Impulse and Momentum Linear momentum impulse Linear momentum

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Impulse and Momentum

Impulse and Momentum

Linear momentum & impulse • Linear momentum is defined as the product of mass

Linear momentum & impulse • Linear momentum is defined as the product of mass and velocity – p=mv, px=mvx , py= mvy – units of momentum are kgm/s • From Newtons 2 nd law • F= ma F=m v/ t F= p/ t • The rate of momentum change with respect to time is equal to the resultant force on an object • The product of Force and time is known as IMPULSE • J= F t • units of impulse are Ns

Linear momentum & impulse Examples of impulses being applied on everyday objects

Linear momentum & impulse Examples of impulses being applied on everyday objects

Impulse Momentum Theorem F t=m v You apply an impulse on an object and

Impulse Momentum Theorem F t=m v You apply an impulse on an object and you get an equal change in momentum Area under a Force vs time graph

Impulse Graph

Impulse Graph

Conservation of momentum 2 particle system For gravitational or electrostatic force m 1 m

Conservation of momentum 2 particle system For gravitational or electrostatic force m 1 m 2 F 12 F 21 F 12 =dp 1/dt F 21 = dp 2/dt F 12 is force of 1 on 2 F 21 is force of 2 on 1

Conservation of momentum 2 particle system From Newton’s 3 rd Law F 12 =

Conservation of momentum 2 particle system From Newton’s 3 rd Law F 12 = - F 21 m 1 or F 12 + F 21 = 0 m 2 F 12 F 21 F 12 + F 21 =dp 1/dt + dp 2/dt = 0 d(p 1 + p 2)/dt= 0 F 12 is force of 1 on 2 F 21 is force of 2 on 1 Since this derivative is equal to 0

Conservation of momentum 2 particle system Since this derivative is d(p 1 + p

Conservation of momentum 2 particle system Since this derivative is d(p 1 + p 2)/dt= 0 then integration yields equal to 0 p 1 + p 2 = a CONSTANT F 12 m 1 F 12 F 21 Thus the total momentum of the system of 2 particles is a constant. is force of 1 on 2 is force of 2 on 1

Conservation of linear momentum Provided the particles are isolated from external forces, the total

Conservation of linear momentum Provided the particles are isolated from external forces, the total momentum of the particles will remain constant regards of the interaction between them F 12 m 1 F 21 m 2 Simply stated: when two particles collide, their total momentum remains constant. pi = pf p 1 i + p 2 i = p 1 f + p 2 f (m 1 v 1)i + (m 2 v 2)i = (m 1 v 1)f + (m 2 v 2)f

Collisions

Collisions

Collisions Event when two particles come together for a short time producing impulsive forces

Collisions Event when two particles come together for a short time producing impulsive forces on each other. , No external forces acting. Or for the enthusiast: External forces are very small compared to the impulsive forces Types of collisions 1) Elastic- Momentum and Kinetic energy conserved 2) Inelastic- Momentum conserved, some KE lost 3) Perfectly(completely) Inelastic- Objects stick together

Collisions in 1 d Perfectly Elastic 1) Cons. of mom. 2) KE lost in

Collisions in 1 d Perfectly Elastic 1) Cons. of mom. 2) KE lost in collision 3) KE changes to PE

Elastic Collision Calculation 2 objects

Elastic Collision Calculation 2 objects

Collisions - Examples Computer Simulations example 2, problems 5, 24, 29 Serway Problems 27,

Collisions - Examples Computer Simulations example 2, problems 5, 24, 29 Serway Problems 27, 29, 33, 37

Collisions in 2 dimensions After Collision x momentum before collision equals x momentum after

Collisions in 2 dimensions After Collision x momentum before collision equals x momentum after the collision mavax Before collision mb vel=0 p=0 mavaf 1 mavafx mbvbxf mbvbf 2

Collisions in 2 dimensions mavax= mavafx + mbvbxf or mavax= mavaf cos 1 +

Collisions in 2 dimensions mavax= mavafx + mbvbxf or mavax= mavaf cos 1 + mbvbf cos 2

Collisions in 2 dimensions After Collision y momentum before collision equals y momentum after

Collisions in 2 dimensions After Collision y momentum before collision equals y momentum after the collision mavax Before collision Velocity y axis =0 py=o mavaf 1 mavayf mb vel=0 p=0 2 mbvbf Mbvbyf

Collisions in 2 dimensions 0= mavafy - mbvbfy or 0= mavaf sin 1 -mbvbf

Collisions in 2 dimensions 0= mavafy - mbvbfy or 0= mavaf sin 1 -mbvbf sin 2

Collisions in 2 dimensions 0= mavaf sin 1 -mbvbf sin 2 mavax= mavaf cos

Collisions in 2 dimensions 0= mavaf sin 1 -mbvbf sin 2 mavax= mavaf cos 1 + mbvbf cos 2