Ch 6 Gravitation Newtons Synthesis This cartoon mixes

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Ch. 6: Gravitation & Newton’s Synthesis This cartoon mixes two legends: 1. The legend

Ch. 6: Gravitation & Newton’s Synthesis This cartoon mixes two legends: 1. The legend of Newton, the apple & gravity which led to the Universal Law of Gravitation. 2. The legend of William Tell & the apple.

 • It was very SIGNIFICANT & PROFOUND in the 1600's when Sir Isaac

• It was very SIGNIFICANT & PROFOUND in the 1600's when Sir Isaac Newton first wrote Newton's Universal Law of Gravitation! This was done at the young age of about 30. It was this, more than any of his other achievements, which caused him to be well-known in the world scientific community of the late 1600's. • He used this law, along with Newton's 2 nd Law (his 2 nd Law!) plus Calculus, which he also (co-) invented, to PROVE that the orbits of the planets around the sun must be ellipses. – For simplicity, we will assume in Ch. 6 that these orbits are circular. • Ch. 6 fits THE COURSE THEME OF NEWTON'S LAWS OF MOTION because Newton used his Gravitation Law & his 2 nd Law in his analysis of planetary motion. • His prediction that planetary orbits are elliptical is in excellent agreement with Kepler's analysis of observational data & with Kepler's empirical laws of planetary motion.

 • When Newton first wrote the Universal Law of Gravitation, it was the

• When Newton first wrote the Universal Law of Gravitation, it was the first time, anyone had EVER written a theoretical expression (physics in math form) & used it to PREDICT something that is in agreement with observations! For this reason, Newton's Formulation of his Universal Gravitation Law is considered THE BEGINNING OF THEORETICAL PHYSICS. • It also gave Newton his major “claim to fame”. After this, he was considered to be a “major leader” in science & math among his peers. • In modern times, this, plus the many other things he did, have led to the consensus that Sir Isaac Newton was the GREATEST SCIENTIST WHO EVER LIVED

Newton’s Grave & a Monument to him are in Westminster Abbey in London, England.

Newton’s Grave & a Monument to him are in Westminster Abbey in London, England.

Inscription on Newton’s Gravestone: “Here is buried Isaac Newton, Knight, who by a strength

Inscription on Newton’s Gravestone: “Here is buried Isaac Newton, Knight, who by a strength of mind almost divine, and mathematical principles peculiarly his own, explored the course and figures of the planets, the paths of comets, the tides of the sea, the dissimilarities in rays of light, and, what no other scholar has previously imagined, the properties of the colors thus produced. Diligent, sagacious and faithful, in his expositions of nature, antiquity and the holy Scriptures, he vindicated by his philosophy the majesty of God mighty and good, and expressed the simplicity of the Gospel in his manners. Mortals rejoice that there has existed such and so great an ornament of the human race! He was born on 25 th December, 1642, and died on 20 th March 1727. Newton’s Monument in Westminster Abbey.

Sect. 6 -1: Newton’s Universal Law of Gravitation • This is an EXPERIMENTAL LAW

Sect. 6 -1: Newton’s Universal Law of Gravitation • This is an EXPERIMENTAL LAW describing the gravitational force of attraction between 2 objects. • Newton’s reasoning: the Gravitational force of attraction between 2 large objects (Earth - Moon, etc. ) is the SAME force as the attraction of objects to the Earth. • Apple story: This is likely not a true historical account, but the reasoning discussed there is correct. This story is probably legend rather than fact.

If the force of gravity is being exerted on objects on Earth, What is

If the force of gravity is being exerted on objects on Earth, What is the Origin of that Force? Newton’s realization was that the force must come from the Earth itself! He further realized that this same force must be what keeps the Moon in its orbit!

The gravitational force on you is half of a Newton’s 3 rd Law pair:

The gravitational force on you is half of a Newton’s 3 rd Law pair: Earth exerts a downward force on you, & you exert an upward force on Earth. When there is such a large difference in the 2 masses, the reaction force (the force you exert on the Earth) is undetectable, but for 2 objects with masses closer in size to each other, it can be significant. This must be true from Newton’s 3 rd Law! The Force of Attraction between 2 small masses is the same as the force between Earth & Moon, Earth & Sun, etc.

By observing planetary orbits, Newton also concluded that the gravitational force decreases as the

By observing planetary orbits, Newton also concluded that the gravitational force decreases as the inverse of the square of the distance r between the masses. Newton’s Universal Law of Gravitation: “Every particle in the Universe attracts every other particle in the Universe with a force that is proportional to the product of their masses & inversely proportional to the square of the distance between them: F 12 = -F 21 [(m 1 m 2)/r 2] This must be true from Newton’s 3 rd Law! The direction of this force: Along the line joining the 2 masses

Newton’s Universal Gravitation Law • This force is written as: G a constant, the

Newton’s Universal Gravitation Law • This force is written as: G a constant, the Universal Gravitational Constant G is measured & is the same for ALL objects. G must be small! • The measurement of G in the lab is tedious & sensitive because it is so small. – First done by Cavendish in 1789. • Modern version of Cavendish experiment: Two small masses are fixed at the ends of a light horizontal rod. Two larger masses are placed near the smaller ones. • The angle of rotation is measured. • Use Newton’s 2 nd Law to get the vector force between the masses. Relate to angle of rotation & can extract G. Cavendish Measurement Apparatus

 • G = the Universal Gravitational Constant • Measurements Find, in SI Units:

• G = the Universal Gravitational Constant • Measurements Find, in SI Units: • The force given above is strictly valid only for: – Very small masses m 1 & m 2 (point masses) – Uniform spheres • For other objects: We need integral calculus!

