Kinematics of Particles Rectilinear Motion Lesson 2 Sections

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Kinematics of Particles – Rectilinear Motion Lesson 2 - Sections 2/2 and 2/3 •

Kinematics of Particles – Rectilinear Motion Lesson 2 - Sections 2/2 and 2/3 • Rectilinear Motion – Fundamental equations of motion from last class © D. J. Morrison, 2013 1

 • Frequently we want to define the motion of the particle by expressing

• Frequently we want to define the motion of the particle by expressing s in terms of t • Consider the following three cases: © D. J. Morrison, 2013 2

– Case I: Acceleration given in terms of t. For example: First, look for

– Case I: Acceleration given in terms of t. For example: First, look for a fundamental equation that contains both a and t © D. J. Morrison, 2013 3

So, we start with Note we wrote the acceleration as a(t) to emphasize the

So, we start with Note we wrote the acceleration as a(t) to emphasize the fact that a is a function of t. Then: This gives us v as a function of time or v(t) © D. J. Morrison, 2013 4

But we want s in terms of t or So we must “transform” v(t)

But we want s in terms of t or So we must “transform” v(t) into s(t) © D. J. Morrison, 2013 5

Look for a fundamental equation that contains v, t, and s © D. J.

Look for a fundamental equation that contains v, t, and s © D. J. Morrison, 2013 6

So, we start with Then: This gives us s as a function of time

So, we start with Then: This gives us s as a function of time or s(t) © D. J. Morrison, 2013 7

This is what we wanted, s(t) But we already showed that: So: v(t) ©

This is what we wanted, s(t) But we already showed that: So: v(t) © D. J. Morrison, 2013 8

– Case II: Acceleration given in terms of s. For example: (Problem 2/40) First,

– Case II: Acceleration given in terms of s. For example: (Problem 2/40) First, look for a fundamental equation that contains both a and s © D. J. Morrison, 2013 9

So, we start with Rearranging terms Then This gives us v(s) © D. J.

So, we start with Rearranging terms Then This gives us v(s) © D. J. Morrison, 2013 10

Thus, we have But we want to get s(t) So we must “transform” v(s)

Thus, we have But we want to get s(t) So we must “transform” v(s) into s(t) Look for a fundamental equation that contains v, t, and s © D. J. Morrison, 2013 11

So, we start with Then: This gives us what we wanted, s as a

So, we start with Then: This gives us what we wanted, s as a function of t or s(t) © D. J. Morrison, 2013 12

– Case III: Acceleration given in terms of v. For example: (Problem 2/40) First,

– Case III: Acceleration given in terms of v. For example: (Problem 2/40) First, look for a fundamental equation that contains both a and v © D. J. Morrison, 2013 13

So, we start with Then This gives us v(t) © D. J. Morrison, 2013

So, we start with Then This gives us v(t) © D. J. Morrison, 2013 14

Then as for Case I, once we know v(t) we can find s(t) From

Then as for Case I, once we know v(t) we can find s(t) From We already showed that This gives us what we wanted, s as a function of t or s(t) © D. J. Morrison, 2013 15

 • Special Case: Uniformly accelerated rectilinear motion (UARM) – ACCELERATION is CONSTANT -

• Special Case: Uniformly accelerated rectilinear motion (UARM) – ACCELERATION is CONSTANT - not a function of time © D. J. Morrison, 2013 16

Likewise But for UARM So © D. J. Morrison, 2013 17

Likewise But for UARM So © D. J. Morrison, 2013 17

Also Then © D. J. Morrison, 2013 18

Also Then © D. J. Morrison, 2013 18

– For uniformly accelerated rectilinear motion the following equations apply: REMEMBER, UARM MEANS ACCELERATION

– For uniformly accelerated rectilinear motion the following equations apply: REMEMBER, UARM MEANS ACCELERATION IS CONSTANT!!! © D. J. Morrison, 2013 19

Example Problem: L 2 -1 © D. J. Morrison, 2013 20

Example Problem: L 2 -1 © D. J. Morrison, 2013 20

Example Problem: L 2 -1 Given: so= 3 m Find: s, v, and a,

Example Problem: L 2 -1 Given: so= 3 m Find: s, v, and a, when t = 3 s © D. J. Morrison, 2013 21

Example Problem: L 2 -2 © D. J. Morrison, 2013 22

Example Problem: L 2 -2 © D. J. Morrison, 2013 22

Example Problem: L 2 -2 Given: so= 3 m vo= 10 m/s Find: v(s),

Example Problem: L 2 -2 Given: so= 3 m vo= 10 m/s Find: v(s), and v when s = 5 m and k = 0. 1 m-1 s-2 © D. J. Morrison, 2013 23

Example Problem: L 2 -3 © D. J. Morrison, 2013 24

Example Problem: L 2 -3 © D. J. Morrison, 2013 24

Example Problem: L 2 -3 Given: a=1. 5 g = constant so= 0 vo=

Example Problem: L 2 -3 Given: a=1. 5 g = constant so= 0 vo= 0 Find: v and t when s = 30 km © D. J. Morrison, 2013 25

Example Problem: L 2 -4 © D. J. Morrison, 2013 26

Example Problem: L 2 -4 © D. J. Morrison, 2013 26

Example Problem: L 2 -4 Given: a= 0. 4 g = constant vo= 0

Example Problem: L 2 -4 Given: a= 0. 4 g = constant vo= 0 so= 0 Find: s and t when v = 200 km/h © D. J. Morrison, 2013 27