EVERYTHING YOU NEED TO KNOW TO GET A

EVERYTHING YOU NEED TO KNOW TO GET A GRADE C GEOMETRY & MEASURES (FOUNDATION) AUTHOR

2. 5 -1

70° 40° 70° Alternate angles are equal Angles on a straight line add up 180° - 110° = 70° Angles in a triangle add up 180° - 40° - 70° = 70° As both base angles are 70°, triangle BEF is isosceles.

55° Alternate angles are equal Angles in a triangle add up 180° - 70° - 55° = 55° As both base angles are 55°, triangle ABC is isosceles.

41° 113° 41 Interior angles add up to 180° - 67° = 113° 113

2 4 cm 3 cm 4 cm 6 cm 2 cm OTHER ANSWERS ALSO ALLOWED 6 cm Perimeter of rectangle A = 14 cm Perimeter of rectangle B = 16 cm Difference = 16 cm - 14 cm 2 Perimeter is the length around a shape

6 cm 4 cm Perimeter is the length around a shape 4 cm 6 cm Perimeter of rectangle = 6 cm + 4 cm + 6 cm + 4 cm 20 Square has 4 equal sides 3 cm for each side

x x OTHER ANSWERS ALSO ALLOWED Because two lengths of 12 cm makes 24 cm which is more than the perimeter As evident from the rectangle drawn for part (a)

20 cm 40 cm 1 cm 20 cm 40 cm 10 cm 4 cm 8 cm 4 cm 10 cm 2 cm 5 cm 8 cm Find the only rectangle which has a perimeter of 26 cm 8 5

Kilo means a thousand 1 km = 1000 m Area = Length x Width = 1000 m x 10 m Rectangle A Split compound shape into two rectangles 200 m Rectangle B Area of rectangle A = 100 x 30 Area of rectangle B = 200 x a 35 200 a + 3000 = 10000 200 a = 7000

Count the number of squares to find the area C B E

ter Dia me 30 cm Shaded Area = Area of square – Area of circle LEARN THE FORMULAE OFF BY HEART Area of square = length x width = 80 cm x 80 cm Area of circle = = 3. 14 x 30 cm Area shaded = 6400 - 2826 3574

equal to less than (because the length around the shape is the same) (because more than half the rectangle is unshaded)

10 cm Shaded Area = Area of big square ABCD – Area of the 4 congruent (identical) triangles Area of big square = length x width = 10 cm x 10 cm Area of one triangle = Area of four triangles = 82 Shaded area =

Area of small square = 30 cm x 30 cm 900 Length of large square = 50 Area of floor = 300 cm x 180 cm Number of small tiles needed = 60

Perimeter A = 10 cm m 2 c 2 cm Perimeter B = 9 cm Perimeter is the length around a shape 2 cm m 2 c Perimeter C = 10 cm Perimeter of D = 2 cm + 2 cm 8 A and C C and D Area is the space inside a shape

Shaded Area = Area of big square – Area of two smaller squares Area of big square = length x width = 12 cm x 12 cm Area of one small square = length x width = 4 cm x 4 cm Area of both squares = Shaded Area = Area of big square = length x width Area of one small square = length x width Area of both squares = Unshaded Shaded Area = Fraction shaded =

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A, B and E