 • The Universal Law of Gravitation is an example of an Inverse Square

• The Universal Law of Gravitation is an example of an Inverse Square Law – The magnitude of the force varies as the inverse square of the separation of the particles • The law can also be expressed in vector form The negative sign means it’s an attractive force • Aren’t we glad it’s not repulsive?

Comments Force exerted by particle 1 on particle 2 21 Force exerted by particle

Comments Force exerted by particle 1 on particle 2 21 Force exerted by particle 2 on particle 1 F 21 = - F 12 This tells us that the forces form a Newton’s 3 rd Law action-reaction pair, as expected. The negative sign in the above vector equation tells us that particle 2 is attracted toward particle 1

More Comments • Gravity is a “field force” that always exists between two masses,

More Comments • Gravity is a “field force” that always exists between two masses, regardless of the medium between them. • The gravitational force decreases rapidly as the distance between the two masses increases – This is an obvious consequence of the inverse square law

Example 6 -1: Gravitational Force Between 2 People A 50 -kg person & a

Example 6 -1: Gravitational Force Between 2 People A 50 -kg person & a 70 -kg person are sitting on a bench close to each other. Estimate the magnitude of the gravitational force each exerts on the other.

Example 6 -2: Spacecraft at 2 r. E • Spacecraft at twice the Earth

Example 6 -2: Spacecraft at 2 r. E • Spacecraft at twice the Earth radius Earth Radius: r. E = 6320 km Earth Mass: ME = 5. 98 1024 kg ME m

Example 6 -2: Spacecraft at 2 r. E • Spacecraft at twice the Earth

Example 6 -2: Spacecraft at 2 r. E • Spacecraft at twice the Earth radius Earth Radius: r. E = 6320 km Earth Mass: ME = 5. 98 1024 kg FG = G(m. ME/r 2) • At surface (r = r. E) FG = weight = mg = G[m. ME/(r. E)2] • At r = 2 r. E ME FG = G[m. ME/(2 r. E)2] = (¼)mg = 4900 N m

Example 6 -3: Force on the Moon Find the net force on the Moon

Example 6 -3: Force on the Moon Find the net force on the Moon due to the gravitational attraction of both the Earth & the Sun, assuming they are at right angles to each other. ME= 5. 99 1024 kg MM=7. 35 1022 kg MS = 1. 99 1030 kg r. ME = 3. 85 108 m r. MS = 1. 5 1011 m F = FME + FMS (vector sum!)

F = FME + FMS (vector sum!) FME = G [(MMME)/(r. ME)2] = 1.

F = FME + FMS (vector sum!) FME = G [(MMME)/(r. ME)2] = 1. 99 1020 N FMS = G [(MMMS)/(r. MS)2] = 4. 34 1020 N F =[ (FME)2 + (FMS)2]� = 4. 77 1020 N tan(θ) = 1. 99/4. 34 θ = 24. 6º

Gravitational Force Due to a Mass Distribution • In can be shown, with integral

Gravitational Force Due to a Mass Distribution • In can be shown, with integral calculus, that: The gravitational force exerted by a SPHERICALLY SYMMETRIC mass distribution of uniform density on a particle outside the distribution is the same as if the entire mass of the distribution were concentrated at the center. • So, assuming that the Earth is such a sphere, the gravitational force exerted by the Earth on a particle of mass m on or near the Earth’s surface is FG = G[(m. ME)/r 2]; ME Earth Mass, r. E Earth Radius • Similarly, to treat the gravitational force due to large spherical shaped objects, it can be shown with calculus, that: 1) If a (point) particle is outside a thin spherical shell, the gravitational force on the particle is the same as if all the mass of the sphere were at center of shell. 2) If a (point) particle is inside a thin spherical shell, the gravitational force on the particle is zero. So, we can model a sphere as a series of thin shells. For a mass outside any large spherically symmetric mass, the gravitational force acts as though all the mass of the sphere is at the sphere’s center.

Sect. 6 -2: Vector Form of Universal Gravitation Law In vector form, The figure

Sect. 6 -2: Vector Form of Universal Gravitation Law In vector form, The figure gives the directions of the displacement & force vectors. If there are many particles, the total force is the vector sum of the individual forces:

Example: Billiards (Pool) • 3 billiard (pool) balls, masses m 1 = m 2

Example: Billiards (Pool) • 3 billiard (pool) balls, masses m 1 = m 2 = m 3 = 0. 3 kg on a table as in the figure. Triangle sides: a = 0. 4 m, b = 0. 3 m, c = 0. 5 m. Calculate the magnitude & direction of the total gravitational force F on m 1 due to m 2 & m 3. Note: Gravitational force is a vector, so we have to add the vectors F 21 & F 31 to get the vector F (using the vector addition methods of earlier). F = F 21 + F 31 Using components: So, Fx = F 21 x + F 31 x = 0 + 6. 67 10 -11 N Fy = F 21 y + F 31 y = 3. 75 10 -11 N + 0 F = [(Fx)2 + (Fy)2]½ = 3. 75 10 -11 N tanθ = 0. 562, θ = 29. 3º