Drawing Motion Graphs Level 1 Convert the following

Drawing Motion Graphs = Level 1 = Convert the following Displacement vs. Time graphs into Velocity vs. Time graphs d v 7 6 7 6 5 5 4 3 2 1 0 0 1 2 3 4 5 6 7 0 1 4 3 4 3 2 2 1 0 -1 -2 -3 0 1 2 3 4 5 6 7 2 3 4 5 6 7

Drawing Motion Graphs = Level 2 = Convert the following Velocity vs. Time graphs into Displacement vs. Time graphs d v 7 6 7 6 5 5 4 3 2 1 0 0 1 2 3 4 5 6 7 0 1 4 3 4 3 2 2 1 0 -1 -2 -3 0 1 2 3 4 5 6 7 2 3 4 5 6 7

Drawing Motion Graphs = Level 3 = Convert the following Displacement vs. Time graphs into Velocity vs. Time graphs d v 7 6 7 6 5 5 4 3 2 1 0 0 1 2 3 4 5 6 7 0 1 4 3 4 3 2 2 1 0 -1 -2 -3 0 1 2 3 4 5 6 7 2 3 4 5 6 7

Velocity (m/s) 4 3 What is the acceleration between 2 -5 seconds? 2 1 0 -1 -2 -3 What the total displacement represented in this graph? 0 1 2 3 4 5 6 7 Velocity (m/s) Time (s) 4 3 What is the acceleration between 2 -5 seconds? 2 1 0 -1 -2 -3 What the total displacement represented in this graph? 0 1 2 3 4 5 6 7 Time (s)

Velocity (m/s) 4 3 During which interval is it moving in the negative direction? 2 1 0 -1 -2 -3 What the total displacement represented in this graph? 0 1 2 3 4 5 6 7 Velocity (m/s) Time (s) 4 3 What is the significance of the point at 6 seconds? 2 1 0 -1 -2 -3 What the total displacement represented in this graph? 0 1 2 3 4 5 6 7 Time (s)

Velocity (m/s) 4 3 Describe the motion between 0 -6 seconds 2 1 0 -1 -2 -3 What the total displacement represented in this graph? 0 1 2 3 4 5 6 7 Velocity (m/s) Time (s) 4 3 Describe the motion between 0 -6 seconds 2 1 0 -1 -2 -3 What the total displacement represented in this graph? 0 1 2 3 4 5 6 7 Time (s)

=Solutions=

Drawing Motion Graphs = Level 1 = Convert the following Displacement vs. Time graphs into Velocity vs. Time graphs 1 0 1 2 /s m 3 4 5 6 7 4 3 2 1 0 0 1 2 3 4 5 6 7 4 3 2 1 0 0 m/s 1 0 1 2 /s m 3 4 5 6 7 m 0. 5 5 4 3 2 1 0 /s 7 6 5 3 m /s 5 7 6 0 m/s 0 1 4 3 4 3 2 2 1 0 -1 -2 -3 0 1 2 3 4 5 6 7 -3 m 5 0 m/s s m/ v 7 6 -2 d 7 6 0 1 2 3 4 5 6 7

Drawing Motion Graphs = Level 2 = Convert the following Velocity vs. Time graphs into Displacement vs. Time graphs 5 6 7 2 3 4 5 6 7 0 1 4 3 4 3 2 2 1 0 -1 -2 -3 0 1 2 3 4 5 6 7 s /s 0 1 4 3 2 1 0 0 1 4 m/ 3 m 5 6 7 4 3 2 1 0 /s 3 4 4 3 2 1 0 m/s 0 0 1 2 3 4 m 2 /s 0 m/s 5 -1 0 1 m 7 6 s 4 3 2 1 0 -1 5 2 m 5 /s 5 0 m/s 7 6 m/ v 7 6 -2 d 7 6 2 3 4 5 6 7

Drawing Motion Graphs = Level 3 = Convert the following Displacement vs. Time graphs into Velocity vs. Time graphs 4 3 2 1 0 4 3 2 2 1 0 -1 -2 -3 0 1 2 3 4 5 6 7 Changes Direction 0 1 2 3 4 5 6 7 /s /s 3 m /s m m 0 1 2 3 4 5 6 7 /s 5 -1 7 6 0 1 4 3 2 2 1 0 -1 -2 -3 0 1 2 3 4 5 6 7 2 m 5 1 2 m 5 6 7 5 0 m/s s 4 3 2 0 m/s 1 0 0 1 2 3 4 7 6 m/ v 5 7 6 -2 d /s 7 6 2 3 4 5 6 7 Changes Direction 0 1 2 3 4 5 6 7

Velocity (m/s) 4 3 1 0 -1 -2 -3 2 4 2 Acceleration = slope = 0. 5 m/s 2 (or 0. 5 m/s/s) What the total displacement represented in this graph? 0 1 3 4 2 5 6 7 Velocity (m/s) Time (s) 4 3 Displacement = area = (½)(4)(2)+(1)(2) = 6 m What is the acceleration between 2 -5 seconds? 2 2 1 0 -1 -2 -3 What is the acceleration between 2 -5 seconds? -2 0 1 2 Acceleration = slope = 0 m/s 2 (or 0 m/s/s) What the total displacement represented in this graph? 3 4 5 6 7 Time (s) Displacement = area = (½)(2)(-2) + (½)(2)(2) =0 m

Velocity (m/s) 4 3 During which interval is it moving in the negative direction? 2 1 0 -1 -2 -3 -4 -1 0 1 2 3 4 Velocity is negative from 4 s to 7 s What the total displacement represented in this graph? 5 6 7 Time (s) Displacement = area = (½)(1)(-2) + (2)(-2) Velocity (m/s) = -5 m 4 3 1 0 -1 -2 -3 4 2 2 -1 0 1 2 3 4 What is the significance of the point at 6 seconds? This is when the object changes direction What the total displacement represented in this graph? 5 6 7 Time (s) Displacement = area = (½)(1)(4) + (½)(2)(4) + (½)(1)(-2) = 5 m

Velocity (m/s) 4 3 Describe the motion between 0 -6 seconds 1 1 2 1 0 -1 -2 -3 -4 0 1 2 3 4 Moving backward (negative velocity) from 0 -4 s Moving forward (positive velocity) from 4 -6 s What the total displacement represented in this graph? 5 6 7 Time (s) Displacement = area Velocity (m/s) = (½)(4)(-2) + (½)(2)(1) + (1)(1) = -2 m 4 3 4. 5 2 1 0 -1 -2 -3 Describe the motion between 0 -6 seconds -1 -4. 5 0 1 2 3 4 5 Time (s) -1 6 7 Moving forward (positive velocity) from 0 -3 s Moving backward (negative velocity) from 4 -6 s What the total displacement represented in this graph? Displacement = area = (½)(3)(3) + (½)(3)(-3) + (1)(1) + (½)(1)(-2) = -2 m