The Gas Laws 1 Use the kineticmolecular theory

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The Gas Laws 1. Use the kinetic-molecular theory to explain the behavior of gases

The Gas Laws 1. Use the kinetic-molecular theory to explain the behavior of gases 2. State, apply, & calculate the 3 following gas laws: a. Boyle’s Law b. Charles’s Law c. Gay-Lussac’s Law

The Combined Gas Law & Avogadro’s Principle 1. State, apply, & calculate the combined

The Combined Gas Law & Avogadro’s Principle 1. State, apply, & calculate the combined gas law 2. Relate number of particles and volumes using Avogadro’s Principle

The Ideal Gas Law 1. State, apply, & calculate the ideal gas law 2.

The Ideal Gas Law 1. State, apply, & calculate the ideal gas law 2. State, apply, & calculate Dalton’s Law of Partial Pressure 3. State, apply, & calculate Graham’s Law of Effusion http: //www. chemistry. ohio-state. edu/betha/neal. Gas. Law/fr 2. 1. html

BR: Visit the following site! http: //www. mhhe. com/physsci/chemistry/animations/chang_7 e_esp/gam 2 s 2_6. swf

BR: Visit the following site! http: //www. mhhe. com/physsci/chemistry/animations/chang_7 e_esp/gam 2 s 2_6. swf

Science Connection • From barbecuing on a gas grill to taking a ride in

Science Connection • From barbecuing on a gas grill to taking a ride in a hot air balloon, many activities involve gases. • It is important to be able to predict what effect changes in pressure, temperature, volume, or amount will have on the properties and behavior of a gas. Gases expand, diffuse, exert pressure, and can be compressed because they are in a low density state consisting of tiny, constantly-moving particles.

Gases Chs. 12, 13 STP is standard temperature and pressure • Kinetic-molecular theory –

Gases Chs. 12, 13 STP is standard temperature and pressure • Kinetic-molecular theory – Explains the properties of gases – 5 assumptions/Characteristics of gases • • Gases are fluids Gases have low density Gases are highly compressible Gases completely fill a container and exert pressure equally in all directions • The temp of a gas determines the average KE of its particles – Recall from PSci KE = ½mv 2

The Kinetic-Molecular Theory Section 12 -1 • Kinetic-molecular theory explains the different properties of

The Kinetic-Molecular Theory Section 12 -1 • Kinetic-molecular theory explains the different properties of solids, liquids, and gases. • Atomic composition affects chemical properties. • Atomic composition also affects physical properties. • The kinetic-molecular theory describes the behavior of matter in terms of particles in motion.

The Kinetic-Molecular Theory (cont. ) Section 12 -1 • Gases consist of small particles

The Kinetic-Molecular Theory (cont. ) Section 12 -1 • Gases consist of small particles separated by empty space. • Gas particles are too far apart to experience significant attractive or repulsive forces.

The Kinetic-Molecular Theory (cont. ) • Section 12 -1 Gas particles are in constant

The Kinetic-Molecular Theory (cont. ) • Section 12 -1 Gas particles are in constant random motion. • An elastic collision is one in which no kinetic energy is lost.

The Kinetic-Molecular Theory (cont. ) Section 12 -1 • Kinetic energy of a particle

The Kinetic-Molecular Theory (cont. ) Section 12 -1 • Kinetic energy of a particle depends on mass and velocity. • Temperature is a measure of the average kinetic energy of the particles in a sample of matter.

A. The Kinetic-Molecular Theory 1. Gas particles do NOT attract or repel 2. Gas

A. The Kinetic-Molecular Theory 1. Gas particles do NOT attract or repel 2. Gas particles are small; virtually no volume 3. Gas particles are in constant, random motion 4. Kinetic energy is transferred during the elastic collisions 5. All gases have same average kinetic energy at given temp

Explaining the Behavior of Gases Section 12 -1 • Great amounts of space exist

Explaining the Behavior of Gases Section 12 -1 • Great amounts of space exist between gas particles. • Compression reduces the empty spaces between particles.

Explaining the Behavior of Gases (cont. ) Section 12 -1 • Gases easily flow

Explaining the Behavior of Gases (cont. ) Section 12 -1 • Gases easily flow past each other because there are no significant forces of attraction. • Diffusion is the movement of one material through another. • Effusion is a gas escaping through a tiny opening.

