Phasor Relationships for Circuit Elements 7 4 Prof

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Phasor Relationships for Circuit Elements (7. 4) Prof. Phillips April 16, 2003 lecture 20

Phasor Relationships for Circuit Elements (7. 4) Prof. Phillips April 16, 2003 lecture 20 1

Phasor Relationships for Circuit Elements • Phasors allow us to express current-voltage relationships for

Phasor Relationships for Circuit Elements • Phasors allow us to express current-voltage relationships for inductors and capacitors much like we express the current-voltage relationship for a resistor. • A complex exponential is the mathematical tool needed to obtain this relationship. lecture 20 2

I-V Relationship for a Resistor + i(t) v(t) R – Suppose that i(t) is

I-V Relationship for a Resistor + i(t) v(t) R – Suppose that i(t) is a sinusoid: i(t) = IM ej(wt+q) Find v(t) lecture 20 3

Computing the Voltage lecture 20 4

Computing the Voltage lecture 20 4

Class Example lecture 20 5

Class Example lecture 20 5

I-V Relationship for a Capacitor + i(t) v(t) C – Suppose that v(t) is

I-V Relationship for a Capacitor + i(t) v(t) C – Suppose that v(t) is a sinusoid: v(t) = VM ej(wt+q) Find i(t) lecture 20 6

Computing the Current lecture 20 7

Computing the Current lecture 20 7

Phasor Relationship • Represent v(t) and i(t) as phasors: V = VM q I

Phasor Relationship • Represent v(t) and i(t) as phasors: V = VM q I = jw. C V • The derivative in the relationship between v(t) and i(t) becomes a multiplication by jw in the relationship between V and I. lecture 20 8

Example v(t) = 120 V cos(377 t + 30 ) C = 2 m.

Example v(t) = 120 V cos(377 t + 30 ) C = 2 m. F • What is V? • What is I? • What is i(t)? lecture 20 9

Class Example lecture 20 10

Class Example lecture 20 10

I-V Relationship for an Inductor + i(t) v(t) L – V = jw. L

I-V Relationship for an Inductor + i(t) v(t) L – V = jw. L I lecture 20 11

Example i(t) = 1 m. A cos(2 p 9. 15 • 107 t +

Example i(t) = 1 m. A cos(2 p 9. 15 • 107 t + 30 ) L = 1 m. H • What is I? • What is V? • What is v(t)? lecture 20 12

Class Example lecture 20 13

Class Example lecture 20 13

Circuit Element Phasor Relations (ELI and ICE man) lecture 20 14

Circuit Element Phasor Relations (ELI and ICE man) lecture 20 14

Phasor Diagrams • A phasor diagram is just a graph of several phasors on

Phasor Diagrams • A phasor diagram is just a graph of several phasors on the complex plane (using real and imaginary axes). • A phasor diagram helps to visualize the relationships between currents and voltages. lecture 20 15

An Example 2 m. A 40 + + 1 m. F w = 377

An Example 2 m. A 40 + + 1 m. F w = 377 1 k. W – VC + – V VR – lecture 20 16

An Example (cont. ) I = 2 m. A 40 VR = 2 V

An Example (cont. ) I = 2 m. A 40 VR = 2 V 40 VC = 5. 31 V -50 V = 5. 67 V -29. 37 lecture 20 17

Phasor Diagram Imaginary Axis Real Axis V VC VR lecture 20 18

Phasor Diagram Imaginary Axis Real Axis V VC VR lecture 20 18

MATLAB Exercise • Let’s use MATLAB to plot an ac current and voltage, and

MATLAB Exercise • Let’s use MATLAB to plot an ac current and voltage, and then to graphically determine the lead-lag relationship • Start MATLAB on your computer • We begin by creating a time vector >> t = 0 : 0. 0005 : 0. 025; • Next, we create the voltage and current >> vt = 170 * cos(377*t+10*pi/180); >> it = 100 * cos(377*t-65*pi/180); lecture 20 19

MATLAB Exercise • Now we will graph v(t) and i(t) >> plot(t, vt, 'b',

MATLAB Exercise • Now we will graph v(t) and i(t) >> plot(t, vt, 'b', t, it, 'r--'); >> xlabel('Time (sec)'); >> ylabel('Voltage (Volts) or Current (Amps)'); >> title('Household AC Voltage-Current'); >> legend('v(t)=170 cos(377 t+10)', 'i(t)=100 cos(377 t-65)'); lecture 20 20

MATLAB Exercise • From the graphs created: – Determine whether the current leads the

MATLAB Exercise • From the graphs created: – Determine whether the current leads the voltage, or vice versa – Determine the amount of lead by the current or voltage • Compare the voltage-current lead-lag relationship obtained by graphical means above to an analytic solution which you should be able to compute lecture 20 21