VOLTAIC CELL A SPONTANEOUS ENERGY RELEASING REDOX REACTIONUSING

VOLTAIC CELL: A SPONTANEOUS ENERGY RELEASING REDOX REACTION…USING Fe AND Pb ELECTRONS RELEASED BY REDUCING AGENT(THAT WHICH IS OXIDIZED-Fe(s) NEGATIVE SALT BRIDGE ION CARRIES NEGATIVE CHARGE BACT TO ANODE, THIS IS THE IONIC HALF OF THE CIRCUIT. ELECTRONS GAINED BY OXIDIZING AGENT IONS IN CATHODAL SOLUTION (Pb+2 (aq) ) THE CATHODE ITSELF IS Pb SOLID. ELECTRONS REPELLED FROM ANODE INTO WIRE, ELECTRONS CARRY NEGATIVE CHARGE THROUGH WIRE , RELEASE CHEMICAL POTENTIAL ENERGY AS ELECTRICITY

VOLTAIC CELL - 2 e - OVERVIEW ANIMATION 2 e 2 e VOLTMETER SLIDE ONE - 2 e. SO 4 2 - 2 - Na+ SO 42 Na+ 2 e- - Fe Fe 2 e. Fe 2+ SO 42 - Fe 0(s) 2 e- + Fe 2+ ANODE (ANOX) 2+ Pb. Pb Pb Na+ Pb 2+ Pb + + + Pb 2 e- + Pb 2+ Pb 0(s) CATHODE (REDCAT)

ANODE LIST Fe 0(s) 2 e- + Fe 2+ F 0 IS: 1) 2) 3) 4) 5) 6) OXIDIZED IS THE ANODE TOPMOST ON TABLE J. IS ELECTRON SOURCE IS REDUCING AGENT IS COVERTED TO AN AQUIOUS ION. THE ANODE: 1) IS NEGATIVE DUE TO ELECTRONS BEING PRODUCED. 1) DISSOLVES…LOSES MASS 2) THE ANODAL SOLUTION BECOMES + DUE TO PRODUCTION OF A POSITIVE ION…SALT BRIDGE – ION NEUTRALIZES.

CATHODE LIST 2 e- + Pb 2+ Pb 0(s) Pb+2 IS: 1) 2) 3) 4) 5) 6) REDUCED REACTS AT CATHODE (Pb 0) BOTTOM MOST ON TABLE J. IS ELECTRON DESTINATION IS OXIDIZING AGENT ITS AQUIOUS ION IS SOLIDIFIED. THE CATHODE: 1) IS POSITIVE DUE TO ELECTRONS BEING CONSUMED. 1) ELECTROPLATED…GAINS MASS 2) THE CATHODAL SOLUTION BECOMES - DUE TO CONSUMPTION OF A POSITIVE ION…SALT BRIDGE + ION NEUTRALIZES.

ELECTRON FLOW - ELECTRODES: FROM ANODE (SOLID IRON Fe) TRANSFERS ELECTRONS TO CATHODE (SOLID LEAD Pb). -SPECIES: FROM Fe 0 TO Pb+2 THE CIRCUIT -THE WIRE: THE FLOW OF ELECTRONS FROM ANODE TO CATHODE IS ELECTRICAL CONDUCTION, - CHARGE LEAVES ANODE CARRIED BY ELECTRONS. -SALT BRIDGE: NEGATIVE CHARGE RETURNS TO ANODE AS NEGATIVE IONS. NOTE ♪, ELECTRONS NEVER TRAVEL IN SALT BRIDGE OR ANY SOLUTION.

VOLTAIC AS THE Fe(S) IS CELL OXIDIZED, IT DISSOLVES AND SLIDE TWO THE ANODE LOSES MASS AND THE ANODE 2 e- ARE AS THE Fe(S) IS OXIDIZED, IT DISSOLVES AND THE VOLTMETER ANODE LOSES MASS, THE IRON(II) IONS WILL MAKE THE ANODE SOLUTION POSITIVE, THEREFORE THE + Na NEGATIVE SALT SO 42 - Na+ 2 SO 42 ION MOVES IN + Na. BRIDGE TO NEGATE THE + CHARGE RELEASED 2 e. Fe Fe Fe 2+ SO 4 Fe 0(s) 2 e- + Fe 2+ ANODE (ANOX) 2 - NSBTA Negative salt bridge to anode Pb 2+ Never sell booze to adolescents! Pb Pb 2 e- + Pb 2+ Pb 0(s) CATHODE (REDCAT)

VOLTAIC CELL - - - 2 e. Fe Fe Fe 0(s) 2 e- + ELECTRONS ALWAYS MOVE FROM Na ANODE + 2 SOCATHODE TO 4 Na+ SO 42(FATCAT). THE Na+ ELECTRONS BUILD UP IN THE ANODE Fe 2+ MAKING IT NEGATIVE, TRAVEL TO THE SO 42 -CATHODE WHERE A METAL ION GAINS Pb 2+ THEM IN REDUCTION, THE CATHODE IS POSITIVE. VOLTMETER ALWAYS Fe 2+ POINTS TO CATHODE, 2 e + ANODE (ANOX) 2 e- e- FLOW 2 e VOLTMETER 2 e 2 e SLIDE THREE 2 e. Pb Pb Pb 2+ Pb 0(s) CATHODE (REDCAT)

VOLTAIC CELL - - 2 e - POSITIVE SALT ION THE MIGRATES TO THE CATHODE TO REPLACE + CHARGE LOST AS Pb(II) Na+ 2 SO 4 Na+ ARE REDUCED TO 2 -Pb SO 42 SOLID. SO 4 Na+ 2 e. Fe Fe 2 e- THE CATHODE VOLTMETER 2 e 2 e SLIDE FOUR 2 e. Fe 2+ SO 42 AS ELECTRONS ARE GAINED BY Pb(II) IONS FROM THE CATHODE, THE IONS BECOME REDUCED INTO Pb(S) Fe 0(s) 2 e- + Fe 2+ ANODE (ANOX) Pb 2+ Pb Na+ Pb Pb 2+ Pb THE SOLID LEAD BONDS (METALLIC BONDING) THE CATHODE WHICH GAINS MASS. THIS IS ELECTROPL ATING. 2 e- + Pb 2+ Pb 0(s) CATHODE (REDCAT)