The Laws of SINES and COSINES The Law
- Slides: 26
The Laws of SINES and COSINES
The Law of SINES For any triangle (right, acute or obtuse), you may use the following formula to solve for missing sides or angles:
Use Law of SINES when given. . . AAS l ASA l SSA (the ambiguous case) l
Example 1 You are given a triangle, ABC, with angle A = 70°, angle B = 80° and side a = 12 cm. Find the measures of angle C and sides b and c. * In this section, angles are named with capital letters and the side opposite an angle is named with the same lower case letter. *
Example 1 (con’t) B The angles in a ∆ total 180°, so angle C = 30°. 80° a = 12 c A 70° b Set up the Law of Sines to find side b: C
Example 1 (con’t) B 80° c A 70° Set up the Law of Sines to find side c: a = 12 b = 12. 6 30° C
B Angle C = 30° 80° Side b = 12. 6 cm a = 12 Side c = 6. 4 cm c= 6. 4 Example 1 (solution) A 70° b = 12. 6 30° Note: C We used the given values of A and a in both calculations since your answer is more accurate if you do not use rounded values in calculations.
Example 2 You are given a triangle ABC, with angle C = 115°, angle B = 30° and side a = 30 cm. Find the measures of angle A and sides b and c.
Example 2 (con’t) To solve for the missing sides/angles, we must have an angle/side opposite pair to set up the first equation. B 30° c a = 30 115° C b We MUST find angle A because the only side given is side a. A The angles in a ∆ total 180°, so angle A = 35°.
Example 2 (con’t) Set up the Law of Sines to find side b: B 30° c a = 30 115° 35° C b A
Example 2 (con’t) Set up the Law of Sines to find side c: B 30° c a = 30 115° 35° C b = 26. 2 A
Example 2 (solution) B Angle A = 35° 30° Side b = 26. 2 cm c = 47. 4 a = 30 115° 35° C b = 26. 2 A Side c = 47. 4 cm Note: Use the Law of Sines whenever you are given 2 angles and one side!
The Ambiguous Case (SSA) When given SSA (two sides and an angle that is NOT the included angle) , the situation is ambiguous. The dimensions may not form a triangle, or there may be 1 or 2 triangles with those dimensions. We first go through a series of tests to determine how many (if any) solutions exist.
The Ambiguous Case (SSA) In the following examples, the given angle will always be angle A and the given sides will be sides a and b. If you are given a different set of variables, feel free to change them to simulate the steps provided here. C=? angle C is so we can’t draw side ‘a’ in the right position b A ‘a’ - we don’t know what c=? B?
The Ambiguous Case (SSA) Situation I: Angle A is obtuse If angle A is obtuse there are TWO possibilities. If a ≤ b, then a is too short to reach side c - a triangle with these dimensions is C = ? impossible. a b A C=? If a > b, then there is ONE triangle with these dimensions. a b c=? B? A c=? B?
The Ambiguous Case (SSA) Situation I: Angle A is obtuse - EXAMPLE Given a triangle with angle A = 120°, side a = 22 cm and side b = 15 cm, find the other dimensions. Since a > b, these dimensions are possible. C To find the missing dimensions, use the Law of Sines: a = 22 b = 15 A 120° c B
The Ambiguous Case (SSA) Situation I: Angle A is obtuse - EXAMPLE Angle C = 180° - 120° - 36. 2° = 23. 8° C Use Law of Sines to find side c: a = 22 b = 15 A 120° c B 36. 2° Solution: angle B = 36. 2°, angle C = 23. 8°, side c = 10. 3
The Ambiguous Case (SSA) Situation II: Angle A is acute If angle A is acute there are SEVERAL possibilities. C=? b A a c=? Side ‘a’ may or may not be long enough to reach side ‘c’. We calculate the height of the altitude from angle C to side c to compare it with side a. B?
The Ambiguous Case (SSA) Situation II: Angle A is acute First, use SOH-CAH-TOA to find h: C=? b a h A c=? B? Then, compare ‘h’ to sides a and b. . .
The Ambiguous Case (SSA) Situation II: Angle A is acute If a < h, then NO triangle exists with these dimensions. C=? a b h A c=? B?
The Ambiguous Case (SSA) Situation II: Angle A is acute If h < a < b, then TWO triangles exist with these dimensions. C b h A c C b a B If we open side ‘a’ to the outside of h, angle B is acute. A c a h B If we open side ‘a’ to the inside of h, angle B is obtuse.
The Ambiguous Case (SSA) Situation II: Angle A is acute If h < b < a, then ONE triangle exists with these dimensions. C b a h A c B Since side a is greater than side b, side a cannot open to the inside of h, it can only open to the outside, so there is only 1 triangle possible!
The Ambiguous Case (SSA) Situation II: Angle A is acute If h = a, then ONE triangle exists with these dimensions. C b A a=h c B If a = h, then angle B must be a right angle and there is only one possible triangle with these dimensions.
The Ambiguous Case (SSA) if angle A is obtuse if a < b no solution if a > b one solution if a < h no solution if angle A is acute find the height, h = b*sin. A if h < a < b 2 solutions one with angle B acute, one with angle B obtuse if a > b > h 1 solution If a = h 1 solution angle B is a right angle
The Law of COSINES
Use Law of COSINES when given. . . SAS l SSS (start with the l largest angle!)
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