The Monohybrid Cross Mendels Work applied These problems

The Monohybrid Cross …

Mendel’s Work, applied These problems will focus on one trait (like plant height for example) We will use Punnett’s Squares to determine what happens to this trait over the course of a few generations This method can be used on almost all genetics problems

An Example… We will replicate one of Mendel’s examples. Cross a pure bred tall plant with a pure bred dwarf plant. Use Punnett’s squares to show the F 1 and F 2 generations

P 1 X P 2 Pheno Tall X Short geno TT X tt T X t Possible Gametes In this case, each parent can only give one possible gamete

Now to make the square… The number of possible gametes per parent decides the dimensions of the square. Our example will use a 1 x 1 square… T t Tt Parent’s Gametes Offspring’s genotype Parent’s Gametes

Now the analsis… F 1 generation T t Tt This means that all of the offspring in the F 1 generation will have the genotype T t. The Genotypic ratio is all Tt Knowing that T is the dominant allele, all of the offspring will have the phenotype “Tall”. The Phenotypic Ratio is All Tall.

Our Statement must state what we see! All of the F 1 pea plants are Tall Next, we will cross two plants from the F 1 generation.

F 1 X F 1 Pheno Tall X Tall geno Tt X Tt T or t X T or t Possible Gametes Each parent can give either one of their gametes

Now, to make the square: One parent’s possible gametes T T t TT Tt tt The other’s possible gametes Offspring’s Genotypes

Now, more analysis… T F 2 generation 1 of the 4 has the genotype TT, t T TT Tt The genotypic ratio is 1 TT : 2 t Tt : 1 tt Tt tt 2 have the genotype Tt, and 1 has the genotype tt. 3 of the 4 offspring will be Tall (either Tt or TT), and 1 will be short (tt). The Phenotypic ratio is going to be 3 Tall : 1 Short

Remember! The Statement! State what we SEE The F 2 phenotypic ratio for pea plants is 3: 1 Tall: Short.

The Guinea Pig problem… Suppose that Guinea Pig colour is determined by one gene. B (brown coat) is dominant to b (grey coat) Show the F 1 generation for a cross of B b x B b using Punnet’s squares Give the Genotypic and phenotypic ratios for each generation

The Guinea Pig Problem: P 1 Pheno geno Possible Gametes Brown X X Bb X B or b X P 2 Brown Bb B or b Both Parents can give either gamete

The Guinea Pig Problem B Genotypic Ratio: 1 BB : 2 Bb : 1 bb b B BB Bb bb Phenotypic Ratio: 3 Brown : 1 Grey Statement: The F 1 phenotypic ratio for Guinea Pig’s coat colour is 3 Brown : 1 Grey

The Guinea Pig problem… Tips for monohybrids Do each generation one step at a time What gametes can each parent contribute? What are the dimensions of each square? Count how many of each type of offspring you will have in terms of BOTH genotype and phenotype. REMEMBER YOUR STATEMENTS

The Test Cross What if you had a female brown Guinea Pig at home, and wanted to know her GENOTYPE? How would you be able to find out? We’d use a Test Cross A Test Cross is crossing the unknown with a homozygous recessive. In this case, you would need a male homozygous recessive… he would have to be grey

Baby Guinea Pig… Lets say we do this cross…and get this result? x =

This was the cross: BB x bb We know the grey Guinea Pigs is bb. But the Brown Guinea Pig could be BB or Bb. All Brown offspring means that our brown Guinea Pig was genotype BB, because 100% of the offspring had the dominant trait.

Baby Guinea Pigs… How about this result? x =

This was the cross: Bb x bb Half brown and half grey offspring means that our brown Guinea Pig was genotype Bb, because Half got the ‘B’ gamete and half got the ‘b’ gamete. Half express the recessive trait, and half express the dominant trait.