B. The Nature of Gases 1. Actual gases do not always obey the kinetic-molecular

B. The Nature of Gases 1. Actual gases do not always obey the kinetic-molecular theory 2. The KMT is based on 4 factors: a. Temperature (measured in Kelvin) [o. C + 273 = K] b. Pressure (measured in atm, k. Pa, etc. ) [1 atm = 101. 3 k. Pa = 760 mm. Hg or torr] c. Volume (measured in liters or m. L) d. Amount of Gas (measured in moles)

http: //www. chem. iastate. edu/group/Greenbowe/sections/projectfolder/flashfiles/gaslaw/boyles_law_graph. html C. Boyle’s Law 1. Temperature held CONSTANT 2.

http: //www. chem. iastate. edu/group/Greenbowe/sections/projectfolder/flashfiles/gaslaw/boyles_law_graph. html C. Boyle’s Law 1. Temperature held CONSTANT 2. Found inverse relationship between pressure & volume 3. P 1 V 1 = P 2 V 2

Volume –vs- Pressure of a Gas

Volume –vs- Pressure of a Gas

P 1 V 1 = P 2 V 2 Sample Problem 1: If the

P 1 V 1 = P 2 V 2 Sample Problem 1: If the pressure of helium gas in a balloon has a volume of 4. 0 L at 210 k. Pa, what will the pressure be at 2. 5 L? 336 k. Pa Complete Practice Problems: from next slide SHOW YOUR WORK!!!

Gas Law Calculations: Boyle’s Law • A sample of oxygen gas occupies a volume

Gas Law Calculations: Boyle’s Law • A sample of oxygen gas occupies a volume of 250 m. L at 740 torr pressure. What volume will it occupy at 800 torr pressure? 231 m. L • A sample of carbon dioxide occupies a volume of 3. 50 liters at 125 k. Pa pressure. What pressure would the gas exert if the volume was decreased to 2. 00 liters? 219 k. Pa P 1 x V 1 = P 2 x V 2

http: //www. chem. iastate. edu/group/Greenbowe/sections/projectfolder/flashfiles/gaslaw/charles_law. html http: //www. marymount. k 12. ny. us/marynet/06 stwbwrk/06

http: //www. chem. iastate. edu/group/Greenbowe/sections/projectfolder/flashfiles/gaslaw/charles_law. html http: //www. marymount. k 12. ny. us/marynet/06 stwbwrk/06 gas/2 slyscharles/2 slysflash. html D. Charles’s Law 1. Pressure held CONSTANT 2. Found direct relationship between temperature & volume 3. V 1 = V 2 T 1 T 2 http: //www. chem. iastate. edu/group/Greenbowe/sections/projectfolder/flashfiles/gaslaw/charles_law. html

Temperature –vs- Volume of a Gas

Temperature –vs- Volume of a Gas

V 1 = V 2 T 1 T 2 Sample Problem 2: A gas

V 1 = V 2 T 1 T 2 Sample Problem 2: A gas sample at 40 o. C occupies a volume of 2. 32 L. If the temperature is increased to 75 o. C, what will be the final volume? 4. 35 L Complete Practice Problems: from next slide SHOW YOUR WORK!!!

Gas Law Calculations: Charles’ Law • A sample of nitrogen occupies a volume of

Gas Law Calculations: Charles’ Law • A sample of nitrogen occupies a volume of 250 m. L at 25 C. What volume will it occupy at 95 C? 310 m. L using K; 950 m. L using C • Oxygen gas is at a temperature of 40 C when it occupies a volume of 2. 3 liters. To what temperature should it be raised to occupy a volume of 6. 5 liters? 113 C or 386 K V x. T =V x. T 1 2 2 1

http: //www. marymount. k 12. ny. us/marynet/06 stwbwrk/06 gas/1 amcslussac/amcsgaylussac. html E. Gay-Lussac’s Law

http: //www. marymount. k 12. ny. us/marynet/06 stwbwrk/06 gas/1 amcslussac/amcsgaylussac. html E. Gay-Lussac’s Law 1. Volume held CONSTANT 2. Found direct relationship between temperature & pressure 3. P 1 = P 2 T 1 T 2 What would a graph look like for Gay-Lussac’s Law?

P 1 T 1 = P 2 T 2 Sample Problem 3: The pressure

P 1 T 1 = P 2 T 2 Sample Problem 3: The pressure of a gas in a tank is 3. 2 atm at 22 o. C. If the temperature rises to 60 o. C, what will be the pressure in the tank? 8. 73 atm

A. The Combined Gas Law 1. Amount of Gas held CONSTANT 2. P 1

A. The Combined Gas Law 1. Amount of Gas held CONSTANT 2. P 1 V 1 = T 1 P 2 V 2 T 2 3. This law combines which 3 laws? http: //kids. earth. nasa. gov/archive/air_pressure/balloon. html

Sample Problem 4: A gas at 110 k. Pa and 30 o. C fills

Sample Problem 4: A gas at 110 k. Pa and 30 o. C fills a container at 2. 0 L. If the temperature rises to 80 o. C and the pressure increases to 440 k. Pa, what is the new volume? 1. 33 L P 1 V 1 = P 2 V 2 T 1 T 2

B. Avogadro’s Principle 1. Equal volumes of gases at the same temperature and pressure

B. Avogadro’s Principle 1. Equal volumes of gases at the same temperature and pressure contains equal number of particles 2. Molar volume = 22. 4 L/mol at STP 3. STP (Standard Temp & Pressure) Temperature = 0 o. C or 273 K Pressure = 1 atm

