Unit 8 Right Triangle Trigonometric Ratios in Right

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Unit 8 – Right Triangle Trigonometric Ratios in Right Triangles

Unit 8 – Right Triangle Trigonometric Ratios in Right Triangles

Trigonometric Ratios are based on the Concept of Similar Triangles!

Trigonometric Ratios are based on the Concept of Similar Triangles!

All 45º- 90º Triangles are Similar! 1 45 º 1 2 1 45 º

All 45º- 90º Triangles are Similar! 1 45 º 1 2 1 45 º 2

All 30º- 60º- 90º Triangles are Similar! 2 30º 60º 4 1 60º 1

All 30º- 60º- 90º Triangles are Similar! 2 30º 60º 4 1 60º 1 30º 60º ½ 2

We’ll label the sides a, b, and c and the angles and . Trigonometric

We’ll label the sides a, b, and c and the angles and . Trigonometric functions are defined by taking the ratios of sides of a right triangle. se leg c te osi opp b Similar Triangles Always Have the Same Trig Ratio Answers! nu te adjacent po hy lega SINE COSINE TANGENT They are abbreviated using their first 3 letters

 Oh, I'm acute! This method only applies if you have a right triangle

Oh, I'm acute! This method only applies if you have a right triangle and is only for the acute angles (angles less than 90°) in the triangle. 5 4 3 So am I!

Here is a mnemonic to help you memorize the ratios. b c opp SOHCAHTOA

Here is a mnemonic to help you memorize the ratios. b c opp SOHCAHTOA osi te a adjacent

It is important to note WHICH angle you are talking about when you find

It is important to note WHICH angle you are talking about when you find the value of the trig function. po ten us e c 5 Let's try finding some trig functions with some numbers. opp te osi 4 b hy osit e adjacent a 3 sin = tan = Use a mnemonic and figure out which sides of the triangle you need for tangent. sine.

How do the trig answers for and hy po ten us e c 5

How do the trig answers for and hy po ten us e c 5 opp te osi 4 b relate to each other? osit e adjacent a 3

Trigonometry Ratios Tangent A = Sine A = Cosine A = A Soh Cah

Trigonometry Ratios Tangent A = Sine A = Cosine A = A Soh Cah Toa

The Tangent of an angle is the ratio of the opposite side of a

The Tangent of an angle is the ratio of the opposite side of a triangle to its adjacent side. hypotenuse 1. 9 cm opposite adjacent 14º 7. 7 cm Tangent 14º 0. 25

Tangent A = 3. 2 cm 7. 2 cm Tangent 24º 0. 45

Tangent A = 3. 2 cm 7. 2 cm Tangent 24º 0. 45

Tangent A = As an acute angle of a triangle approaches 90º, its tangent

Tangent A = As an acute angle of a triangle approaches 90º, its tangent becomes infinitely large very large Tan 89. 9º = 573 Tan 89. 99º = 5, 730 etc. very small

Since the sine and cosine functions always have the hypotenuse as the denominator, and

Since the sine and cosine functions always have the hypotenuse as the denominator, and since the hypotenuse is the longest side, these two functions will always be less than 1. Sine A = Cosine A = A Sine 89º =. 9998 Sine 89. 9º =. 999998

Sin α = 7. 9 cm 3. 2 cm 24º 0. 41 Sin 24º

Sin α = 7. 9 cm 3. 2 cm 24º 0. 41 Sin 24º 0. 41

Cosine β = 7. 9 cm 46º 5. 5 cm Cos 46º 0. 70

Cosine β = 7. 9 cm 46º 5. 5 cm Cos 46º 0. 70

Find the sine, the cosine, and the tangent of angle A. Give a fraction

Find the sine, the cosine, and the tangent of angle A. Give a fraction and decimal answer (round to 4 places). 10. 8 9 6 A Now, figure out your ratios.

Ex: 1 Figure out which ratio to use. Find x. Round to the nearest

Ex: 1 Figure out which ratio to use. Find x. Round to the nearest tenth. 20 m x 20 tan 55 ) Now, figure out which trig ratio you have and set up the problem.

Ex: 2 Find the missing side. Round to the nearest tenth. 80 ft x

Ex: 2 Find the missing side. Round to the nearest tenth. 80 ft x 80 ( tan 72 Now, figure out which trig ratio you have and set up the problem. ) ) =

Ex: 3 Find the missing side. Round to the nearest tenth. x 283 m

Ex: 3 Find the missing side. Round to the nearest tenth. x 283 m Now, figure out which trig ratio you have and set up the problem.

