Medians and Altitudes Use Medians and Altitudes A


















- Slides: 18
Medians and Altitudes
Use Medians and Altitudes A median of a triangle is a segment from a vertex to the midpoint of the opposite side.
The point of concurrency of the medians of a triangle is the centroid of the triangle. The centroid is always inside the triangle. The centroid is also called the center of gravity because it is the point where a triangular region will balance.
Example: Using the Centroid to Find Segment Lengths In ∆LMN, RL = 21 and SQ =4. Find LS. Centroid Thm. Substitute 21 for RL. LS = 14 Simplify.
Example: Using the Centroid to Find Segment Lengths In ∆LMN, RL = 21 and SQ =4. Find NQ. 12 = NQ
Use Medians and Altitudes Example 1: Use the centroid of a triangle In Triangle RST, Q is the centroid and SQ = 8. Find QW and SW.
Use Medians and Altitudes Example 2: Use the centroid of a triangle In Triangle HJK, P is the centroid and JP = 12. Find PT and JT.
Use Medians and Altitudes Example 3: Use the centroid of a triangle The vertices of Triangle FGH are F(2, 5), G(4, 9), and H(6, 1). Which ordered pair gives the coordinates of the centroid P of Triangle FGH?
Use Medians and Altitudes An altitude of a triangle is the perpendicular segment from a vertex to the opposite side or to the line that contains the opposite side.
Use Medians and Altitudes The point at which the lines containing the three altitudes of a triangle intersect is called the orthocenter of the triangle.
Use Medians and Altitudes The orthocenter is located in different areas depending on what type of triangle you have.
Example 3: Finding the Orthocenter Find the orthocenter of ∆XYZ with vertices X(3, – 2), Y(3, 6), and Z(7, 1). Step 1 Graph the triangle. X
Example 3 Continued Step 2 Find an equation of the line containing the altitude from Z to XY. Since XY is vertical, the altitude is horizontal. The line containing it must pass through Z(7, 1) so the equation of the line is y = 1.
Example 3 Continued Step 3 Find an equation of the line containing the altitude from Y to XZ. The slope of a line perpendicular to XZ is pass through Y(3, 6). . This line must Point-slope form. Substitute 6 for y 1, x 1. Distribute . Add 6 to both sides. for m, and 3 for
Example 3 Continued Step 4 Solve the system to find the coordinates of the orthocenter. Substitute 1 for y. Subtract 10 from both sides. 6. 75 = x Multiply both sides by The coordinates of the orthocenter are (6. 75, 1).
Altitude. . Vertex. . 90°. . Orthocenter Angle Bisector. . Angle into 2 equal angles. . Incenter Perpendicular Bisector… 90°. . bisects side. . Circumcenter Median. . Vertex. . Midpoint of side. . Centroid
Give the best name for AB A | B B Median Altitude A A | | B B Angle Perp Bisector
Vocabulary Review Circumcenter – Point where three perpendicular bisectors of a triangle intersect. Incenter – Point where three angle bisectors of a triangle intersect. Centroid (Center of Gravity) – Point where three medians of a triangle intersect. Orthocenter – Point where three altitudes of a triangle intersect.


















