Law of Conservation of Momentum Law of Conservation

Law of Conservation of Momentum

Law of Conservation of Momentum - total momentum of all objects before a collision equals the total momentum of all objects after a collision

Law of Conservation of Momentum - total momentum of all objects before a collision equals the total momentum of all objects after a collision pbefore = pafter

Law of Conservation of Momentum - total momentum of all objects before a collision equals the total momentum of all objects after a collision p(before) = p(after) And if p = m x v, then (m x v)before = (m x v)after

Law of Conservation of Momentum - total momentum of all objects before a collision equals the total momentum of all objects after a collision p(before) = p(after) And if p = m x v, then (m x v)before = (m x v)after And with multiple objects, then [before] [after] (m 1 x v 1) + (m 2 x v 2) +… = (m 1 x v 1) + (m 2 x v 2) +…

20 kg 11 kg

20 kg 11 kg 0. 5 m/s 10 m/s

20 kg 11 kg 0. 5 m/s 10 m/s Total momentum before = m 1 x v 1 + m 2 x v 2 = 20 x 0. 5 + 1 x 0 = 10 kgm/s

20 kg 0. 5 m/s 11 kg 10 m/s Total momentum before = m 1 x v 1 + m 2 x v 2 = 20 x 0. 5 + 1 x 0 = 10 kgm/s Total momentum after = m 1 x v 1 + m 2 x v 2 = 20 x 0 + 1 x 10 = 10 kgm/s

20 kg 11 kg 0. 5 m/s 10 m/s Total momentum before = m 1 x v 1 + m 2 x v 2 = 20 x 0. 5 + 1 x 0 = 10 kgm/s Total momentum after = m 1 x v 1 + m 2 x v 2 = 20 x 0 + 1 x 10 = 10 kgm/s Given any three pieces of information, we could solve for the other using the equation:

20 kg 11 kg 0. 5 m/s 10 m/s Total momentum before = m 1 x v 1 + m 2 x v 2 = 20 x 0. 5 + 1 x 0 = 10 kgm/s Total momentum after = m 1 x v 1 + m 2 x v 2 = 20 x 0 + 1 x 10 = 10 kgm/s Given any three pieces of information, we could solve for the other using the equation: before after m 1 x v 1 + m 2 x v 2 = m 1 x v 1 + m 2 x v 2

10 kg 0. 2 1 kg 0. 4 m/s v 2 m/s Given any three pieces of information, we could solve for the other using the equation: before after

10 kg 0. 2 1 kg 0. 4 m/s v 2 m/s Given any three pieces of information, we could solve for the other using the equation: before after m 1 = v 1 = m 2 = v 2 =

10 kg 0. 2 1 kg 0. 4 m/s v 2 m/s Given any three pieces of information, we could solve for the other using the equation: before after m 1 = 10 kg v 1 = 0. 4 m/s m 2 = 0. 2 kg v 2 = 0 m/s

10 kg 0. 4 m/s 0. 2 1 kg v 2 m/s Given any three pieces of information, we could solve for the other using the equation: before after m 1 = 10 kg v 1 = 0. 4 m/s m 2 = 0. 2 kg v 2 = 0 m/s m 1 = v 1 = m 2 = v 2 =

10 kg 0. 4 m/s 0. 2 1 kg v 2 m/s Given any three pieces of information, we could solve for the other using the equation: before after m 1 = 10 kg v 1 = 0. 4 m/s m 2 = 0. 2 kg v 2 = 0 m/s m 1 = 10 kg v 1 = 0 m/s m 2 = 0. 2 kg v 2 = ?

10 kg 0. 2 1 kg 0. 4 m/s v 2 m/s Given any three pieces of information, we could solve for the other using the equation: before after m 1 x v 1 + m 2 x v 2 = m 1 x v 1 + m 2 x v 2 m 1 = 10 kg v 1 = 0. 4 m/s m 2 = 0. 2 kg v 2 = 0 m/s m 1 = 10 kg v 1 = 0 m/s m 2 = 0. 2 kg v 2 = ?

10 kg 0. 2 1 kg 0. 4 m/s v 2 m/s Given any three pieces of information, we could solve for the other using the equation: before after m 1 x v 1 + m 2 x v 2 = m 1 x v 1 + m 2 x v 2 m 1 = 10 kg v 1 = 0. 4 m/s m 2 = 0. 2 kg v 2 = 0 m/s (10 x 0. 4) + (0. 2 x 0) = (10 x 0) + (0. 2 x v 2) m 1 = 10 kg v 1 = 0 m/s m 2 = 0. 2 kg v 2 = ?

10 kg 0. 2 1 kg 0. 4 m/s v 2 m/s Given any three pieces of information, we could solve for the other using the equation: before after m 1 x v 1 + m 2 x v 2 = m 1 x v 1 + m 2 x v 2 m 1 = 10 kg v 1 = 0. 4 m/s m 2 = 0. 2 kg v 2 = 0 m/s (10 x 0. 4) + (0. 2 x 0) = (10 x 0) + (0. 2 x v 2) 4 + 0 = 0 + (0. 2 x v 2) m 1 = 10 kg v 1 = 0 m/s m 2 = 0. 2 kg v 2 = ?

10 kg 0. 2 1 kg 0. 4 m/s v 2 m/s Given any three pieces of information, we could solve for the other using the equation: before after m 1 x v 1 + m 2 x v 2 = m 1 x v 1 + m 2 x v 2 m 1 = 10 kg v 1 = 0. 4 m/s m 2 = 0. 2 kg v 2 = 0 m/s (10 x 0. 4) + (0. 2 x 0) = (10 x 0) + (0. 2 x v 2) 4 + 0 = 0 + 4 = 0. 2 x v 2 (0. 2 x v 2) m 1 = 10 kg v 1 = 0 m/s m 2 = 0. 2 kg v 2 = ?

10 kg 0. 2 1 kg 0. 4 m/s v 2 m/s Given any three pieces of information, we could solve for the other using the equation: before after m 1 x v 1 + m 2 x v 2 = m 1 x v 1 + m 2 x v 2 m 1 = 10 kg v 1 = 0. 4 m/s m 2 = 0. 2 kg v 2 = 0 m/s (10 x 0. 4) + (0. 2 x 0) = (10 x 0) + (0. 2 x v 2) 4 + 0 = 0 + 4 = 0. 2 x v 2 20 m/s = v 2 (0. 2 x v 2) m 1 = 10 kg v 1 = 0 m/s m 2 = 0. 2 kg v 2 = ?