Momentum Types of Collisions http www aplusphysics comcourseshonorsmomentumcollisions

Momentum – Types of Collisions http: //www. aplusphysics. com/courses/honors/momentum/collisions. html Unit #4 Momentum

Objectives and Learning Targets Define and calculate the momentum of an object. Determine the impulse given to an object. Use impulse to solve a variety of problems. Interpret and use force vs. time graphs. Apply conservation of momentum to solve a variety of problems. Distinguish between elastic and inelastic collisions. Calculate the center of mass for a system of point particles. Unit #4 Momentum

Types of Collisions • When objects collide, a number of different things can happen depending on the characteristics of the colliding objects. Of course, you know that momentum is always conserved in a closed system. Imagine, though, the differences in a collision if the two objects colliding are super-bouncy balls compared to two lumps of clay. In the first case, the balls would bounce off each other. In the second, they would stick together and become, in essence, one object. Obviously, you need more ways to characterize collisions. • Elastic collisions occur when the colliding objects bounce off of each other. This typically occurs when you have colliding objects which are very hard or bouncy. Officially, an elastic collision is one in which the sum of the kinetic energy of all the colliding objects before the event is equal to the sum of the kinetic energy of all the objects after the event. Put more simply, kinetic energy is conserved in an elastic collisions. • Elastic Collision Equation (General): m 1 v 1 + m 2 v 2 = m 1 v 1’ + m 2 v 2’ ***The (v’) indicates after the collision, Unit #4 Momentum ΣKEbefore = ΣKEafter

Types of Collisions • Inelastic collisions occur when two objects collide and kinetic energy is not conserved. In this type of collision some of the initial kinetic energy is converted into other types of energy (heat, sound, etc. ), which is why kinetic energy is NOT conserved in an inelastic collision. In a perfectly inelastic collision, the two objects colliding stick together. • In reality, most collisions fall somewhere between the extremes of a completely elastic collision and a completely inelastic collision. • Completely Inelastic Collision Equation (General): m 1 v 1 + m 2 v 2 = (m 1 + m 2)v’ ***The (v’) indicates after the collision • Unit #4 Momentum ΣKEbefore ≠ ΣKEafter also KE = ½ mv 2

Sample Problem #1 • Question: Two billiard balls collide. Ball 1 moves with a velocity of 4 m/s, and ball 2 is at rest. After the collision, ball 1 comes to a complete stop. What is the velocity of ball 2 after the collision? Is this collision elastic or inelastic? The mass of each ball is 0. 16 kg. • Answer: To find the velocity of ball 2, use a momentum table. Unit #4 Momentum

Sample Problem #1 • Question: Two billiard balls collide. Ball 1 moves with a velocity of 4 m/s, and ball 2 is at rest. After the collision, ball 1 comes to a complete stop. What is the velocity of ball 2 after the collision? Is this collision elastic or inelastic? The mass of each ball is 0. 16 kg. • Answer: To find the velocity of ball 2, use a momentum table. Unit #4 Momentum

Sample Problem #1 • Question: Two billiard balls collide. Ball 1 moves with a velocity of 4 m/s, and ball 2 is at rest. After the collision, ball 1 comes to a complete stop. What is the velocity of ball 2 after the collision? Is this collision elastic or inelastic? The mass of each ball is 0. 16 kg. Unit #4 Momentum

Collisions in 2 Dimensions • Much like the key to projectile motion, or two-dimensional kinematics problems, was breaking up vectors into their x- and y-components, the key to solving twodimensional collision problems involves breaking up momentum vectors into x- and y - components. The law of conservation of momentum then states that momentum is independently conserved in both the x- and y- directions. • Therefore, you can solve two-dimensional collision problems by creating a separate momentum table for the x-component of momentum before and after the collision, and a momentum table for the y-component of momentum. Unit #4 Momentum

Sample Problem #2 • Question: Bert strikes a cue ball of mass 0. 17 kg, giving it a velocity of 3 m/s in the xdirection. When the cue ball strikes the eight ball (mass=0. 16 kg), previously at rest, the eight ball is deflected 45 degrees from the cue ball’s previous path, and the cue ball is deflected 30 degrees in the opposite direction. Find the velocity of the cue ball and the eight ball after the collision. Unit #4 Momentum

Sample Problem #2 • Answer: Start by making momentum tables for the collision, beginning with the xdirection. Since you don’t know the velocity of the balls after the collision, call the velocity of the cue ball after the collision vc, and the velocity of the eight ball after the collision v 8. Note that you must use trigonometry to determine the x-component of the momentum of each ball after the collision. Since the total momentum in the x-direction before the collision must equal the total momentum in the x-direction after the collision, you can set the total before and total after columns equal: Unit #4 Momentum

Sample Problem #2 • Next, create a momentum table and algebraic equation for the conservation of momentum in the y-direction. Unit #4 Momentum

Sample Problem #2 • You now have two equations with two unknowns. To solve this system of equations, start by solving the y-momentum equation for vc. • You can now take this equation for vc and substitute it into the equation for conservation of momentum in the x-direction, effectively eliminating one of the unknowns, and giving a single equation with a single unknown. • Finally, solve for the velocity of the cue ball after the collision by substituting the known value for v 8 into the result of the y-momentum equation. Unit #4 Momentum