STP (Standard Temp & Pressure) Temperature = 0 o. C or 273 K Pressure

STP (Standard Temp & Pressure) Temperature = 0 o. C or 273 K Pressure = 1 atm Sample Problem 5: Calculate the volume that 0. 881 mol of a gas at STP will occupy. 19. 7 L

Real Versus Ideal Gases Section 13 -2 • Ideal gases follow the assumptions of

Real Versus Ideal Gases Section 13 -2 • Ideal gases follow the assumptions of the kinetic-molecular theory. • Ideal gases experience: – There are no intermolecular attractive or repulsive forces between particles or with their containers. – The particles are in constant random motion. – Collisions are perfectly elastic. – No gas is truly ideal, but most behave as ideal gases at a wide range of temperatures and pressures.

Real Versus Ideal Gases (cont. ) Section 13 -2 • Real gases deviate most

Real Versus Ideal Gases (cont. ) Section 13 -2 • Real gases deviate most from ideal gases at high pressures and low temperatures. • Polar molecules have larger attractive forces between particles. • Polar gases do not behave as ideal gases. • Large nonpolar gas particles occupy more space and deviate more from ideal gases.

A. The Ideal Gas Law 1. Contains ALL variables 2. P V = n

A. The Ideal Gas Law 1. Contains ALL variables 2. P V = n R T 3. Where P = pressure (depends on R) V = volume (liters) n = amount of gas (moles) R = ideal gas constant (depends on pressure) T = temperature (Kelvin)

The Ideal Gas Law—Molar Mass and Density Section 13 -2 • Density and the

The Ideal Gas Law—Molar Mass and Density Section 13 -2 • Density and the ideal gas law

R = ideal gas constant (depends on pressure) Pressure R value atm 0. 0821

R = ideal gas constant (depends on pressure) Pressure R value atm 0. 0821 k. Pa 8. 314 mm Hg torr 62. 4

STP (Standard Temp & Pressure) Temperature = 0 o. C or 273 K Pressure

STP (Standard Temp & Pressure) Temperature = 0 o. C or 273 K Pressure = 1 atm Sample Problem 6: Calculate the volume of a gas at STP with 2. 80 moles. 62. 8 L PV = n. RT Sample Problem 7: Calculate the moles of a gas at STP with a volume of 238 L. 10. 6 mol Pressure

Sample Problem 8: Calculate the number of moles of gas contained in a 3.

Sample Problem 8: Calculate the number of moles of gas contained in a 3. 0 L vessel at 27 o. C with a pressure of 1. 50 atm. PV = n. RT 2. 03 mol

B. Dalton’s Law of Partial Pressure 1. Contains only pressure 2. Where pressure must

B. Dalton’s Law of Partial Pressure 1. Contains only pressure 2. Where pressure must be in the same units 3. Ptotal = P 1 + P 2 + P 3 +. . .

Ptotal = P 1 + P 2 + P 3 +. . . 4.

Ptotal = P 1 + P 2 + P 3 +. . . 4. Sample Problem 9: If the total pressure of a mixture of oxygen & nitrogen gases was 820 mm. Hg, how much pressure would nitrogen exert if oxygen had 580 mm. Hg? 240 mm. Hg

2. Rate A = Mass B Sample Problem 8: Rate Mass A B If

2. Rate A = Mass B Sample Problem 8: Rate Mass A B If neon travels at 400. m/s, estimate the average speed of butane (C 4 H 10) at the same temperature. 235 m/s Sample Problem 9: Chlorine has a velocity of 0. 0380 m/s. What is the average velocity of sulfur dioxide under the same conditions? 0. 0400 m/s

Graham’s Law of Effusion Sheet 13 Remember to choose the smaller mass as A

Graham’s Law of Effusion Sheet 13 Remember to choose the smaller mass as A (or 1) and the heavier mass as B (or 2) 2. Rate A Rate B = Mass B Mass A Or Rate of Effusion = 1 ÷ √¯Molar Mass

Gas Stoichiometry • Calculations involving only volume – Use eqn mole ratios • Coefficient

Gas Stoichiometry • Calculations involving only volume – Use eqn mole ratios • Coefficient = moles = volumes called vol ratios Other conversion factors 1 mol = 22. 4 L @ STP 1 atm = 101, 325 Pa 1 torr = 133. 322 Pa = 1 mm Hg Any other conversion can be made after this!!! You Try Practice Problems

What Did I Learn Today? • Kinetic theory of gases (kinetic-molecular theory) and the

What Did I Learn Today? • Kinetic theory of gases (kinetic-molecular theory) and the Kelvin scale • Heating and cooling curve interpretation and construction • The behavior of gases • Characteristics of gases • PTV and the gas laws • The combined gas law – Avogadro’s principle • Ideal gas law – Dalton’s law of partial pressure – Graham’s law of effusion