Work Force over a Distance In physics work

![Force over a Distance ] In physics, work is the force acting on object Force over a Distance ] In physics, work is the force acting on object](https://slidetodoc.com/presentation_image_h2/529fa16869ad594faef5d99cc644a7f8/image-2.jpg)
![Creating Motion v=0 ] F Work is force acting over a distance. • Changing Creating Motion v=0 ] F Work is force acting over a distance. • Changing](https://slidetodoc.com/presentation_image_h2/529fa16869ad594faef5d99cc644a7f8/image-3.jpg)
![Work in a Direction ] The force must act in the direction of the Work in a Direction ] The force must act in the direction of the](https://slidetodoc.com/presentation_image_h2/529fa16869ad594faef5d99cc644a7f8/image-4.jpg)
![Beginning and End ] Only the force acting in the direction of displacement counts Beginning and End ] Only the force acting in the direction of displacement counts](https://slidetodoc.com/presentation_image_h2/529fa16869ad594faef5d99cc644a7f8/image-5.jpg)
![Scalar Product ] Finding the component of a vector in the direction of another Scalar Product ] Finding the component of a vector in the direction of another](https://slidetodoc.com/presentation_image_h2/529fa16869ad594faef5d99cc644a7f8/image-6.jpg)
![The Joule ] Work is force acting over a distance, and has units equal The Joule ] Work is force acting over a distance, and has units equal](https://slidetodoc.com/presentation_image_h2/529fa16869ad594faef5d99cc644a7f8/image-7.jpg)
![Constant Force ] Lifting an object requires a constant force equal to gravity, F Constant Force ] Lifting an object requires a constant force equal to gravity, F](https://slidetodoc.com/presentation_image_h2/529fa16869ad594faef5d99cc644a7f8/image-8.jpg)
![Individual Force ] x • Constant velocity has net force of zero. • A Individual Force ] x • Constant velocity has net force of zero. • A](https://slidetodoc.com/presentation_image_h2/529fa16869ad594faef5d99cc644a7f8/image-9.jpg)
![Dissipative Force ] x F A man is letting a 300 kg piano slide Dissipative Force ] x F A man is letting a 300 kg piano slide](https://slidetodoc.com/presentation_image_h2/529fa16869ad594faef5d99cc644a7f8/image-10.jpg)
- Slides: 10
Work
Force over a Distance ] In physics, work is the force acting on object over a distance. ] Forces acting on objects at rest do no work.
Creating Motion v=0 ] F Work is force acting over a distance. • Changing motion requires a force: F = ma. • Force is applied over a finite distance. v>0 ] Forces that change motion may do work.
Work in a Direction ] The force must act in the direction of the displacement to be work. Force acts in this direction The object moves in this direction Not all the force is in the direction of motion.
Beginning and End ] Only the force acting in the direction of displacement counts towards work. • Displacement considers the beginning and end points. FN FN ] FG FG Forces acting perpendicular to an object’s motion do no work. • Linear motion with perpendicular forces • Uniform circular motion
Scalar Product ] Finding the component of a vector in the direction of another vector is called the scalar product. A B q A|| Perpendicular vectors always have a scalar product of zero.
The Joule ] Work is force acting over a distance, and has units equal to units of force times units of distance. • With 1 -dimensional constant force, W = F x • With vectors and a constant force, W = F x cosq ] The unit of work is the joule (J) = 1 N m.
Constant Force ] Lifting an object requires a constant force equal to gravity, F = mg. mg x = h ] The work done by the lifter is W = F x = mgh. -mg mg ] The work done by gravity is W = - F x = -mgh. -mg
Individual Force ] x • Constant velocity has net force of zero. • A net force of zero may include forces that are not zero. FN Ffr F Fg Pearson Education Work can be done by individual forces, or by a net force. ] Force acting through a distance applies to separate forces.
Dissipative Force ] x F A man is letting a 300 kg piano slide 4 m at constant velocity down a 30° incline while exerting a 400 N force on the horizontal. What work does he do? • The component of the force is (400 N)(cos 30) = -350 N • Negative since it is opposite the displacement • The work is (-350 N)(4 m) = -1400 N m = -1400 J