Announcements Assignment 1 solutions posted Assignment 2 due

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Announcements • Assignment 1 solutions posted • Assignment 2 due Thursday • First mid-term

Announcements • Assignment 1 solutions posted • Assignment 2 due Thursday • First mid-term Thursday October 27 th (? )

Lecture 8 Overview • • • Inductors in transient circuits Semiconductors Diodes Rectifying circuits

Lecture 8 Overview • • • Inductors in transient circuits Semiconductors Diodes Rectifying circuits Other Diode Applications Transistors

Time response of Inductors Switch to position a: Integrate and apply boundary condition t=0,

Time response of Inductors Switch to position a: Integrate and apply boundary condition t=0, i=0 Time constant τ=L/R. Switch to position b: Talk about "Charging a capacitor" "Current build-up" in an inductor

Time response of Inductors A battery is connected to an inductor. When the switch

Time response of Inductors A battery is connected to an inductor. When the switch is opened does the light bulb: 1. Remain off 2. Go off 3. Slowly Dim out 4. Keep burning as brightly as it did before the switch was opened 5. Flare up brightly, then dim and go out Answer 5

Semiconductors Simple review of basic concepts: What is a semiconductor? (for more detail see

Semiconductors Simple review of basic concepts: What is a semiconductor? (for more detail see e. g. Simpson Ch. 4) Elements such as Silicon and Germanium have 4 valence electrons in their outer shell They form covalent bonds with neighbouring atoms to form strong crystal lattice structures. In pure silicon, all valence electrons are bound in the lattice structure

Semiconductors The addition of impurities ("doping"), such as Sb(Antimony) with 5 valence electrons, leaves

Semiconductors The addition of impurities ("doping"), such as Sb(Antimony) with 5 valence electrons, leaves one electron unbound and free to move and create a current flow (n-type semiconductor). Alternatively, an impurity with 3 valence electrons can be used to create positive "holes". When a p-type and an n-type are joined (p-n junction), mobile electrons diffuse from the n-type to the p-type, forming positive and negative ions at fixed positions in a state of equilibrium which inhibit further transfer of electrons (depletion region) - depletion region E-field + (~0. 2 V Ge, ~0. 5 V Si)

What happens when you apply a voltage? For the device to conduct, electrons from

What happens when you apply a voltage? For the device to conduct, electrons from the n-type region must cross the junction Depletion region E-field Reverse bias: Apply an electric field in this direction, mobile electrons are driven away from the junction (unlike fixed charged ions). Mobile holes are also driven away in the opposite direction. Depletion region acts like an insulating slab - No current flows Forward bias: Helps electrons overcome the depletion region. Current flows easily applied E-field Depletion region E-field applied E-field

Ideal diode • A diode is a non-linear circuit element • Only passes current

Ideal diode • A diode is a non-linear circuit element • Only passes current in one direction • Constructed from a p-n semiconductor junction

Real diode Diode law: IS = reverse-leakage current v = voltage across the diode

Real diode Diode law: IS = reverse-leakage current v = voltage across the diode k. B = Boltzmann's constant e- = electron charge T = Temperature (K) Strong dependence on T IS is small ~ 10 -6 A (Ge), ~10 -8(Si)

Diode Circuit • Diodes are non-linear; how do we calculate the operating conditions? (Can’t

Diode Circuit • Diodes are non-linear; how do we calculate the operating conditions? (Can’t easily use V=IR) • Consider the simplest diode circuit KVL: When ID=0; VD=VDD When VD=0; ID=VDD/R Must satisfy both equations: Operating point can be calculated by seeing when diode law line intersects load line

Rectifying Circuit Ideal transformer: VS/VP=NS/NP Real transformers are ~98% efficient One of the most

Rectifying Circuit Ideal transformer: VS/VP=NS/NP Real transformers are ~98% efficient One of the most important applications of a diode is in rectifying circuits: used to convert an AC signal into the DC voltage required by most electronics

Half-wave rectifier • Only lets through positive voltages. Rejects negative voltages

Half-wave rectifier • Only lets through positive voltages. Rejects negative voltages

Full-wave rectifier • To use both halves of the input sinusoid, can use a

Full-wave rectifier • To use both halves of the input sinusoid, can use a centre-tapped transformer: - + + e. g. Battery Charger

or use a Bridge rectifier • Does not require centre-tapped transformer • Requires 2

or use a Bridge rectifier • Does not require centre-tapped transformer • Requires 2 diodes in each direction – cheap, but voltage drop is double

Bridge rectifier • Current flow in the bridge - v. O +

Bridge rectifier • Current flow in the bridge - v. O +

Peak rectifier • Most devices need steady DC • To smooth out the peaks

Peak rectifier • Most devices need steady DC • To smooth out the peaks and obtain a DC voltage When source voltage < capacitor voltage Diode is reversed biased Capacitor discharges through resistor

Another diode application: Voltage doubler • High Voltage transformers are expensive and impractical at

Another diode application: Voltage doubler • High Voltage transformers are expensive and impractical at voltages above a few thousand Volts. How do we get higher? C 2 charges to Vsec C 1 charges to 2 Vsec

Voltage doubler • Can extend this circuit to produce extremely high voltages (~750 k.

Voltage doubler • Can extend this circuit to produce extremely high voltages (~750 k. V). Voltage Quadrupler • Cockroft-Walton voltage multiplier • 1932, Cavendish Labs • reached 250 k. V • Accelerated protons onto a Lithium target • Split the atom! • http: //www. youtube. com/watch? v=Rd. Bq. Mtioh 6 U