Van Der Pauw Van Der Pauw measurement and

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半導體專題實驗 實驗三 Van Der Pauw量測與霍爾效應 Van Der Pauw measurement and Hall effect 1

半導體專題實驗 實驗三 Van Der Pauw量測與霍爾效應 Van Der Pauw measurement and Hall effect 1

Hall effect have got two Nobel Prize in Physics Klaus von Klitzing 1985 "the

Hall effect have got two Nobel Prize in Physics Klaus von Klitzing 1985 "the quantized Hall effect" Robert B. Laughlin Horst L. Störmer Daniel C. Tsui 1998 " the fractional quantum Hall effect " 2

實驗目的 o 利用 Van Der Pauw 四點探針法和霍爾效應 (Hall effect),量測半導體中多數載子濃度與 遷移率μ (mobility) 。 The Van

實驗目的 o 利用 Van Der Pauw 四點探針法和霍爾效應 (Hall effect),量測半導體中多數載子濃度與 遷移率μ (mobility) 。 The Van Der Pauw Method Original paper by L. J. van der Pauw in 1958 http: //electron. mit. edu/~gsteele/vanderpauw. pdf 3

霍爾效應 (Hall Effect) For p-type: Remember, Hall effect is used to measure majority carrier

霍爾效應 (Hall Effect) For p-type: Remember, Hall effect is used to measure majority carrier density. For minority carrier density, we use Haynes-Shockley experiment. 6

霍爾效應 (Hall Effect) 由Lorentz force balance: 得到 (positive for ptype) 又 其中 故 稱

霍爾效應 (Hall Effect) 由Lorentz force balance: 得到 (positive for ptype) 又 其中 故 稱 Hall coefficient (positive for ptype) (d為導體厚度) : Hall voltage : Hall field : Hall coefficient 7

霍爾效應 (Hall Effect) For n-type: 同理可得 (for n-type) (negative for ntype) 8

霍爾效應 (Hall Effect) For n-type: 同理可得 (for n-type) (negative for ntype) 8

vs. Original quote: 17

vs. Original quote: 17

B=0. 55 T 地磁 400 m Gause 1 T=104 Gause 方程式 , , 可求出

B=0. 55 T 地磁 400 m Gause 1 T=104 Gause 方程式 , , 可求出 (1) (2) (3) 由量測中得到 可求出 (majority carrier density) 可求出 19

結報問題 1. Calculate r、n、m from measurement data for n-type and p-type 2. Compare with

結報問題 1. Calculate r、n、m from measurement data for n-type and p-type 2. Compare with the hall mobility we already have. 3. Hall coefficient RH 22

BACK UP 23

BACK UP 23

n-type ρ=6. 119Ω·cm n=5. 804 E+14/cm 3 μ=1. 757 E+3 cm 2/Vs 24

n-type ρ=6. 119Ω·cm n=5. 804 E+14/cm 3 μ=1. 757 E+3 cm 2/Vs 24

p-type ρ=8. 467Ω·cm n=1. 918 E+15/cm 3 μ=3. 849 E+2 cm 2/Vs 25

p-type ρ=8. 467Ω·cm n=1. 918 E+15/cm 3 μ=3. 849 E+2 cm 2/Vs 25