10 A hiker undergoes a displacement of d

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10. A hiker undergoes a displacement of d 5 as shown in the figure

10. A hiker undergoes a displacement of d 5 as shown in the figure above. A single displacement that would return the hiker to his starting point would have which of the following sets of components? a. +d 5, x; +d 5, y c. d 5, x; +d 5, y b. +d 5, x; d 5, y d. d 5, x; d 5, y

5 meters east in 2 seconds Distance vs Displacement 3 meters south in 1

5 meters east in 2 seconds Distance vs Displacement 3 meters south in 1 second The total distance d traveled is 8 m The total displacement 5. 8 m 310 south of east Speed = d / t = v Velocity= d / t = v d is The displacement includes the direction! So if you want to go back it’s the negative vector – x or – y regardless of the original direction

Vector mathematics is different than scalar mathematics Scalars are just numbers and can be

Vector mathematics is different than scalar mathematics Scalars are just numbers and can be added with regular math. They add up to a sum. Vectors have direction and must be drawn to scale and connected head-to-tail. They add up to a resultant. HEAD Tail Start Finish

Homework questions

Homework questions

 • Luke drops a pile of roof shingles from the top of a

• Luke drops a pile of roof shingles from the top of a roof located 8. 52 meters above the ground. Determine the time required for the shingles to reach the ground.

Rex throws his mother's crystal vase vertically upwards with an initial velocity of 26.

Rex throws his mother's crystal vase vertically upwards with an initial velocity of 26. 2 m/s. Determine the height to which the vase will rise above its initial height. vf 2 = vi 2 + 2 • a • d (0 m/s)2 = (26. 2 m/s)2 + 2 • (-9. 8 m/s 2) • d 0 m 2/s 2 = 686. 44 m 2/s 2 + (-19. 6 m/s 2) • d = 0 m 2/s 2 -686. 44 m 2/s 2 (-19. 6 m/s 2) • d = -686. 44 m 2/s 2 d = (-686. 44 m 2/s 2)/ (-19. 6 m/s 2) d = 35. 0 m

A kangaroo is capable of jumping to a height of 2. 62 m. Determine

A kangaroo is capable of jumping to a height of 2. 62 m. Determine the takeoff speed of the kangaroo. v = v + 2*a*d (0 m/s) = v + 2*(-9. 8 m/s )*(2. 62 m) 0 m /s = v - 51. 35 m /s = v v = 7. 17 m/s 2 f 2 2 i 2 2 i 2

What about mass/weight? DOESN’T IT MATTER?

What about mass/weight? DOESN’T IT MATTER?

https: //www. youtube. com/watch? v =7 e. Tw 35 ZD 1 Ig

https: //www. youtube. com/watch? v =7 e. Tw 35 ZD 1 Ig