MOMENTUM Action and Reaction Forces Newtons Third Law

MOMENTUM Action and Reaction Forces Newton’s Third Law

Newton's Third Law of Motion (Law of Action & Reaction) [Law of Forces acting in Pairs]

Newton's rd 3 Law of Motion says: for every action, there is an equal and opposite reaction. Forces act in pairs. One force is called the action force and the other is called the reaction force.

MOMENTUM l. Momentum is a property a moving object has because of its mass and velocity.

MOMENTUM l Which would hurt more? ?

MOMENTUM Momentum is a property a moving object has because of its mass and velocity. Momentum can be calculated by : P = momentum (kg m/s) m = mass (kg) v = velocity (m/s)

MOMENTUM l What is the momentum of a 5 kg ball that has a velocity of 15 m/s? G F S A/U

Momentum practice problems What is the momentum of a 5 kg ball that has a velocity of 15 m/s? G P= P M= 5 kg V= 15 m/s F P=MV S A/U

Momentum practice problems What is the momentum of a 5 kg ball that has a velocity of 15 m/s? G P= P M= 5 kg V= 15 m/s F P=MV S P = 5 x 15 A/U

Momentum practice problems What is the momentum of a 5 kg ball that has a velocity of 15 m/s? G P= P M= 5 kg V= 15 m/s F P=MV S P = 5 x 15 A/U 75 kg • m/s

MOMENTUM l What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5 m/s? G F S A/U

MOMENTUM l What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5 m/s? G P= 10 kg • m/s M= M V= 5 m/s F P=MV S A/U

MOMENTUM l What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5 m/s? G P= 10 kg • m/s M= M V= 5 m/s F P=MV S 10 = M x 5 A/U

MOMENTUM l What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5 m/s? G P= 10 kg • m/s M= M V= 5 m/s F P=MV S 10 = M x 5 5 5 A/U

MOMENTUM l What is the mass of a box that has a momentum of 10 kg • m/s and a velocity of 5 m/s? G P= 10 kg • m/s M= M V= 5 m/s F P=MV S 10 = M x 5 5 5 A/U 2 kg

MOMENTUM l What is the velocity of a child that has a mass of 20 kg and a momentum of 50 kg • m/s ? G F S A/U

MOMENTUM l What is the velocity of a child that has a mass of 20 kg and a momentum of 50 kg • m/s ? G P= 50 kg • m/s M= 20 kg V= V F P=MV S A/U

MOMENTUM l What is the velocity of a child that has a mass of 20 kg and a momentum of 50 kg • m/s ? G P= 50 kg • m/s M= 20 kg V= V F P=MV S 50 = 20 x V A/U

MOMENTUM l What is the velocity of a child that has a mass of 20 kg and a momentum of 50 kg • m/s ? G P= 50 kg • m/s M= 20 kg V= V F P=MV S 50 = 20 x V 20 20 A/U

MOMENTUM l What is the velocity of a child that has a mass of 20 kg and a momentum of 50 kg • m/s ? G P= 50 kg • m/s M= 20 kg V= V F P=MV S 50 = 20 x V 20 20 A/U 5/2 or 2. 5 m/s

Copy this question and the steps to solve! This question is on the assignment, quiz, review and test! If a Miata (900 kg) at 30 m/s runs headon into a Civic (1200 kg) and neither car moves after the collision, what is the velocity of the Civic ? Given/ Miata: Miata M Vthe momentum of the Our first job is. Pto= find Miata…………

If a Miata (900 kg) at 30 m/s runs headon into a Civic (1200 kg) and neither car moves after the collision, what is the velocity of the Civic ? Given/ Miata: P= P M=900 kg V= 30 m/s Miata: formula P=MV Our first job is to find the momentum of the Miata…………

If a Miata (900 kg) at 30 m/s runs head-on into a Civic (1200 kg) and neither car moves after the collision, what is the velocity of the Civic ? Given/ Miata: P= P M=900 kg V= 30 m/s Miata: formula P=MV SUB P = 900 x 30 Our first job is to find the momentum of the Miata…………

If a Miata (900 kg) at 30 m/s runs head-on into a Civic (1200 kg) and neither car moves after the collision, what is the velocity of the Civic ? Given/ Miata: P= P M=900 kg Miata: formula P=MV SUB P = 900 x 30 ANS/UNITS P=27000 Kg * m/s V= 30 m/s Since they did NOT move after the collision, their “momentums” must have been EQUAL! EQUAL

If a Miata (900 kg) at 30 m/s runs head-on into a Civic (1200 kg) and neither car moves after the collision, what is the velocity of the Civic ? Given/ Miata: P= P M=900 kg Miata: formula P=MV SUB P = 900 x 30 ANS/UNITS P=27000 Kg * m/s V= 30 m/s Since they did NOT move after the collision, their “momentums” must have been EQUAL! EQUAL Given/Civic: P = 27, 000 kg • m/s

If a Miata (900 kg) at 30 m/s runs head-on into a Civic (1200 kg) and neither car moves after the collision, what is the velocity of the Civic ? Since they did NOT move after the collision, their “momentums” must have been EQUAL! EQUAL Given/Civic: P = 27, 000 kg • m/s M = 1200 kg V=V

If a Miata (900 kg) at 30 m/s runs head-on into a Civic (1200 kg) and neither car moves after the collision, what is the velocity of the Civic ? Since they did NOT move after the collision, their “momentums” must have been EQUAL! EQUAL Given/Civic: P = 27, 000 kg • m/s M = 1200 kg V=V P=mv 27, 000 = 1200 x V

If a Miata (900 kg) at 30 m/s runs head-on into a Civic (1200 kg) and neither car moves after the collision, what is the velocity of the Civic ? Since they did NOT move after the collision, their “momentums” must have been EQUAL! EQUAL Given/Civic: P = 27, 000 kg • m/s M = 1200 kg V=V P=mv 27, 000 = 1200 x V 1200 V = 22. 5 m/s That was the Velocity of the Civic!

The Law of Conservation of Momentum - the total amount of momentum of a group of objects does not change unless outside forces act on the objects. (Ex – momentum of cue ball = momentum of balls struck + remaining momentum in cue ball) What outside force acts against the balls now?

If a larger truck were to run, head to head, into a smaller truck moving at the same speed, what would happen to the momentum of each truck?