Work Energy Energy is Conserved Energy is Conserved

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Work & Energy

Work & Energy

Energy is Conserved • Energy is “Conserved” meaning it can not be created nor

Energy is Conserved • Energy is “Conserved” meaning it can not be created nor destroyed – Can change form – Can be transferred • Total Energy does not change with time. • This is a BIG deal!

Energy • Forms – – Kinetic Energy Potential Energy Heat Mass (E=mc 2) Motion

Energy • Forms – – Kinetic Energy Potential Energy Heat Mass (E=mc 2) Motion (Today) Stored (Wednesday) later 1161 • Units Joules = kg m 2 / s 2

Work The definition of work, when the force is parallel to the displacement: (7

Work The definition of work, when the force is parallel to the displacement: (7 -1) SI work unit: newton-meter (N·m) = joule, J

Typical Work

Typical Work

Positive & Negative Work done may be positive, zero, or negative, depending on the

Positive & Negative Work done may be positive, zero, or negative, depending on the angle between the force and the displacement:

Force at an Angle Work If the force is at an angle to the

Force at an Angle Work If the force is at an angle to the displacement: (7 -3) Only the horizontal component of the force does any work (horizontal displacement).

Work by Constant Force at Angle • You pull a 30 N chest 5

Work by Constant Force at Angle • You pull a 30 N chest 5 meters across the floor at a constant speed by applying a force of 50 N at an angle of 30 degrees. How much work is done by the 50 N force? W = T cos q Dx = (50 N) cos (30) (5 m) = 217 Joules 50 N 30 f N Ty mg T Tx

Where did the energy go? • You pull a 30 N chest 5 meters

Where did the energy go? • You pull a 30 N chest 5 meters across the floor at a constant speed, by applying a force of 50 N at an angle of 30 o. • How much work did gravity do? W = Fcos q Dx Dx = 30 cos(90) x 5 90 =0 mg T • How much work did friction do? N X-Direction: SF = ma f T cos(30) – f = 0 mg f = T cos(30) = 43. 3 N W = f cos(180) Dx = (43. 3 N) cos(180) x 5 = -217 Joules f Dr 180

Perpendicular Force and Work A car is traveling on a curved highway. The force

Perpendicular Force and Work A car is traveling on a curved highway. The force due to friction fs points toward the center of the circular path. How much work does the frictional force do on the car? Zero! General Result: A force that is everywhere perpendicular to the motion does no work.

Work Done by Gravity In lifting an object of weight mg by a height

Work Done by Gravity In lifting an object of weight mg by a height h, the person doing the lifting does an amount of work W = mgh. If the object is subsequently allowed to fall a distance h, gravity does work W = mgh on the object.

Work By Gravity When positive work is done on an object, its speed increases;

Work By Gravity When positive work is done on an object, its speed increases; when negative work is done, its speed decreases.

Kinetic Energy: Motion • Apply constant net force along xdirection to an object m.

Kinetic Energy: Motion • Apply constant net force along xdirection to an object m. W = Fx Dx = m a Dx = ½ m (v 2 – v 02) • Work changes ½ m v 2 • Voila – new concept: • Define Kinetic Energy K = ½ m v 2 W=DK

Work-Energy Theorem: The total work done on an object is equal to its change

Work-Energy Theorem: The total work done on an object is equal to its change in kinetic energy. (7 -7)

Falling Ball Example A ball falls a distance 5 meters, what is final speed?

Falling Ball Example A ball falls a distance 5 meters, what is final speed? Only force/work done by gravity SW = DKE Wg = ½ m(vf 2 – vi 2) Fg h = ½m vf 2 mgh = ½m vf 2 Vf = sqrt( 2 g h ) = 10 m/s mg

Work: Energy Transfer due to Force • Force to lift trunk at constant speed

Work: Energy Transfer due to Force • Force to lift trunk at constant speed – Case a Ta – mg = 0 T = mg – Case b 2 Tb - mg =0 or T = ½ mg • But in case b, trunk only moves ½ distance you pull rope. • F * distance is same in both! Ta mg Tb Tb mg

Loading with a Crane A 3, 000 kg truck is to be loaded onto

Loading with a Crane A 3, 000 kg truck is to be loaded onto a ship by a crane that exerts an upward force of 31 k. N on the truck. This force, which is large enough to overcome the gravitational force and keep the truck moving upward, is applied over a distance of 2. 0 m. (a) Find the work done on the truck by the crane. (b) Find the work done on the truck by gravity. (c) Find the net work done on the truck.

Preflight 1 FN You are towing a car up a hill with constant velocity.

Preflight 1 FN You are towing a car up a hill with constant velocity. The work done on the car by the normal force is: T 38% 1. positive 13% 2. negative 50% 3. zero correct V W “work done by normal force is 0 because q is 90 and cos 90 = 0” 28

Preflight 2 FN You are towing a car up a hill with constant velocity.

Preflight 2 FN You are towing a car up a hill with constant velocity. The work done on the car by the gravitational force. T is: 0% 1. positive 63% 2. negative 37% 3. zero correct V W The work done on the car by the gravitational force is negative because it hinders motion up the hill

Preflight 3 FN You are towing a car up a hill with constant velocity.

Preflight 3 FN You are towing a car up a hill with constant velocity. The work done on the car by the tension force is: T 63% 1. positive 25% 2. negative 12% 3. zero V correct W “work done by tension is positive because the angle of the force is between 0 and 90”

KE ACTS Car 1 has twice the mass of Car 2, but they both

KE ACTS Car 1 has twice the mass of Car 2, but they both have the same kinetic energy. If the speed of Car 1 is v, approximately what is the speed of Car 2? a) 0. 50 v b) 0. 707 v c) v d) 1. 414 v e) 2. 00 v

Preflight 4 FN You are towing a car up a hill with constant velocity.

Preflight 4 FN You are towing a car up a hill with constant velocity. The total work done on the car by all forces is: T 63% 1. positive 12% 2. negative 25% 3. zero correct V W The total work done is positive because the car is moving up the hill. (Not quite!) Total work done on the car is zero because the forces cancel each other out.

Block w/ friction A block is sliding on a surface with an initial speed

Block w/ friction A block is sliding on a surface with an initial speed of 5 m/s. If the coefficent of kinetic friction between the block and table is 0. 4, how far does the block travel before stopping? Y direction: SF=ma N-mg = 0 N = mg Work WN = 0 Wmg = 0 Wf = f Dx cos(180) = -mmg Dx 5 m/s N f y x mg W=DK -mmg Dx = ½ m (vf 2 – v 02) -mg Dx = ½ (0 – v 02) mg Dx = ½ v 02 / mg = 3. 1 meters

Summary • Energy is Conserved • Work = transfer of energy using force –

Summary • Energy is Conserved • Work = transfer of energy using force – Can be positive, negative or zero – W = F d cos(q) • Kinetic Energy (Motion) – K = ½ m v 2 • Work = Change in Kinetic Energy – S W = DK