2 3 Differentiation Formulas Differentiation Formulas Lets start

  • Slides: 32
Download presentation
2. 3 Differentiation Formulas

2. 3 Differentiation Formulas

Differentiation Formulas Let’s start with the simplest of all functions, the constant function f

Differentiation Formulas Let’s start with the simplest of all functions, the constant function f (x) = c. The graph of this function is the horizontal line y = c, which has slope 0, so we must have f (x) = 0. The graph of f (x) = c is the line y = c, so f (x) = 0. 2

Constant Rule Using the formal definition of derivative: 3

Constant Rule Using the formal definition of derivative: 3

Power Rule For functions f (x) = xn, where n is a positive integer:

Power Rule For functions f (x) = xn, where n is a positive integer: 4

Proof by formal definition of derivative: For n = 4 we find the derivative

Proof by formal definition of derivative: For n = 4 we find the derivative of f (x) = x 4 as follows: (x 4) = 4 x 3 5

Practice: Find each derivative (a) If f (x) = x 6 (b) If y

Practice: Find each derivative (a) If f (x) = x 6 (b) If y = x 1000 (c) If y = t 4 (d) (r 3) 6

Extended Power Rule 7

Extended Power Rule 7

PROPERTIES AND RULES OF DERIVATIVES 8

PROPERTIES AND RULES OF DERIVATIVES 8

Constant Multiple Rule 9

Constant Multiple Rule 9

Sum Rule the derivative of a sum of functions is the sum of the

Sum Rule the derivative of a sum of functions is the sum of the derivatives. 10

Difference Rule 11

Difference Rule 11

Example: (x 8 + 12 x 5 – 4 x 4 + 10 x

Example: (x 8 + 12 x 5 – 4 x 4 + 10 x 3 – 6 x + 5) = (x 8) + 12 (x 5) – 4 (x 4) + 10 (x 3) – 6 (x) + (5) = 8 x 7 + 12(5 x 4) – 4(4 x 3) + 10(3 x 2) – 6(1) + 0 = 8 x 7 + 60 x 4 – 16 x 3 + 30 x 2 – 6 12

Product Rule Or: the derivative of a product of two functions is the first

Product Rule Or: the derivative of a product of two functions is the first function times the derivative of the second function plus the second function times the derivative of the first function. 13

Quotient Rule Or: the derivative of a quotient is the denominator times the derivative

Quotient Rule Or: the derivative of a quotient is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the square of the denominator. 14

Example: Let . Then 15

Example: Let . Then 15

Use quotient rule? Don’t use the Quotient Rule every time you see a quotient.

Use quotient rule? Don’t use the Quotient Rule every time you see a quotient. Sometimes, when there is only ONE term in the quotient, it’s easier to rewrite the expression as a sum of power terms, then use the power rule. Example: f(x) = We can use the quotient rule but it is much easier to perform the division first and write the function as: f(x) = 3 x + 2 x – 1 2 16

Examples: (a) If y = , then = –x – 2 = (b) 17

Examples: (a) If y = , then = –x – 2 = (b) 17

Practice: Differentiate the function f (t) = (a + bt). Solution 1: Using the

Practice: Differentiate the function f (t) = (a + bt). Solution 1: Using the Product Rule, we have 18

Practice – Solution 2 cont’d If we first use the laws of exponents to

Practice – Solution 2 cont’d If we first use the laws of exponents to rewrite f (t), then we can proceed directly without using the Product Rule. 19

Normal line at a point: The differentiation rules enable us to find tangent lines

Normal line at a point: The differentiation rules enable us to find tangent lines without having to resort to the definition of a derivative. They also enable us to find normal lines. The normal line to a curve C at point P is the line through P that is perpendicular to the tangent line at P. 20

Example: Find equations of the tangent line and normal line to the curve y

Example: Find equations of the tangent line and normal line to the curve y = (1 + x 2) at the point (1, ). Solution: According to the Quotient Rule, we have 21

Example – Solution cont’d So the slope of the tangent line at (1, )

Example – Solution cont’d So the slope of the tangent line at (1, ) is We use the point-slope form to write an equation of the tangent line at (1, ): y– = – (x – 1) or y= 22

Example – Solution cont’d The slope of the normal line at (1, ) is

Example – Solution cont’d The slope of the normal line at (1, ) is the negative reciprocal of , namely 4, so an equation is y– = 4(x – 1) or y = 4 x – The curve and its tangent and normal lines are graphed in Figure 5 23

Summary of Rules 24

Summary of Rules 24

2. 4 Derivatives of Trig Functions 25

2. 4 Derivatives of Trig Functions 25

26

26

27

27

Example 1 Differentiate y = x 2 sin x. Solution: Using the Product Rule

Example 1 Differentiate y = x 2 sin x. Solution: Using the Product Rule 28

Example 2 An object at the end of a vertical spring is stretched 4

Example 2 An object at the end of a vertical spring is stretched 4 cm beyond its rest position and released at time t = 0 (note that the downward direction is positive. ) Its position at time t is s = f (t) = 4 cos t Find the velocity and acceleration at time t and use them to analyze the motion of the object. 29

Example 2 – Solution The velocity and acceleration are 30

Example 2 – Solution The velocity and acceleration are 30

Example 2 – Solution cont’ The object oscillates from the lowest point (s =

Example 2 – Solution cont’ The object oscillates from the lowest point (s = 4 cm) to the highest point (s = – 4 cm). The period of the oscillation is 2 , which is the period of cos t. 31

Example 2 – Solution cont’d The speed is | v | = 4 |

Example 2 – Solution cont’d The speed is | v | = 4 | sin t |, which is greatest when | sin t | = 1, that is, when cos t = 0. So the object moves fastest as it passes through its equilibrium position (s = 0). Its speed is 0 when sin t = 0, that is, at the high and low points. The acceleration a = – 4 cos t = 0 when s = 0. It has greatest magnitude at the high and low points. 32