WORK AND POWER solutions Work is done when

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WORK AND POWER solutions

WORK AND POWER solutions

Work is done when an object moves through a distance because of a Force

Work is done when an object moves through a distance because of a Force acting upon the object.

2. When calculating work, you should use the formula: work = force X distance.

2. When calculating work, you should use the formula: work = force X distance.

 • 3. The SI unit for work is the joules. It is represented

• 3. The SI unit for work is the joules. It is represented by the letter __J____.

4. How much work is done in holding a 15 N sack of potatoes

4. How much work is done in holding a 15 N sack of potatoes 2 m off the ground while waiting in line at the grocery store for 3 minutes? Work = Force x Distance W=0 J

5. You must exert a force of 4. 5 N on a book to

5. You must exert a force of 4. 5 N on a book to slide it across a table. If you do 2. 7 J of work in the process, how far have you moved the book? W=Fxd 2. 7 = 4. 5 x d d = 2. 7/4. 5 = 0. 6 m

6. A child pulls a sled up a snow-covered hill. The child does 405

6. A child pulls a sled up a snow-covered hill. The child does 405 J of work on the sled. If the child walks 15 m up the hill, how large of a force must the child exert? W=Fxd 405 = F x 15 F = 405 / 15 F = 27 N

7. How much work is done on a small car if a 3150 N

7. How much work is done on a small car if a 3150 N force is exerted to move it 75. 5 m to the side of the road? W = 3150 x 75. 5 W = 237. 825 k. J

8. A crate is being lifted into a truck. If it is moved with

8. A crate is being lifted into a truck. If it is moved with a 2470 N force and 3650 J of work is done, then how far is the crate being lifted? W=Fxd 3650 = 2470 x d d = 3650/2470 d = 1. 48 m

9. If 16, 700 J of work is done to shoot the human cannonball

9. If 16, 700 J of work is done to shoot the human cannonball down a 3. 05 m barrel, then how much force is applied to the person to fire them out the cannon? W=Fxd 16700 = F x 3. 05 F = 16700/3. 05 F = 5475 N

10. An elephant pushes with 2000 N on a load of trees. It then

10. An elephant pushes with 2000 N on a load of trees. It then pushes these trees for 150 m. How much work did the elephant do? W=Fxd W = 2000 x 150 W = 300000 J = 300 k. J

11. If a small motor does 520. J of work to move a toy

11. If a small motor does 520. J of work to move a toy car 260. m, what force does it exert? W=Fxd 520 = F x 260 F=2 N

12. A girl pushes her little brother on his sled with a force of

12. A girl pushes her little brother on his sled with a force of 300. N for 750. m. How much work is this if the force of friction acting on the sled is (a) 200. N, (b) 300. N? a. Wnet = Fnet x d Wnet = (300 – 200) x 750 Wnet = 100 x 750 Wnet = 75000 J = 75 k. J b. Wnet = (300 – 300) x 750 Wnet = 0 J

13. A 75. 0 kg man pushes on a 5. 0 x 105 ton

13. A 75. 0 kg man pushes on a 5. 0 x 105 ton wall for 250 s but it does not move. How much work does he do on the wall? (2000 lb = 1 ton; 0. 454 kg = 1 lb) If the wall does not move, no work is done because d = 0 m.

14. A boy on a bicycle drags a wagon full of newspapers at 0.

14. A boy on a bicycle drags a wagon full of newspapers at 0. 800 m/s for 30. 0 min using a force of 40. 0 N. How much work has the boy done? d=vxt d = 0. 8 m/s x 30 minutes x 60 seconds/minute d = 1440 m W=Fxd W = 40 x 1440 W = 57600 J = 57. 6 k. J

15. Power is the rate at which work is done.

15. Power is the rate at which work is done.

16. When calculating power, you should use the formula P = work divided by

16. When calculating power, you should use the formula P = work divided by time. In this formula, “P” stands for power, W stands for work, and t for time.

17. The SI unit for Power is the Watt(s).

17. The SI unit for Power is the Watt(s).

18. An 190, 000 W engine can accelerate from rest to a top speed

18. An 190, 000 W engine can accelerate from rest to a top speed in 9 s. How much work did the engine do? P = W/t W = Pt W = 190000 x 9 W = 1710000 J = 1710 k. J

19. Another engine reaches its top speed from rest in 7. 5 s. It

19. Another engine reaches its top speed from rest in 7. 5 s. It is able to perform 250, 000 J of work in that time. How much power does this engine have in that time? P = W/t P = 250000/7. 5 P = 33333 W = 33. 3 k. W

20. If a runner exerts 350 J of work to make 125 W of

20. If a runner exerts 350 J of work to make 125 W of power, then how long did it take the runner to do the work? P = W/t t = W/P t = 350/125 t = 2. 8 seconds

21. A person weighing 600 N gets on an elevator. The elevator lifts the

21. A person weighing 600 N gets on an elevator. The elevator lifts the person 6 m in 10 seconds. How much power was used? P = W/t P = Fd/t P = 600 x 6 / 10 P = 360 W

22. How much time is needed to produce 720 Joules of work if 90

22. How much time is needed to produce 720 Joules of work if 90 watts of power is used? P = W/t t = W/P t = 720/90 t = 8 seconds

23. A set of pulleys lifts an 800 N crate 4 meters in 7

23. A set of pulleys lifts an 800 N crate 4 meters in 7 seconds. What power was used? P = W/t P = Fd/t P = 800 x 4 / 7 P = 457 W

24. A force of 5. 0 N moves a 6. 0 kg object along

24. A force of 5. 0 N moves a 6. 0 kg object along a rough floor at a constant speed of 2. 5 m/s. a. How much work is done in 25 s? W=Fxd W = 5 x (2. 5 x 25) W = 312. 5 J b. What power is being used? P = W/t P = 312. 5/25 P = 12. 5 W c. What force of friction is acting on the object? constant velocity dynamic equilibrium equal forces friction force equals apply force = 5 N, so friction force = 5 N

25. A car uses 2, 500 Joules in 25 seconds. Find power. P =

25. A car uses 2, 500 Joules in 25 seconds. Find power. P = W/t P = 2500/25 P = 100 W

26. How much power does it take to lift 30. 0 N 10. 0

26. How much power does it take to lift 30. 0 N 10. 0 m high in 5. 00 s? P = W/t P = F x d/t P = 30 x 10 / 5 P = 60 W

27. How much power does it take to lift 30. 0 kg 10. 0

27. How much power does it take to lift 30. 0 kg 10. 0 m high in 5. 00 s? P = W/t P=Fxd/t P = (30 x 9. 8) x 10 / 5 P = 588 W