10 Parametric Equations and Polar Coordinates Copyright Cengage

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10 Parametric Equations and Polar Coordinates Copyright © Cengage Learning. All rights reserved.

10 Parametric Equations and Polar Coordinates Copyright © Cengage Learning. All rights reserved.

10. 4 Areas and Lengths in Polar Coordinates Copyright © Cengage Learning. All rights

10. 4 Areas and Lengths in Polar Coordinates Copyright © Cengage Learning. All rights reserved.

Areas and Lengths in Polar Coordinates In this section we develop the formula for

Areas and Lengths in Polar Coordinates In this section we develop the formula for the area of a region whose boundary is given by a polar equation. We need to use the formula for the area of a sector of a circle: A = r 2 where, as in Figure 1, r is the radius and is the radian measure of the central angle. Figure 1 3

Areas and Lengths in Polar Coordinates Formula 1 follows from the fact that the

Areas and Lengths in Polar Coordinates Formula 1 follows from the fact that the area of a sector is proportional to its central angle: A = ( /2 ) r 2 = r 2. 4

Areas and Lengths in Polar Coordinates Let be the region, illustrated in Figure 2,

Areas and Lengths in Polar Coordinates Let be the region, illustrated in Figure 2, bounded by the polar curve r = f ( ) and by the rays = a and = b, where f is a positive continuous function and where 0 < b – a 2. Figure 2 We divide the interval [a, b] into subintervals with endpoints 0, 1, 2, . . . , n and equal width . 5

Areas and Lengths in Polar Coordinates The rays = i then divide into n

Areas and Lengths in Polar Coordinates The rays = i then divide into n smaller regions with central angle = i – 1. If we choose in the ith subinterval [ i – 1, i], then the area Ai of the ith region is approximated by the area of the sector of a circle with central angle and radius f ( ). (See Figure 3. ) Figure 3 6

Areas and Lengths in Polar Coordinates Thus from Formula 1 we have Ai [f

Areas and Lengths in Polar Coordinates Thus from Formula 1 we have Ai [f ( )]2 and so an approximation to the total area A of is It appears from Figure 3 that the approximation in (2) improves as n . 7

Areas and Lengths in Polar Coordinates But the sums in (2) are Riemann sums

Areas and Lengths in Polar Coordinates But the sums in (2) are Riemann sums for the function g( ) = [f ( )]2, so It therefore appears plausible that the formula for the area A of the polar region is 8

Areas and Lengths in Polar Coordinates Formula 3 is often written as with the

Areas and Lengths in Polar Coordinates Formula 3 is often written as with the understanding that r = f ( ). Note the similarity between Formulas 1 and 4. When we apply Formula 3 or 4 it is helpful to think of the area as being swept out by a rotating ray through O that starts with angle a and ends with angle b. 9

Example 1 Find the area enclosed by one loop of the four-leaved rose r

Example 1 Find the area enclosed by one loop of the four-leaved rose r = cos 2. Solution: Notice from Figure 4 that the region enclosed by the right loop is swept out by a ray that rotates from = – /4 to = /4. Figure 4 10

Example 1 – Solution cont’d Therefore Formula 4 gives 11

Example 1 – Solution cont’d Therefore Formula 4 gives 11

Example 1 – Solution cont’d 12

Example 1 – Solution cont’d 12

Arc Length 13

Arc Length 13

Arc Length To find the length of a polar curve r = f (

Arc Length To find the length of a polar curve r = f ( ), a b, we regard as a parameter and write the parametric equations of the curve as x = r cos = f ( ) cos y = r sin = f ( ) sin Using the Product Rule and differentiating with respect to , we obtain 14

Arc Length So, using cos 2 + sin 2 = 1, we have 15

Arc Length So, using cos 2 + sin 2 = 1, we have 15

Arc Length Assuming that f is continuous, we can write the arc length as

Arc Length Assuming that f is continuous, we can write the arc length as Therefore the length of a curve with polar equation r = f ( ), a b, is 16

Example 4 Find the length of the cardioid r = 1 + sin .

Example 4 Find the length of the cardioid r = 1 + sin . Solution: The cardioid is shown in Figure 8. r = 1 + sin Figure 8 17

Example 4 – Solution cont’d Its full length is given by the parameter interval

Example 4 – Solution cont’d Its full length is given by the parameter interval 0 2 , so Formula 5 gives 18

Example 4 – Solution cont’d We could evaluate this integral by multiplying and dividing

Example 4 – Solution cont’d We could evaluate this integral by multiplying and dividing the integrand by , or we could use a computer algebra system. In any event, we find that the length of the cardioid is L = 8. 19