2 0010 C (12) 1100 2 C(16) = 00101100(2) Danang Wahyu Utomo

Binary to Hexadecimal 00101100(2) = …(16) 00101100 Danang Wahyu Utomo

Binary to Hexadecimal 00101100(2) = …(16) 00101100 0010 1100 Danang Wahyu Utomo

Binary to Hexadecimal 00101100(2) = …(16) 00101100 0010 2 1100 12 / (C) 00101100(2) = 2 C(16) Danang Wahyu Utomo

Octal �Binary digits are grouped into sets of three �Base 8 Ex : � 545(8) � 55(8) Danang Wahyu Utomo

Octal to Decimal � 545(8) = …(10) 5 4 5 Danang Wahyu Utomo

Octal to Decimal � 545(8) = …(10) 5 82 4 81 5 80 Danang Wahyu Utomo

Octal to Decimal � 545(8) = …(10) 5 82 320 4 81 32 5 80 5 545(8) = (5 x 82) + (4 x 81) + (5 x 80) = 320 + 32 + 5 = 357(10) Danang Wahyu Utomo

Decimal to Octal 357(10) = …(8) 357(10) = 545(8) Danang Wahyu Utomo

Octal to Binary 545(8) = …(2) 5 4 5 Danang Wahyu Utomo

Octal to Binary 545(8) = …(2) 5 101 4 100 5 101 545(8) = 101100101(2) Danang Wahyu Utomo

Binary to Octal 101100101(2) = …(8) 101100101 Danang Wahyu Utomo

Binary to Octal 101100101(2) = …(8) 101100101 100 101 Danang Wahyu Utomo

Binary to Octal 101100101(2) = …(8) 101 5 101100101 100 4 101 5 101100101(2) = 545(8) Danang Wahyu Utomo

Octal to Hexadecimal 545(8) = …(16) 5 101 4 100 5 101 0001 1 0110 6 0101 5 545(8) = 165(16) Danang Wahyu Utomo

Hexadecimal to Octal 165(16) = …(8) 1 0001 6 0110 5 0101 5 000101100101 4 5 165(16) = 545(8) Danang Wahyu Utomo

Representasi Informasi dalam Bit Text Image Danang Wahyu Utomo

Representasi Text dalam Bit �Pada tahun 1940 – 1950 an banyak jenis kode yang dirancang dan digunakan dengan peralatan yang berbeda, hal ini menyebabkan meluasnya masalah komunikasi. �Untuk mengatasi masalah ini American Standard National Institute (ANSI) mengadopsi sistem American Standard Code for Information Interchange (ASCII). Danang Wahyu Utomo

Representasi Text dalam Bit �Kode ASCII menggunakan pola bit dengan panjang 7 bit untuk merepresentasikan huruf kecil, huruf kapital dalam alfabet Inggris, angka 0 -9, tanda baca, control information seperti carriage return(CR), line feed(LF), dan DEL. Danang Wahyu Utomo

Contoh Representasi Text Danang Wahyu Utomo

Representasi Citra dalam Bit Red : 69(10) = 01000101(2) Green : 152(10) = 10011000(2) Blue : 202(10) = 11001010(2) Danang Wahyu Utomo

Main Memory � Penyusunan memory cell berdasarkan alamat Danang Wahyu Utomo

Main Memory � Pengaturan memory cell berukuran byte (8 bit) � Most significant bit : the leftmost bit � Least significant bit : the rightmost bit Danang Wahyu Utomo

Mass Storage � Most computers have additional memory devices � Example : - Magnetic disks CDs DVDs Magnetic tapes Flash drives Danang Wahyu Utomo

Magnetic System � Magnetic Disk Danang Wahyu Utomo

Magnetic System � Magnetic Tape Danang Wahyu Utomo

Optical System Danang Wahyu Utomo

TERIMA KASIH Danang Wahyu Utomo