LECTURE 15 Amperes Law Gauss Law for Magnetism

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LECTURE 15 • Ampere’s Law • Gauss’ Law for Magnetism • Force between Current

LECTURE 15 • Ampere’s Law • Gauss’ Law for Magnetism • Force between Current Carrying Wires • Magnetism in Matter

Magnetic Field of a Solenoid Step 1: Cut up the distribution into pieces Step

Magnetic Field of a Solenoid Step 1: Cut up the distribution into pieces Step 2: Contribution of one piece origin: center of the solenoid one loop: B Number of loops per meter: N/L Number of loops in z: (N/L) z Field due to z: 2

Magnetic Field of a Solenoid Step 3: Add up the contribution of all the

Magnetic Field of a Solenoid Step 3: Add up the contribution of all the pieces B Magnetic field of a solenoid: 3

Magnetic Field of a Solenoid Special case: R<<L, center of the solenoid (d~0): in

Magnetic Field of a Solenoid Special case: R<<L, center of the solenoid (d~0): in the middle of a long solenoid 4

Solenoid *Direction of B: Use the right hand rule. Curl fingers in direction of

Solenoid *Direction of B: Use the right hand rule. Curl fingers in direction of current flow in loop and thumb points in the direction of B. 12/20/2021 5

Magnetic Field Inside an Ideal Solenoid 12/20/2021 6

Magnetic Field Inside an Ideal Solenoid 12/20/2021 6

Ampere’s Law • Calculate field at distance r from wire using Ampere's Law:

Ampere’s Law • Calculate field at distance r from wire using Ampere's Law:

Magnetic Field Inside a Long Straight Wire 12/20/2021 8

Magnetic Field Inside a Long Straight Wire 12/20/2021 8

Magnetic Field Inside & Outside a Long Straight Wire Inside Outside 12/20/2021 9

Magnetic Field Inside & Outside a Long Straight Wire Inside Outside 12/20/2021 9

Magnetic Field Inside a Toroid 12/20/2021 10

Magnetic Field Inside a Toroid 12/20/2021 10

When Ampere’s Law doesn’t Help B can’t be factored out of the integral. finite

When Ampere’s Law doesn’t Help B can’t be factored out of the integral. finite length current segment 12/20/2021 insufficient symmetry current is not continuous 11

Remember Gauss’ Law for Electric Fields 12/20/2021 12

Remember Gauss’ Law for Electric Fields 12/20/2021 12

Gauss’ Law for Magnetism 12/20/2021 Since all lines of B are closed loops, any

Gauss’ Law for Magnetism 12/20/2021 Since all lines of B are closed loops, any B line leaving a closed surface MUST reenter it somewhere. TRUE IN GENERAL, not just for this “dipole” example 13

Question y Two parallel horizontal wires are located in the vertical (x, y) plane

Question y Two parallel horizontal wires are located in the vertical (x, y) plane as shown. Each wire carries a current of I = 1 A flowing in the directions shown. What is the direction of B at P? y I 1 = 1 A 4 cm x 4 cm I 2 = 1 A Front view 3 cm z P Side view y y y . . . z P A 12/20/2021 z P B z z P P C D z P E 14

Calculation y Two parallel horizontal wires are located in the vertical (x, y) plane

Calculation y Two parallel horizontal wires are located in the vertical (x, y) plane as shown. Each wire carries a current of I = 1 A flowing in the directions shown. y I 1 = 1 A 4 cm x 4 cm What is the B field at point P? y y y . . A z P B 90 o z z P P C 3 cm P Side view y P z I 2 = 1 A Front view What is the direction of B at P? z . D

Force between Two Parallel Current Carrying Wires *Parallel currents attract *Anti-parallel currents repel

Force between Two Parallel Current Carrying Wires *Parallel currents attract *Anti-parallel currents repel

Force between Two Parallel Current Carrying Wires

Force between Two Parallel Current Carrying Wires

DEMO parallel wires 13. 5 V I 1 R 1 12/20/2021 R 2 I

DEMO parallel wires 13. 5 V I 1 R 1 12/20/2021 R 2 I 2 , depending on switch position 18

Force Between two Parallel Current Carrying Wires I 1 I 2 attraction I 1

Force Between two Parallel Current Carrying Wires I 1 I 2 attraction I 1 I 2 repulsion Collapse or expansion? Magnetic “pressure” 12/20/2021 19

Force between a Solenoid & a Current Carrying Wire (DEMO) 12/20/2021 20

Force between a Solenoid & a Current Carrying Wire (DEMO) 12/20/2021 20

QUIZ lecture 15 The figure shows a long straight wire with current I and

QUIZ lecture 15 The figure shows a long straight wire with current I and three wire loops, all with the same clockwise current around them. The loops are all at the same distance from the long wire and have edge lengths of either L or 2 L. Rank the loops according to the magnitude of the net force on them due to the current in the long straight wire, greatest first. A. 1 = 2 =3 I B. 1 > 2 > 3 L 2 L I (1) I I (2) (3) C. 1 > 2 = 3 D. 2 = 3 > 1 E. 3 > 2 >1 12/20/2021 21

Dipole Moments in Applied Fields 12/20/2021 22

Dipole Moments in Applied Fields 12/20/2021 22

Magnetization and “Bound Current” Net current inside the material is zero. We are left

Magnetization and “Bound Current” Net current inside the material is zero. We are left with a surface current and therefore a magnetic moment 12/20/2021 23

Magnetization and “Bound Current” 12/20/2021 24

Magnetization and “Bound Current” 12/20/2021 24

Magnetization and Magnetic Susceptibility bismuth, 12/20/2021 25

Magnetization and Magnetic Susceptibility bismuth, 12/20/2021 25

Magnetic Materials fall into Three Categories m Km 1+ *increase in B is small

Magnetic Materials fall into Three Categories m Km 1+ *increase in B is small *aligns with Bapp Order of (+10– 5), depends on temperature Diamagnetism Order of (– 10– 5) 1– positive and large ~ m Category Paramagnetism Decrease in B is small aligns opposite Bapp Ferromagnetism High degree of alignment even in weak Bapp 12/20/2021 26

Magnetic Susceptibility m Material m Type Bi – 1. 66 x 10– 5 diamagnetic

Magnetic Susceptibility m Material m Type Bi – 1. 66 x 10– 5 diamagnetic Ag – 2. 6 x 10– 5 diamagnetic Al Fe (annealed) Permalloy mu-metal superconductor 2. 3 x 10– 5 5, 500 25, 000 100, 000 – 1 paramagnetic ferromagnetic diamagnetic (perfect) m negative for diamagnetics, small and positive for paramagnetics, large and positive for ferromagnetics. 12/20/2021 27