Trigonometry Lengths Demonstration This resource provides animated demonstrations

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Trigonometry – Lengths – Demonstration This resource provides animated demonstrations of the mathematical method.

Trigonometry – Lengths – Demonstration This resource provides animated demonstrations of the mathematical method. Check animations and delete slides not needed for your class.

A right-angled triangle has 4 parts. n e ot p y H Adjacent Hypotenuse

A right-angled triangle has 4 parts. n e ot p y H Adjacent Hypotenuse – always opposite the right-angle & always longest. Opposite e s u

SOH CAH TOA O Sin θ H (H) 7 cm (O) Cos θ H

SOH CAH TOA O Sin θ H (H) 7 cm (O) Cos θ H Tan θ A We want to find O. (so cover O) 62° cm

SOH CAH TOA O Sin θ H Cos θ H Tan θ A We

SOH CAH TOA O Sin θ H Cos θ H Tan θ A We want to find H. (so cover H) 26 cm (O) 49° (H) cm

SOH CAH TOA O Sin θ H Cos θ (H) 34° 12 cm (A)

SOH CAH TOA O Sin θ H Cos θ (H) 34° 12 cm (A) H Tan θ A We want to find H. (so cover H) cm

SOH CAH TOA O Sin θ H 13 cm Cos θ (H) 37° (A)

SOH CAH TOA O Sin θ H 13 cm Cos θ (H) 37° (A) H Tan θ A We want to find A. (so cover A) cm

SOH CAH TOA O Sin θ H Cos θ H Tan θ A We

SOH CAH TOA O Sin θ H Cos θ H Tan θ A We want to find O. (so cover O) (O) 52° (A) 4 cm cm

SOH CAH TOA O Sin θ H Cos θ H Tan θ A We

SOH CAH TOA O Sin θ H Cos θ H Tan θ A We want to find A. (so cover A) (O) 11 cm (A) 34° cm

SOH CAH TOA O Sin θ H (O) 41° 13 cm (H) Cos θ

SOH CAH TOA O Sin θ H (O) 41° 13 cm (H) Cos θ H Tan θ A We want to find O. (so cover O) cm

SOH CAH TOA O Sin θ H Cos θ H Tan θ A We

SOH CAH TOA O Sin θ H Cos θ H Tan θ A We want to find H. (so cover H) (A) 4 cm 62° (H) cm

SOH CAH TOA O Sin θ H Cos θ H Tan θ A We

SOH CAH TOA O Sin θ H Cos θ H Tan θ A We want to find A. (so cover A) 28° (O) 32 cm (A) cm

SOH CAH TOA O Sin θ H Cos θ H Tan θ A We

SOH CAH TOA O Sin θ H Cos θ H Tan θ A We want to find A. (so cover A) (A) 43° 25 cm (H) cm

SOH CAH TOA O Sin θ H Cos θ H Tan θ A We

SOH CAH TOA O Sin θ H Cos θ H Tan θ A We want to find H. (so cover H) (O) 14 cm 53° (H) cm

SOH CAH TOA O Sin θ (A) 9 cm H Cos θ H Tan

SOH CAH TOA O Sin θ (A) 9 cm H Cos θ H Tan θ A We want to find O. (so cover O) 57° cm (O)

SOH CAH TOA O Sin θ H 28° 6 cm Cos θ 6 cm

SOH CAH TOA O Sin θ H 28° 6 cm Cos θ 6 cm 15° H Tan θ A 44° 8 cm

SOH CAH TOA O Sin θ H 28° 6 cm Cos θ 6 cm

SOH CAH TOA O Sin θ H 28° 6 cm Cos θ 6 cm 15° H Tan θ A 44° 8 cm

SOH CAH TOA O Sin θ H 28° 6 cm Cos θ 6 cm

SOH CAH TOA O Sin θ H 28° 6 cm Cos θ 6 cm 15° H Tan θ A 44° 8 cm

Questions? Comments? Suggestions? …or have you found a mistake!? Any feedback would be appreciated

Questions? Comments? Suggestions? …or have you found a mistake!? Any feedback would be appreciated . Please feel free to email: tom@goteachmaths. co. uk

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