Ex: 4 Find the missing side. Round to the nearest tenth. 20 ft x

Ex: 4 Find the missing side. Round to the nearest tenth. 20 ft x

Finding an angle. (Figuring out which ratio to use and getting to use the

Finding an angle. (Figuring out which ratio to use and getting to use the 2 nd button and one of the trig buttons. )

Ex. 1: Find . Round to four decimal places. nd 2 17. 2 tan

Ex. 1: Find . Round to four decimal places. nd 2 17. 2 tan 17. 2 9 9 Now, figure out which trig ratio you have and set up the problem. Make sure you are in degree mode (not radians). )

Ex. 2: Find . Round to three decimal places. 7 23 nd 2 cos

Ex. 2: Find . Round to three decimal places. 7 23 nd 2 cos 7 23 Make sure you are in degree mode (not radians). )

Ex. 3: Find . Round to three decimal places. 200 0 0 4 nd

Ex. 3: Find . Round to three decimal places. 200 0 0 4 nd 2 sin 200 400 ) Make sure you are in degree mode (not radians).

When we are trying to find a side we use sin, cos, or tan.

When we are trying to find a side we use sin, cos, or tan. When we are trying to find an angle we use sin-1, cos-1, or tan-1.

A plane takes off from an airport an an angle of 18º and a

A plane takes off from an airport an an angle of 18º and a speed of 240 mph. Continuing at this speed angle, what is the altitude of the plane after 1 minute? After 60 sec. , at 240 mph, the plane has traveled 4 miles x 4 18º

Soh. Cah. Toa Soh Sine A = Sine 18 = 0. 3090 = 1

Soh. Cah. Toa Soh Sine A = Sine 18 = 0. 3090 = 1 x opposite 4 hypotenuse x = 1. 236 miles or 6, 526 feet 18º

An explorer is standing 14. 3 miles from the base of Mount Everest below

An explorer is standing 14. 3 miles from the base of Mount Everest below its highest peak. His angle of elevation to the peak is 21º. What is the number of feet from the base of Mount Everest to its peak? Tan 21 = 0. 3839 = 1 x = 5. 49 miles = 29, 000 feet x 14. 3 21º

A swimmer sees the top of a lighthouse on the edge of shore at

A swimmer sees the top of a lighthouse on the edge of shore at an 18º angle. The lighthouse is 150 feet high. What is the number of feet from the swimmer to the shore? Tan 18 = 0. 3249 = 1 0. 3249 x = 150 0. 3249 X = 461. 7 ft 150 x 18º

A dragon sits atop a castle 60 feet high. An archer stands 120 feet

A dragon sits atop a castle 60 feet high. An archer stands 120 feet from the point on the ground directly below the dragon. At what angle does the archer need to aim his arrow to slay the dragon? Tan x = 0. 5 Tan-1(0. 5) = 26. 6º 60 x 120

Solving a Problem with the Tangent Ratio We know the angle and the side

Solving a Problem with the Tangent Ratio We know the angle and the side adjacent to 60º. We want to know the opposite side. Use the tangent ratio: h=? 2 60º 53 ft 1 Why?

Ex. A surveyor is standing 50 feet from the base of a large tree.

Ex. A surveyor is standing 50 feet from the base of a large tree. The surveyor measures the angle of elevation to the top of the tree as 71. 5°. How tall is the tree? tan 71. 5° ? 71. 5° 50 tan 71. 5° y = 50 (tan 71. 5°) y = 50 (2. 98868)

Ex. 5 A person is 200 yards from a river. Rather than walk directly

Ex. 5 A person is 200 yards from a river. Rather than walk directly to the river, the person walks along a straight path to the river’s edge at a 60° angle. How far must the person walk to reach the river’s edge? cos 60° x (cos 60°) = 200 60° x x X = 400 yards

Trigonometric Functions on a Rectangular Coordinate System y Pick a point on the terminal

Trigonometric Functions on a Rectangular Coordinate System y Pick a point on the terminal ray and drop a perpendicular to the x-axis. r q x The adjacent side is x The opposite side is y The hypotenuse is labeled r This is called a REFERENCE TRIANGLE. y x

Trigonometric Ratios may be found by: Using ratios of special triangles 1 45 º

Trigonometric Ratios may be found by: Using ratios of special triangles 1 45 º 1 For angles other than 45º, 30º, 60º you will need to use a calculator. (Set it in Degree Mode for now. )