Questions of the Day The reactions in our

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Questions of the Day: The reactions in our Exp. 3 (NBS-Bromination) are radical reactions!

Questions of the Day: The reactions in our Exp. 3 (NBS-Bromination) are radical reactions! a) What is the structure of the radical formed when Br. radical reacts with ethyl benzene? b) Why is there no radical formation in the beta position of ethyl benzene?

Today: • Exp. 3: NBS Bromination: NMR • Introduction to Diels-Alder (Exp. 4) •

Today: • Exp. 3: NBS Bromination: NMR • Introduction to Diels-Alder (Exp. 4) • Mini. Quiz

1. What is the function of dibenzoyl peroxide? 2. What is the function of

1. What is the function of dibenzoyl peroxide? 2. What is the function of N-Bromosuccinimide (NBS)? For which compounds can it be used? (compare with your lecture text!) 3. Why do we use NBS and not Br 2?

Propagation is complex here … How can you explain that the reaction mixture goes

Propagation is complex here … How can you explain that the reaction mixture goes through a series of color changes?

Synthesis of Bromoethylbenzene (Manual Exp. III) 1. Why is CCl 4 a good solvent

Synthesis of Bromoethylbenzene (Manual Exp. III) 1. Why is CCl 4 a good solvent for our reaction mixture? 2. What are criteria for a "good solvent" in general? 3. What is the purpose of adding cyclododecane?

1 H-NMR 1. Draw a rough 1 H-NMR of a sample that contains (only)

1 H-NMR 1. Draw a rough 1 H-NMR of a sample that contains (only) 1. ethyl benzene in CCl 4 and a drop of TMS standard. 2. a-monobromoethyl benzene in CCl 4 and a drop of TMS standard. 3. a-dibromoethyl benzene in CCl 4 and a drop of TMS standard. 4. Cyclododecane in CCl 4 and a drop of TMS standard.

http: //www. aist. go. jp/RIODB ethylbenzene α-bromoethylbenzene

http: //www. aist. go. jp/RIODB ethylbenzene α-bromoethylbenzene

singlet doublet quartet

singlet doublet quartet

1 H-NMR Why is cyclododecane a good standard in our experiment?

1 H-NMR Why is cyclododecane a good standard in our experiment?

Calculation of the Yield %-yield of alpha –bromoethylbenzene … For actual yield: Compare the

Calculation of the Yield %-yield of alpha –bromoethylbenzene … For actual yield: Compare the integrations of the cyclododecane peak with those of the a and b protons of the mono-brominated product. np = nc x Aa/Ac x 24/1 = nc x Ab/Ac x 24/3 np = moles of mono-bromo product nc = moles of cyclododecane Aa = area of alpha protons Ab= area of beta protons Ac= area of cyclododecane protons Use both the alpha and beta signals to calculate your yield and also report the average value.

Diels – Alder Reactions (Exp. 4) Cyclopentadiene STINKS!! Maleic anhydride Diels Alder Adduct Diels-Alder

Diels – Alder Reactions (Exp. 4) Cyclopentadiene STINKS!! Maleic anhydride Diels Alder Adduct Diels-Alder reactions are another example of syntheses that introduce additional C's to a reactant. A Diels-Alder reaction always forms a new cyclohexene ring. Diels-Alder reactions are cycloaddition reactions. The addition is stereospecific.

Diels – Alder Reactions (Exp. 4) Cyclopentadiene dimerizes easily. Thus we have to “crack”

Diels – Alder Reactions (Exp. 4) Cyclopentadiene dimerizes easily. Thus we have to “crack” it first (STENCH!) : Step 1: Cracking (A retro Diels Alder) Step 2: Diels. Alder Step 3: Hydrolysis

Next time: • Diels-Alder (cont. ) • Esterification (Exp. 5) • Mini. Quiz on

Next time: • Diels-Alder (cont. ) • Esterification (Exp. 5) • Mini. Quiz on today’s class

Mini. Quiz 3 Questions: a) What is the structure of the radical formed when

Mini. Quiz 3 Questions: a) What is the structure of the radical formed when Br. radical reacts with ethyl benzene? b) Why is there no radical formation in the beta position of ethyl benzene?