Integrated rate laws rate kA lnA kt lnA0

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Integrated rate laws rate = k[A] ln[A] = -kt + ln[A]0 rate = k[A]2

Integrated rate laws rate = k[A] ln[A] = -kt + ln[A]0 rate = k[A]2 1/[A] = kt + 1/[A]0

Reaction mechanism reaction = Elementary steps Molecularity Elementary step rate law unimolecular A product

Reaction mechanism reaction = Elementary steps Molecularity Elementary step rate law unimolecular A product bimolecular A+ B product termolecular A+B+C product A+A+A product k[A][B][C] k[A]3 chemical reaction = sum of elementary steps rate law and stoichiometry

Reaction mechanism 2 H 2 O 2 (aq) 2 H 2 O(l) + O

Reaction mechanism 2 H 2 O 2 (aq) 2 H 2 O(l) + O 2(g) Gorxn = [ 2(-237. 9)] - [2(-131. 67)] = -212. 46 k. J spontaneous reaction experimental rate law: rate = k[H 2 O 2] [I-] I- = catalyst increase rate of reaction not consumed in the overall reaction reactant in early elementary step product in later elementary step

Reaction mechanism 2 H 2 O 2 (aq) 2 H 2 O(l) + O

Reaction mechanism 2 H 2 O 2 (aq) 2 H 2 O(l) + O 2(g) rate = k[H 2 O 2] [I-] k 1 step 1 H 2 O 2 + I- H 2 O + OIk 2 step 2 H 2 O 2 + OI- H 2 O + O 2 +I 2 H 2 O 2 (aq) 2 H 2 O(l) + O 2(g) step 1 rate = k 1 [H 2 O 2] [I-]

Reaction mechanism k 1 step 1 H 2 O 2 + I- H 2

Reaction mechanism k 1 step 1 H 2 O 2 + I- H 2 O + OIk 2 step 2 H 2 O 2 + OI- H 2 O + O 2 +Iwhat about step 2 ? step 1 assume k 2 >> k 1 rate determining step I- catalyst consumed in rate determining step regenerated in later elementary step OI- intermediate formed in early step, consumed in later step

Rate determining step on Labor Day weekend “Big Mac” bridge

Rate determining step on Labor Day weekend “Big Mac” bridge

Reaction Mechanism H 2(g) + I 2(g) 2 HI(g) rate = k [H 2]

Reaction Mechanism H 2(g) + I 2(g) 2 HI(g) rate = k [H 2] [I 2] reaction faster in light free radical unpaired electron

Reaction Mechanism H 2(g) + I 2(g) 2 HI(g) step 1 rate = k

Reaction Mechanism H 2(g) + I 2(g) 2 HI(g) step 1 rate = k [H 2] [I 2] I 2 2 I. forward rate = kf [I 2]. reverse rate = kr [I ]2. 2 k [I ] = k [I ] equilibrium f 2 r Keq= . [I ]2 = kf [I 2] kr

Reaction Mechanism H 2(g) + I 2(g) 2 HI(g) step 2 step 1 rate

Reaction Mechanism H 2(g) + I 2(g) 2 HI(g) step 2 step 1 rate = k [H 2] [I 2]. I 2 2 I. H 2 + 2 I 2 HI H 2 + I 2 2 HI need H 2 in the rate determining step from step 2 rate = k [H 2] [I. ]2. I = intermediate

Reaction Mechanism H 2(g) + I 2(g) 2 HI(g) step 2 step 1 rate

Reaction Mechanism H 2(g) + I 2(g) 2 HI(g) step 2 step 1 rate = k [H 2] [I 2]. I 2 2 I. H 2 + 2 I 2 HI . rate = k [H 2] [I ]2 rate = k [H 2] Keq [I 2] rate = k’ [H 2] [I 2] . Keq = [I ]2 = kf [I 2] kr . [I ]2 = Keq [I 2]

Reaction Mechanism 2 NO + O 2 2 NO 2 rate = k[NO]2 2

Reaction Mechanism 2 NO + O 2 2 NO 2 rate = k[NO]2 2 NO N 2 O 2 step 1 N 2 O 2 + O 2 2 NO 2 overall reaction: 2 NO + O 2 2 NO 2 step 2 intermediates: N 2 O 2 relative rates of steps 1 and 2

2 NO + O 2 2 NO 2 rate = k[NO]2 step 2 2

2 NO + O 2 2 NO 2 rate = k[NO]2 step 2 2 NO N 2 O 2 + O 2 2 NO 2 step 1