Water Potential p s Water potential pressure potential
![Water Potential Water Potential](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-1.jpg)
![Ψ = Ψp + Ψs Water potential = pressure potential + solute potential *Bozeman Ψ = Ψp + Ψs Water potential = pressure potential + solute potential *Bozeman](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-2.jpg)
![Water Potential • Water Potential - In osmosis, the tendency for a system (a Water Potential • Water Potential - In osmosis, the tendency for a system (a](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-3.jpg)
![Ψp (PRESSURE POTENTIAL) – An increase in pressure INCREASES water potential – Normal atmospheric Ψp (PRESSURE POTENTIAL) – An increase in pressure INCREASES water potential – Normal atmospheric](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-4.jpg)
![Ψs (SOLUTE POTENTIAL) – Relative concentration of solutes – Addition of solutes LOWERS water Ψs (SOLUTE POTENTIAL) – Relative concentration of solutes – Addition of solutes LOWERS water](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-5.jpg)
![Water Potential • Ψp and Ψs are inversely related – As pressure increases, Ψp Water Potential • Ψp and Ψs are inversely related – As pressure increases, Ψp](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-6.jpg)
![](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-7.jpg)
![Finding Ψs • Solute potential = –i. CRT i = The number of particles Finding Ψs • Solute potential = –i. CRT i = The number of particles](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-8.jpg)
![Finding Ψs • The molar concentration of a sugar solution in an open beaker Finding Ψs • The molar concentration of a sugar solution in an open beaker](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-9.jpg)
![Problem #1 • The molar concentration of a sugar solution in an open beaker Problem #1 • The molar concentration of a sugar solution in an open beaker](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-10.jpg)
![-2. 43 bars Problem #2 -3. 3 bars • The value for Ψ in -2. 43 bars Problem #2 -3. 3 bars • The value for Ψ in](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-11.jpg)
![Problem #3 -4. 86 bars -3. 3 bars • Na. Cl dissociates into 2 Problem #3 -4. 86 bars -3. 3 bars • Na. Cl dissociates into 2](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-12.jpg)
- Slides: 12
![Water Potential Water Potential](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-1.jpg)
Water Potential
![Ψ Ψp Ψs Water potential pressure potential solute potential Bozeman Ψ = Ψp + Ψs Water potential = pressure potential + solute potential *Bozeman](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-2.jpg)
Ψ = Ψp + Ψs Water potential = pressure potential + solute potential *Bozeman science video
![Water Potential Water Potential In osmosis the tendency for a system a Water Potential • Water Potential - In osmosis, the tendency for a system (a](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-3.jpg)
Water Potential • Water Potential - In osmosis, the tendency for a system (a cell or solution) to take up water from pure water, through a differentially permeable membrane. • Water will ALWAYS move from a region of HIGH water potential to an area of LOW water potential.
![Ψp PRESSURE POTENTIAL An increase in pressure INCREASES water potential Normal atmospheric Ψp (PRESSURE POTENTIAL) – An increase in pressure INCREASES water potential – Normal atmospheric](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-4.jpg)
Ψp (PRESSURE POTENTIAL) – An increase in pressure INCREASES water potential – Normal atmospheric pressure: Ψp = 0
![Ψs SOLUTE POTENTIAL Relative concentration of solutes Addition of solutes LOWERS water Ψs (SOLUTE POTENTIAL) – Relative concentration of solutes – Addition of solutes LOWERS water](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-5.jpg)
Ψs (SOLUTE POTENTIAL) – Relative concentration of solutes – Addition of solutes LOWERS water potential *Make MORE NEGATIVE!
![Water Potential Ψp and Ψs are inversely related As pressure increases Ψp Water Potential • Ψp and Ψs are inversely related – As pressure increases, Ψp](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-6.jpg)
Water Potential • Ψp and Ψs are inversely related – As pressure increases, Ψp increases – As solutes increase, Ψs decreases (value become more NEGATIVE)
![](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-7.jpg)
![Finding Ψs Solute potential i CRT i The number of particles Finding Ψs • Solute potential = –i. CRT i = The number of particles](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-8.jpg)
Finding Ψs • Solute potential = –i. CRT i = The number of particles the molecule will make in water; for sucrose or glucose, this number is 1 (Na. Cl= Na+1 and Cl-1 so = 2 particles) C = Molar concentration (from your experimental data) R = Pressure constant = 0. 0831 liter bar/mole K T = Temperature in degrees Kelvin = 273 + °C of solution
![Finding Ψs The molar concentration of a sugar solution in an open beaker Finding Ψs • The molar concentration of a sugar solution in an open beaker](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-9.jpg)
Finding Ψs • The molar concentration of a sugar solution in an open beaker has been determined to be 0. 3 M. Calculate the solute potential at 27 °C degrees. Round your answer to the nearest hundredth.
![Problem 1 The molar concentration of a sugar solution in an open beaker Problem #1 • The molar concentration of a sugar solution in an open beaker](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-10.jpg)
Problem #1 • The molar concentration of a sugar solution in an open beaker has been determined to be 0. 3 M. Calculate the solute potential at 27 degrees. Round your answer to the nearest hundredth. Ψs = -(1)(. 3 mole/liter)(0. 0831)(273+27) Ψs = -7. 48
![2 43 bars Problem 2 3 3 bars The value for Ψ in -2. 43 bars Problem #2 -3. 3 bars • The value for Ψ in](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-11.jpg)
-2. 43 bars Problem #2 -3. 3 bars • The value for Ψ in root tissue was found to be -3. 3 bars. If you take the root tissue and place it in a 0. 1 M solution of sucrose at 20°C in an open beaker, what is the Ψ of the solution, and in which direction would the net flow of water be? Ψ s= -i. CRT -(1)(0. 0831)(293)= -2. 43 bars Yp=0, so Y=-2. 43. The movement will be into the cell. Higher to lower.
![Problem 3 4 86 bars 3 3 bars Na Cl dissociates into 2 Problem #3 -4. 86 bars -3. 3 bars • Na. Cl dissociates into 2](https://slidetodoc.com/presentation_image_h2/1846bb0b8abaf42496e56eb4d9219395/image-12.jpg)
Problem #3 -4. 86 bars -3. 3 bars • Na. Cl dissociates into 2 particles in water: Na+ and Cl-. If the solution in question 4 contained 0. 1 M Na. Cl instead of 0. 1 M sucrose, what is the Ψ of the solution, and in which direction would the net flow of water be? -(2)(0. 1)(0. 0831)(293) + 0= Ψ= -4. 86 Into the environment
Water and water and water water
Flaccid cell
Water potential in plants
Water potential definition
How to find pressure potential
Insall salvati ratio
Pressure support vs pressure control
Continuous bedside pressure mapping
Intrapulmonary pressure
Oncotic pressure
Hypergraph containers
Where is intrapleural pressure
Regional metamorphism