DET 101 ELECTRIC CIRCUIT FUNDAMENTAL I Chapter 2

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DET 101 ELECTRIC CIRCUIT FUNDAMENTAL I Chapter 2 Resistive Circuits: Part II

DET 101 ELECTRIC CIRCUIT FUNDAMENTAL I Chapter 2 Resistive Circuits: Part II

RESISTIVE CIRCUIT: PART II § Series-Parallel § Delta-Wye Transformation

RESISTIVE CIRCUIT: PART II § Series-Parallel § Delta-Wye Transformation

PREVIOUS CHAPTER Series Resistance Current Voltage Parallel

PREVIOUS CHAPTER Series Resistance Current Voltage Parallel

PREVIOUS CHAPTER Series Parallel KVL KCL VDR CDR Law Rule

PREVIOUS CHAPTER Series Parallel KVL KCL VDR CDR Law Rule

SERIES-PARALLEL A series-parallel circuit consists of both series and parallel current path.

SERIES-PARALLEL A series-parallel circuit consists of both series and parallel current path.

SERIES-PARALLEL § Most practical circuits have combinations of series and parallel components. § An

SERIES-PARALLEL § Most practical circuits have combinations of series and parallel components. § An important analysis method is to form an equivalent circuit. § An equivalent circuit is one that has characteristics that are electrically the same as another circuit but is generally simpler.

SERIES-PARALLEL For example: is equivalent to

SERIES-PARALLEL For example: is equivalent to

SERIES-PARALLEL Another example: is equivalent to

SERIES-PARALLEL Another example: is equivalent to

SERIES-PARALLEL is equivalent to

SERIES-PARALLEL is equivalent to

SERIES-PARALLEL

SERIES-PARALLEL

SERIES-PARALLEL

SERIES-PARALLEL

SERIES-PARALLEL

SERIES-PARALLEL

SERIES-PARALLEL Example 1: ANS: R 1 + R 2 ║R 3 + R 4

SERIES-PARALLEL Example 1: ANS: R 1 + R 2 ║R 3 + R 4

SERIES-PARALLEL Example 2: ANS: R 1 + R 2 ║R 3 + R 4

SERIES-PARALLEL Example 2: ANS: R 1 + R 2 ║R 3 + R 4 ║R 5

SERIES-PARALLEL Exercise 1: Identify the series-parallel relationships between terminals A and D: ANS: R

SERIES-PARALLEL Exercise 1: Identify the series-parallel relationships between terminals A and D: ANS: R 1 + [ (((R 2 + R 3)║R 4 ) + R 5)║R 6 ]

SERIES-PARALLEL Exercise 2: Find the total resistance, RT : ANS: RT = 148. 4

SERIES-PARALLEL Exercise 2: Find the total resistance, RT : ANS: RT = 148. 4 Ω

SERIES-PARALLEL Exercise 3: Find the current through R 2 and the current through R

SERIES-PARALLEL Exercise 3: Find the current through R 2 and the current through R 3. ANS: I 2 = 5. 69 m. A , I 3 = 3. 79 m. A

SERIES-PARALLEL Exercise 4: Determine the current through R 4 and if Vs= 5 V.

SERIES-PARALLEL Exercise 4: Determine the current through R 4 and if Vs= 5 V. ANS: I 4 = 3. 45 m. A

SERIES-PARALLEL Exercise 5: Determine the voltage drop across each resistor. ANS: V 1 =

SERIES-PARALLEL Exercise 5: Determine the voltage drop across each resistor. ANS: V 1 = 688 m. V , V 2 = 688 m. V , V 3 = 1. 35 V , V 4 = 981 m. V , V 5 = 366 m. V

∆-TO-Y AND Y-TO-∆ Wye-Delta (and vice versa) Transformation § The Y-Δ transform, also written

∆-TO-Y AND Y-TO-∆ Wye-Delta (and vice versa) Transformation § The Y-Δ transform, also written wye-delta and also known by many other names, is a mathematical technique to simplify the analysis of an electrical network. § The aim is to analyse the circuit when the resistors are neither in parallel nor in series.

∆-TO-Y AND Y-TO-∆ How to Combine R 1 – R 6? § Solution: Use

∆-TO-Y AND Y-TO-∆ How to Combine R 1 – R 6? § Solution: Use three terminal equivalent networks: a) Wye (Y) or Tee (T) b) Delta (∆) or Pi (π) § Useful in: a) Three phase networks b) Electrical filters c) Matching networks

∆-TO-Y AND Y-TO-∆ Delta Configuration Delta (∆) Pi (π)

∆-TO-Y AND Y-TO-∆ Delta Configuration Delta (∆) Pi (π)

∆-TO-Y AND Y-TO-∆ Wye Configuration Wye (Y) Tee (T)

∆-TO-Y AND Y-TO-∆ Wye Configuration Wye (Y) Tee (T)

∆-TO-Y AND Y-TO-∆ How to Apply Transformation? Delta (∆) Wye (Y)

∆-TO-Y AND Y-TO-∆ How to Apply Transformation? Delta (∆) Wye (Y)

∆-TO-Y AND Y-TO-∆ How to Apply Transformation?

∆-TO-Y AND Y-TO-∆ How to Apply Transformation?

∆-TO-Y AND Y-TO-∆ ∆-Y Conversion

∆-TO-Y AND Y-TO-∆ ∆-Y Conversion

∆-TO-Y AND Y-TO-∆ Y-∆ Conversion

∆-TO-Y AND Y-TO-∆ Y-∆ Conversion

∆-TO-Y AND Y-TO-∆ Example 3: Find the current and power supplied by the 40

∆-TO-Y AND Y-TO-∆ Example 3: Find the current and power supplied by the 40 V sources in the circuit shown below.

∆-TO-Y AND Y-TO-∆ Solution: § We can find this equivalent resistance easily after replacing

∆-TO-Y AND Y-TO-∆ Solution: § We can find this equivalent resistance easily after replacing either: upper Δ (100, 125, 25Ω) or lower Δ (40, 25, 37. 5Ω) with its equivalent Y. § We choose to replace the upper Δ.

∆-TO-Y AND Y-TO-∆

∆-TO-Y AND Y-TO-∆

∆-TO-Y AND Y-TO-∆ § Substituting the Y-resistor into the equivalent circuit:

∆-TO-Y AND Y-TO-∆ § Substituting the Y-resistor into the equivalent circuit:

∆-TO-Y AND Y-TO-∆ § Calculate the equivalent resistance:

∆-TO-Y AND Y-TO-∆ § Calculate the equivalent resistance:

∆-TO-Y AND Y-TO-∆ § Then, the current and power values are:

∆-TO-Y AND Y-TO-∆ § Then, the current and power values are: