The photoelectric effect Contents Einsteins proposed experiment Solving

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The photoelectric effect Contents: • Einstein’s proposed experiment • Solving photoelectric problems • Example

The photoelectric effect Contents: • Einstein’s proposed experiment • Solving photoelectric problems • Example 1 | Example 2 • Whiteboard • Photon vs wave theory

Light Waves Wavelength Changes Color small = blue Photons Energy per photon changes E

Light Waves Wavelength Changes Color small = blue Photons Energy per photon changes E = hf X-Rays, UV, Gamma big = red Amplitude Changes Brightness small = dim big = bright # of photons changes many = bright few = dim CCD Devices, High speed film

Einstein • Proposes Photon theory • Experiment: Light ejects electrons Ammeter detects • Some

Einstein • Proposes Photon theory • Experiment: Light ejects electrons Ammeter detects • Some Potential V stops all electrons • This is called the “Stopping potential” • (Pretty tough, huh? ) - V + Reverse the voltage TOC

- Electric Force + Consider an ejected electron hurtling toward the negative plate: Remember

- Electric Force + Consider an ejected electron hurtling toward the negative plate: Remember V = W/q, so W = Vq Definition of electron volt Ekin turns to potential energy If 5. 12 V is the stopping potential, then Ekin = 5. 12 e. V

Einstein’s Photon theory predicts: Photon energy = Work function + Kinetic energy of electron

Einstein’s Photon theory predicts: Photon energy = Work function + Kinetic energy of electron hf = + Ekmax hf = hfo + e. Vs - Work function (Depends on material) fo - Lowest frequency that ejects e - Electron charge Vs - The uh stopping potential - V + TOC

Metal Work Function Ag (silver) Au (gold) Cs (cesium) Cu (copper) Li (lithium) Pb

Metal Work Function Ag (silver) Au (gold) Cs (cesium) Cu (copper) Li (lithium) Pb (lead) Sn (tin) Chromium Nickel 4. 26 5. 1 2. 14 4. 65 2. 9 4. 25 4. 42 4. 6

Photon energy = Work function + Kinetic energy of electron hf = + Ekmax

Photon energy = Work function + Kinetic energy of electron hf = + Ekmax hf = hfo + e. Vs - Work function e = 1. 602 x 10 -19 C fo - Lowest frequency that ejects V = W/q e - Electron charge E = hf = hc/ Vs - The uh stopping potential Example 1: A certain metal has a work function of 3. 25 e. V. When light of an unknown wavelength strikes it, the electrons have a stopping potential of 7. 35 V. What is the wavelength of the light? TOC

Photon energy = Work function + Kinetic energy of electron hf = + Ekmax

Photon energy = Work function + Kinetic energy of electron hf = + Ekmax hf = hfo + e. Vs - Work function e = 1. 602 x 10 -19 C fo - Lowest frequency that ejects V = W/q e - Electron charge E = hf = hc/ Vs - The uh stopping potential Example 2: 70. 9 nm light strikes a metal with a work function of 5. 10 e. V. What is the maximum kinetic energy of the ejected photons in e. V? What is the stopping potential? TOC

Whiteboards: Photoelectric effect 1|2|3|4 TOC

Whiteboards: Photoelectric effect 1|2|3|4 TOC

Photons of a certain energy strike a metal with a work function of 2.

Photons of a certain energy strike a metal with a work function of 2. 15 e. V. The ejected electrons have a kinetic energy of 3. 85 e. V. (A stopping potential of 3. 85 V) What is the energy of the incoming photons in e. V? Photon energy = Work function + Kinetic energy of electron Photon energy = 2. 15 e. V + 3. 85 e. V = 6. 00 e. V W

Another metal has a work function of 3. 46 e. V. What is the

Another metal has a work function of 3. 46 e. V. What is the wavelength of light that ejects electrons with a stopping potential of 5. 00 V? (2) E = hf = hc/ , Photon energy = Work function + Kinetic energy of electron Photon energy = 3. 46 e. V + 5. 00 e. V = 8. 46 e. V E = (8. 46 e. V)(1. 602 x 10 -19 J/e. V) = 1. 3553 x 10 -18 J E = hf = hc/ , = hc/E = (6. 626 x 10 -34 Js)(3. 00 x 108 m/s)/(1. 3553 x 10 -18 J) = 1. 4667 x 10 -07 m = 147 nm W

112 nm light strikes a metal with a work function of 4. 41 e.

112 nm light strikes a metal with a work function of 4. 41 e. V. What is the stopping potential of the ejected electrons? (2) E = hf = hc/ , 1 e. V = 1. 602 x 10 -19 J Photon energy = Work function + Kinetic energy of electron E = hf = hc/ = (6. 626 x 10 -34 Js)(3. 00 x 108 m/s)/(112 x 10 -9 m) E = 1. 7748 x 10 -18 J E = (1. 7748 x 10 -18 J)/(1. 602 x 10 -19 J/e. V) = 11. 079 e. V Photon energy = Work function + Kinetic energy of electron 11. 079 e. V = 4. 41 e. V + e. Vs 11. 079 e. V - 4. 41 e. V = 6. 6688 e. V = e. Vs Vs = 6. 67 V W

256 nm light strikes a metal and the ejected electrons have a stopping potential

256 nm light strikes a metal and the ejected electrons have a stopping potential of 1. 15 V. What is the work function of the metal in e. V? (2) E = hf = hc/ , 1 e. V = 1. 602 x 10 -19 J Photon energy = Work function + Kinetic energy of electron E = hf = hc/ = (6. 626 x 10 -34 Js)(3. 00 x 108 m/s)/(256 x 10 -9 m) E = 7. 7648 x 10 -19 J E = (7. 7648 x 10 -19 J)/(1. 602 x 10 -19 J/e. V) = 4. 847 e. V Photon energy = Work function + Kinetic energy of electron 4. 847 e. V = Work function + 1. 15 e. V 11. 079 e. V - 1. 15 e. V = 3. 70 e. V W

Einstein’s Photon theory predicts: Photon energy = work function + Kinetic energy of electron

Einstein’s Photon theory predicts: Photon energy = work function + Kinetic energy of electron hf = + Ekmax = hf - Photon Theory predicts: • Ekmax rises with frequency • Intensity of light ejects more Wave Theory predicts: • Ekmax rises with Amplitude (Intensity) • Frequency should not matter Survey says Millikan does the experiment 1915 conclusion 1930 conclusion TOC